How to make phone call in iOS 10 using Swift?

IosSwiftSwift3Ios10Phone Call

Ios Problem Overview


I want my app to be able to call a certain number when a button is clicked. I've tried to google it but there doesn't seem to have one for iOS 10 so far (where openURL is gone). Can someone put an example for me on how to do so? For instance like:

@IBAction func callPoliceButton(_ sender: UIButton) {
    // Call the local Police department
}

Ios Solutions


Solution 1 - Ios

You can call like this:

 if let url = URL(string: "tel://\(number)") {
     UIApplication.shared.openURL(url)
 }

For Swift 3+, you can use like

guard let number = URL(string: "tel://" + number) else { return }
UIApplication.shared.open(number)

OR

UIApplication.shared.open(number, options: [:], completionHandler: nil)

Make sure you've scrubbed your phone number string to remove any instances of (, ), -, or space.

Solution 2 - Ios

Task

Make a call with phone number validation

Details

Tested on:

  • Swift 5.2, Xcode 11.4 (11E146)

Solution

// MARK: DataDetector

class DataDetector {
    
    private class func _find(all type: NSTextCheckingResult.CheckingType,
                             in string: String, iterationClosure: (String) -> Bool) {
        guard let detector = try? NSDataDetector(types: type.rawValue) else { return }
        let range = NSRange(string.startIndex ..< string.endIndex, in: string)
        let matches = detector.matches(in: string, options: [], range: range)
        loop: for match in matches {
            for i in 0 ..< match.numberOfRanges {
                let nsrange = match.range(at: i)
                let startIndex = string.index(string.startIndex, offsetBy: nsrange.lowerBound)
                let endIndex = string.index(string.startIndex, offsetBy: nsrange.upperBound)
                let range = startIndex..<endIndex
                guard iterationClosure(String(string[range])) else { break loop }
            }
        }
    }
    
    class func find(all type: NSTextCheckingResult.CheckingType, in string: String) -> [String] {
        var results = [String]()
        _find(all: type, in: string) {
            results.append($0)
            return true
        }
        return results
    }
    
    class func first(type: NSTextCheckingResult.CheckingType, in string: String) -> String? {
        var result: String?
        _find(all: type, in: string) {
            result = $0
            return false
        }
        return result
    }
}

// MARK: PhoneNumber

struct PhoneNumber {
    private(set) var number: String
    init?(extractFrom string: String) {
        guard let phoneNumber = PhoneNumber.first(in: string) else { return nil }
        self = phoneNumber
    }
    
    private init (string: String) { self.number = string }
    
    func makeACall() {
        guard let url = URL(string: "tel://\(number.onlyDigits())"),
            UIApplication.shared.canOpenURL(url) else { return }
        if #available(iOS 10, *) {
            UIApplication.shared.open(url)
        } else {
            UIApplication.shared.openURL(url)
        }
    }
    
    static func extractAll(from string: String) -> [PhoneNumber] {
        DataDetector.find(all: .phoneNumber, in: string)
            .compactMap {  PhoneNumber(string: $0) }
    }
    
    static func first(in string: String) -> PhoneNumber? {
        guard let phoneNumberString = DataDetector.first(type: .phoneNumber, in: string) else { return nil }
        return PhoneNumber(string: phoneNumberString)
    }
}

extension PhoneNumber: CustomStringConvertible { var description: String { number } }

// MARK: String extension

extension String {
    
    // MARK: Get remove all characters exept numbers
    
    func onlyDigits() -> String {
        let filtredUnicodeScalars = unicodeScalars.filter { CharacterSet.decimalDigits.contains($0) }
        return String(String.UnicodeScalarView(filtredUnicodeScalars))
    }
    
    var detectedPhoneNumbers: [PhoneNumber] { PhoneNumber.extractAll(from: self) }
    var detectedFirstPhoneNumber: PhoneNumber? { PhoneNumber.first(in: self) }
}

Usage

PhoneNumber(extractFrom: "+1-(800)-123-4567")?.makeACall()

PhoneNumber.extractAll(from: "+1-(800)-123-4567 bla bla 1(617)111-22-33").last?.makeACall()

PhoneNumber.first(in: "+1-(800)-123-4567 bla bla 1(617)111-22-33")?.makeACall()

"+1-(800)-123-4567 bla bla 1(617)111-22-33".detectedPhoneNumbers[1].makeACall()
"+1-(800)-123-4567 bla bla 1(617)111-22-33".detectedFirstPhoneNumber?.makeACall()

