How to insert values into VB.NET Dictionary on instantiation?

vb.netDictionaryC# to-vb.net

vb.net Problem Overview


Is there a way that I can insert values into a VB.NET Dictionary when I create it? I can, but don't want to, do dict.Add(int, "string") for each item.

Basically, I want to do "How to insert values into C# Dictionary on instantiation?" with VB.NET.

var dictionary = new Dictionary<int, string>
    {
        {0, "string"},
        {1, "string2"},
        {2, "string3"}
    };

vb.net Solutions


Solution 1 - vb.net

If using Visual Studio 2010 or later you should use the FROM keyword like this:

Dim days = New Dictionary(Of Integer, String) From {{0, "string"}, {1, "string2"}}

See: http://msdn.microsoft.com/en-us/library/dd293617(VS.100).aspx

If you need to use a prior version of Visual Studio and you need to do this frequently you could just inherit from the Dictionary class and implement it yourself.

It might look something like this:

Public Class InitializableDictionary
    Inherits Dictionary(Of Int32, String)

    Public Sub New(ByVal args() As KeyValuePair(Of Int32, String))
        MyBase.New()
        For Each kvp As KeyValuePair(Of Int32, String) In args
            Me.Add(kvp.Key, kvp.Value)
        Next
    End Sub

End Class

Solution 2 - vb.net

This is not possible versions of Visual Basic prior to 2010.

In VB2010 and later, you can use the FROM keyword.

Dim days = New Dictionary(Of Integer, String) From {{0, "Sunday"}, {1, "Monday"}}

Reference

http://msdn.microsoft.com/en-us/library/dd293617(VS.100).aspx

Solution 3 - vb.net

What you're looking at is a feature of C# called "collection initializers". The feature existed for VB as well, but was cut prior to the release of Visual Studio 2008. It doesn't help you right now, but this is expected to be available in Visual Studio 2010. In the meantime, you'll have to do it the old fashioned way — call the .Add() method of your new instance.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestiononsaitoView Question on Stackoverflow
Solution 1 - vb.netbrendanView Answer on Stackoverflow
Solution 2 - vb.netStefanView Answer on Stackoverflow
Solution 3 - vb.netJoel CoehoornView Answer on Stackoverflow