How to list all months between two dates

PhpDateDatetime

Php Problem Overview


I'm trying to list all months between two dates.

For example; start date is: 2010-12-02 and last date is: 2012-05-06

I want to list something like this:

2010-12
2011-01
2011-02
2011-03
2011-04
.
.
.
2012-04
2012-05

This is what I have tried and it is not working at all:

	$year_min = 2010;
	$year_max = 2012;
	$month_min = 12;
	$month_max = 5;
	for($y=$year_min; $y<=$year_max; $y++)
	{
		for($m=$month_min; $m<=$month_max; $m++)
		{
			$period[] = $y.$m;
		}
	}

Php Solutions


Solution 1 - Php

PHP 5.3

$start    = new DateTime('2010-12-02');
$start->modify('first day of this month');
$end      = new DateTime('2012-05-06');
$end->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period   = new DatePeriod($start, $interval, $end);

foreach ($period as $dt) {
    echo $dt->format("Y-m") . "<br>\n";
}

See it in action

PHP 5.4 or newer

$start    = (new DateTime('2010-12-02'))->modify('first day of this month');
$end      = (new DateTime('2012-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period   = new DatePeriod($start, $interval, $end);

foreach ($period as $dt) {
    echo $dt->format("Y-m") . "<br>\n";
}

The part where we modify the start and end dates to the first of the month is important. If we didn't, and the current day higher then the last day in February (i.e. 28 in non-leap years, 29 in leap years) this would skip February.

Solution 2 - Php

You must make a difference between two months of the same year and two months of different years.

$year_min = substr($row['contractStart'], 0, 4);
$year_max = substr($row['contractEnd'], 0, 4);
$month_min = substr($row['contractStart'], 5, 2);
$month_min = substr($row['contractEnd'], 5, 2);
$period = array();
try {
  if ($year_min > $year_max)
    throw new Exception();
  else if ($year_min == $year_max)
    if ($month_min > $month_max)
      throw new Exception();
    for ($month = $month_min; $month <= $month_max; $month++) {
      $period[] = $month . '-' . $year;
    }
  else {
    for ($month = $month_min; $month <= 12; $month++) {
      $period[] = $month . '-' . $year_min;
    }
    for ($year = $year_min + 1; $year < $year_max; $year++) {
      for ($month = $month_min; $month <= $month_max; $month++) {
        $period[] = $month . '-' . $year;
      }
    }
    for ($month = 1; $month <= $month_max; $month++) {
      $period[] = $month . '-' . $year_max;
    }
  }
  implode("<br />\r\n", $period);
}
catch (Exception $e) {
  echo 'Start date occurs after end date.'
}

That's for the hard way. Now there is a quick and easy way that is already given as an answer which I recommend you to choose.

Solution 3 - Php

function getMonthsInRange($startDate, $endDate)
{
    $months = array();

    while (strtotime($startDate) <= strtotime($endDate)) {
        $months[] = array(
            'year' => date('Y', strtotime($startDate)),
            'month' => date('m', strtotime($startDate)),
        );

        // Set date to 1 so that new month is returned as the month changes.
        $startDate = date('01 M Y', strtotime($startDate . '+ 1 month'));
    }

    return $months;
}

Solution 4 - Php

This was my solution since DateTime is not available in my server environment.

$a = "2007-01-01";
$b = "2008-02-15";

$i = date("Ym", strtotime($a));
while($i <= date("Ym", strtotime($b))){
    echo $i."\n";
    if(substr($i, 4, 2) == "12")
        $i = (date("Y", strtotime($i."01")) + 1)."01";
    else
        $i++;
}

Try it out: http://3v4l.org/BZOmb

Solution 5 - Php

In Laravel,

$period = \Carbon\CarbonPeriod::create('2017-06-28', '1 month', '2019-06-01');

foreach ($period as $dt) {
     echo $dt->format("Y-m") . "<br>\n";
}

Solution 6 - Php

October 2021 Update
If you have dates selected by the user, here's a solution

$from = date('Y-m-d', strtotime($_POST['from']));
$to = date('Y-m-d', strtotime($_POST['to']));

$counter = 1;
$max_date = strtotime($to);
$current_date = strtotime($from);
$dates = [];
$months = [];
$loop = true;
while($loop) {
    if(strtotime(date('Y-m-d',$current_date)." +".$counter."days") >= $max_date) $loop = false;
    else {
        $current_date = strtotime(date('Y-m-d', $current_date)." +".$counter."days");
        $date = date('Y-m-d', $current_date);
        $dates[] = $date;
        $months[] = date('Y-m', $current_date);
        $counter++;
    }
}
$months = array_unique($months);
echo '<pre>';
print_r($dates);
echo '<br>';
print_r($months);
echo '</pre>';

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionPooyaView Question on Stackoverflow
Solution 1 - PhpJohn CondeView Answer on Stackoverflow
Solution 2 - PhpSteeveDrozView Answer on Stackoverflow
Solution 3 - PhpsulaymanView Answer on Stackoverflow
Solution 4 - PhpCptAJView Answer on Stackoverflow
Solution 5 - PhpChandan SharmaView Answer on Stackoverflow
Solution 6 - PhpPeterView Answer on Stackoverflow