How to pass 2D array (matrix) in a function in C?
CMultidimensional ArrayParameter PassingC Problem Overview
I need to do this to persist operations on the matrix as well. Does that mean that it needs to be passed by reference?
Will this suffice?
void operate_on_matrix(char matrix[][20]);
C Solutions
Solution 1 - C
C does not really have multi-dimensional arrays, but there are several ways to simulate them. The way to pass such arrays to a function depends on the way used to simulate the multiple dimensions:
-
Use an array of arrays. This can only be used if your array bounds are fully determined at compile time, or if your compiler supports VLA's:
#define ROWS 4 #define COLS 5
void func(int array[ROWS][COLS]) { int i, j;
for (i=0; i
void func_vla(int rows, int cols, int array[rows][cols]) { int i, j;
for (i=0; i
int main() { int x[ROWS][COLS];
func(x); func_vla(ROWS, COLS, x); }
-
Use a (dynamically allocated) array of pointers to (dynamically allocated) arrays. This is used mostly when the array bounds are not known until runtime.
void func(int** array, int rows, int cols) { int i, j;
for (i=0; i
int main() { int rows, cols, i; int **x;
/* obtain values for rows & cols */
/* allocate the array */ x = malloc(rows * sizeof *x); for (i=0; i
/* use the array */ func(x, rows, cols);
/* deallocate the array */ for (i=0; i
-
Use a 1-dimensional array and fixup the indices. This can be used with both statically allocated (fixed-size) and dynamically allocated arrays:
void func(int* array, int rows, int cols) { int i, j;
for (i=0; i
cols+j]=ij; } } } int main() { int rows, cols; int *x;
/* obtain values for rows & cols */
/* allocate the array */ x = malloc(rows * cols * sizeof *x);
/* use the array */ func(x, rows, cols);
/* deallocate the array */ free(x); }
-
Use a dynamically allocated VLA. One advantage of this over option 2 is that there is a single memory allocation; another is that less memory is needed because the array of pointers is not required.
#include
#include #include extern void func_vla(int rows, int cols, int array[rows][cols]); extern void get_rows_cols(int *rows, int *cols); extern void dump_array(const char *tag, int rows, int cols, int array[rows][cols]);
void func_vla(int rows, int cols, int array[rows][cols]) { for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { array[i][j] = (i + 1) * (j + 1); } } }
int main(void) { int rows, cols;
get_rows_cols(&rows, &cols); int (*array)[cols] = malloc(rows * cols * sizeof(array[0][0])); /* error check omitted */ func_vla(rows, cols, array); dump_array("After initialization", rows, cols, array); free(array); return 0;
}
void dump_array(const char *tag, int rows, int cols, int array[rows][cols]) { printf("%s (%dx%d):\n", tag, rows, cols); for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) printf("%4d", array[i][j]); putchar('\n'); } }
void get_rows_cols(int *rows, int *cols) { srand(time(0)); // Only acceptable because it is called once *rows = 5 + rand() % 10; *cols = 3 + rand() % 12; }
Solution 2 - C
Easiest Way in Passing A Variable-Length 2D Array
Most clean technique for both C & C++ is: pass 2D array like a 1D array, then use as 2D inside the function.
#include <stdio.h>
void func(int row, int col, int* matrix){
int i, j;
for(i=0; i<row; i++){
for(j=0; j<col; j++){
printf("%d ", *(matrix + i*col + j)); // or better: printf("%d ", *matrix++);
}
printf("\n");
}
}
int main(){
int matrix[2][3] = { {0, 1, 2}, {3, 4, 5} };
func(2, 3, matrix[0]);
return 0;
}
Internally, no matter how many dimensions an array has, C/C++ always maintains a 1D array. And so, we can pass any multi-dimensional array like this.
Solution 3 - C
I don't know what you mean by "data dont get lost". Here's how you pass a normal 2D array to a function:
void myfunc(int arr[M][N]) { // M is optional, but N is required
..
}
int main() {
int somearr[M][N];
...
myfunc(somearr);
...
}
Solution 4 - C
2D array:
int sum(int array[][COLS], int rows)
{
}
3D array:
int sum(int array[][B][C], int A)
{
}
4D array:
int sum(int array[][B][C][D], int A)
{
}
and nD array:
int sum(int ar[][B][C][D][E][F].....[N], int A)
{
}