Full sample

> do not forget to paste the solution code here

func test() {
    isPhone("blabla")
    isPhone("+1(222)333-44-55")
    isPhone("+42 555.123.4567")
    isPhone("+1-(800)-123-4567")
    isPhone("+7 555 1234567")
    isPhone("+7(926)1234567")
    isPhone("(926) 1234567")
    isPhone("+79261234567")
    isPhone("926 1234567")
    isPhone("9261234567")
    isPhone("1234567")
    isPhone("123-4567")
    isPhone("123-89-01")
    isPhone("495 1234567")
    isPhone("469 123 45 67")
    isPhone("8 (926) 1234567")
    isPhone("89261234567")
    isPhone("926.123.4567")
    isPhone("415-555-1234")
    isPhone("650-555-2345")
    isPhone("(416)555-3456")
    isPhone("202 555 4567")
    isPhone("4035555678")
    isPhone(" 1 416 555 9292")
    isPhone("1(617)111-22-33!")
    isPhone("+44 1838 300284")
    isPhone("+44 1838 300284, 1 416 555 9292")
    isPhone("+44 1838 3d0384, 1 416 555 9292!")
}

private func isPhone(_ string: String) {
    let phoneNumbers = PhoneNumber.extractAll(from: string)
    let result = !phoneNumbers.isEmpty
    print("\(result ? "✅" : "❌") \(string) | detected phones: \(phoneNumbers)")
}

Result

 blabla | detected phones: []
 +1(222)333-44-55 | detected phones: [+1(222)333-44-55]
 +42 555.123.4567 | detected phones: [555.123.4567]
 +1-(800)-123-4567 | detected phones: [+1-(800)-123-4567]
 +7 555 1234567 | detected phones: [+7 555 1234567]
 +7(926)1234567 | detected phones: [+7(926)1234567]
 (926) 1234567 | detected phones: [(926) 1234567]
 +79261234567 | detected phones: [+79261234567]
 926 1234567 | detected phones: [926 1234567]
 9261234567 | detected phones: [9261234567]
 1234567 | detected phones: [1234567]
 123-4567 | detected phones: [123-4567]
 123-89-01 | detected phones: [123-89-01]
 495 1234567 | detected phones: [495 1234567]
 469 123 45 67 | detected phones: [469 123 45 67]
 8 (926) 1234567 | detected phones: [8 (926) 1234567]
 89261234567 | detected phones: [89261234567]
 926.123.4567 | detected phones: [926.123.4567]
 415-555-1234 | detected phones: [415-555-1234]
 650-555-2345 | detected phones: [650-555-2345]
 (416)555-3456 | detected phones: [(416)555-3456]
 202 555 4567 | detected phones: [202 555 4567]
 4035555678 | detected phones: [4035555678]
  1 416 555 9292 | detected phones: [1 416 555 9292]
 1(617)111-22-33! | detected phones: [1(617)111-22-33]
 +44 1838 300284 | detected phones: [+44 1838 300284]
 +44 1838 300284, 1 416 555 9292 | detected phones: [+44 1838 300284, 1 416 555 9292]
 +44 1838 3d0384, 1 416 555 9292! | detected phones: [1 416 555 9292]

Solution 3 - Ios

In Swift 4.2

func dialNumber(number : String) {
        
 if let url = URL(string: "tel://\(number)"),
   UIApplication.shared.canOpenURL(url) {
      if #available(iOS 10, *) {
        UIApplication.shared.open(url, options: [:], completionHandler:nil)
       } else {
           UIApplication.shared.openURL(url)
       }
   } else {
            // add error message here 
   }
}

Call this like below

dialNumber(number: "+921111111222")

Hope this help.

Solution 4 - Ios

> Updated for Swift 3:

used below simple lines of code, if you want to make a phone call:

// function defination:

func makeAPhoneCall()  {
    let url: NSURL = URL(string: "TEL://1234567890")! as NSURL
    UIApplication.shared.open(url as URL, options: [:], completionHandler: nil)
}

// function call: [Used anywhere in your code]

self.makeAPhoneCall()

Note: Please run the app on a real device because it won't work on the simulator.

Solution 5 - Ios

By mistake my answer was misplaced, please checkout this one: You can use this:

guard let url = URL(string: "tel://\(yourNumber)") else {
return //be safe
}

if #available(iOS 10.0, *) {
UIApplication.shared.open(url)
} else {
UIApplication.shared.openURL(url)
}

> We need to check whether we're on iOS 10 or later As 'openURL' was deprecated in iOS 10.0

Solution 6 - Ios

if let phoneCallURL:URL = URL(string: "tel:\(strPhoneNumber)") {
        let application:UIApplication = UIApplication.shared
        if (application.canOpenURL(phoneCallURL)) {
            let alertController = UIAlertController(title: "MyApp", message: "Are you sure you want to call \n\(self.strPhoneNumber)?", preferredStyle: .alert)
            let yesPressed = UIAlertAction(title: "Yes", style: .default, handler: { (action) in
                application.openURL(phoneCallURL)
            })
            let noPressed = UIAlertAction(title: "No", style: .default, handler: { (action) in
                
            })
            alertController.addAction(yesPressed)
            alertController.addAction(noPressed)
            present(alertController, animated: true, completion: nil)
        }
    }

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser3175707View Question on Stackoverflow
Solution 1 - IosParth AdrojaView Answer on Stackoverflow
Solution 2 - IosVasily BodnarchukView Answer on Stackoverflow
Solution 3 - IosAbdul RehmanView Answer on Stackoverflow
Solution 4 - IosKiran JadhavView Answer on Stackoverflow
Solution 5 - IosAnjali jariwalaView Answer on Stackoverflow
Solution 6 - IosPratik PatelView Answer on Stackoverflow