Here are two ways:

 - escape the `/` which is the default substitute separator: `:s/usrbin/\/usr\/bin`
 - use another substitute separator, e.g., using the hash `#` character: `:s#usrbin#/usr/bin`. Note that there are characters that you can&#39;t use as a separator: `&quot;`, `\`, `|`

You can review this in the help subsystem using `:h pattern-delimiter`

I&#39;m trying to redirect to another route using:

    $location.path(&quot;/route&quot;);

But for some reason it is not working. I did an auto-complete widget using jQuery-UI and I&#39;m calling a function from the scope once the user selects an option. I debugged it and it enters the function but it is never redirected to the other route. It only changes the route when I press a key.

I think it is kind of strange but I haven&#39;t figured out how to solve this. I used

    window.location = &quot;#/route&quot;;

and it works but I want to use the `path()` function.

Does anybody have any idea why this is happening?

Redirect using AngularJS

I use &lt;a href=&quot;http://fortawesome.github.com/Font-Awesome/&quot;&gt;font-awesome&lt;/a&gt; and display their fonts like that:

    &lt;i class=&quot;icon-lock&quot;&gt;&lt;/i&gt;

This will display a nice little lock symbol. For the user to know what exactly that means, I tried adding attributes such as title and alt, but to no avail.

Is there any attribute I can use for the `&lt;i&gt;` tag that executes the same task as alt for images and title for links?

Alt or title attribute for i tag

I have a file that contains the string `usrbin`. I want to search for `usrbin` and replace it with `/usr/bin/`.

I tried `:%s/usrbin/usr/bin/g`, but it&#39;s showing error `E488: Trailing characters`.

How do I include a forward slash in a search and replace?

How to include forward slash in vi search &amp; replace

I have a file that contains the string <code>usrbin</code>. I want to search for <code>usrbin</code> and replace it with <code>/usr/bin/</code>.
I tried <code>:%s/usrbin/usr/bin/g</code>, but it's showing error <code>E488: Trailing characters</code>.
How do I include a forward slash in a search and replace?

I&#39;d like to search for text in all files currently open in vim and display all results in a single place. There are two problems, I guess:

 - I can&#39;t pass the list of open files to `:grep`/`:vim`, especially the names of files that aren&#39;t on the disk;
 - The result of `:grep -C 1 text` doesn&#39;t look good in the quickfix window.

Here is a nice example of multiple file search in Sublime Text 2:![enter image description here][1]

Any ideas?

  [1]: http://i.stack.imgur.com/mCi09.png

How do I search the open buffers in Vim?

I use `reverse-i-search` often, and that&#39;s cool. Sometime though when pressing &lt;kbd&gt;CTRL&lt;/kbd&gt;+&lt;kbd&gt;r&lt;/kbd&gt; multiple times, I *pass* the command I am actually looking for. Because &lt;kbd&gt;CTRL&lt;/kbd&gt;+&lt;kbd&gt;r&lt;/kbd&gt; searches backward in history, from newest to oldest, I have to:

 1. cancel,
 2. search again and
 3. stop exactly at the command, without passing it.

While in `reverse-i-search` prompt, is it possible to search forward, i.e. from where I stand to newest. I naively tried &lt;kbd&gt;CTRL&lt;/kbd&gt;+&lt;kbd&gt;Shift&lt;/kbd&gt;+&lt;kbd&gt;r&lt;/kbd&gt;, no luck. I heard about &lt;kbd&gt;CTRL&lt;/kbd&gt;+&lt;kbd&gt;g&lt;/kbd&gt; but this is not what I am expecting here. Anyone has an idea?

How to reverse-i-search back and forth?

I have a log file (application.log) which might contain the following string of normal &amp; special characters on multiple lines:

    *^%Q&amp;$*&amp;^@$&amp;*!^@$*&amp;^&amp;^*&amp;^&amp;

I want to search for the line number(s) which contains this special character string.

&lt;!-- language: sh --&gt;

    grep &#39;*^%Q&amp;$*&amp;^@$&amp;*!^@$*&amp;^&amp;^*&amp;^&amp;&#39; application.log

The above command doesn&#39;t return any results.

What would be the correct syntax to get the line numbers?

grep for special characters in Unix

Need to find a way in ElasticSearch to boost the relevance of a document based on a particular value of a field.  Specifically, there is a special field in all my documents where the higher the field value is, the more relevant the doc that contains it should be, regardless of the search.

Consider the following document structure:

    {
        &quot;_all&quot; : {&quot;enabled&quot; : &quot;true&quot;},
        &quot;properties&quot; : {
            &quot;_id&quot;:            {&quot;type&quot; : &quot;string&quot;,  &quot;store&quot; : &quot;yes&quot;, &quot;index&quot; : &quot;not_analyzed&quot;},
            &quot;first_name&quot;:     {&quot;type&quot; : &quot;string&quot;,  &quot;store&quot; : &quot;yes&quot;, &quot;index&quot; : &quot;yes&quot;},
            &quot;last_name&quot;:      {&quot;type&quot; : &quot;string&quot;,  &quot;store&quot; : &quot;yes&quot;, &quot;index&quot; : &quot;yes&quot;},
            &quot;boosting_field&quot;: {&quot;type&quot; : &quot;integer&quot;, &quot;store&quot; : &quot;yes&quot;, &quot;index&quot; : &quot;yes&quot;}
            }
    }


I&#39;d like documents with a higher boosting_field value to be __inherently more relevant__ than those with a lower boosting_field value.  This is just a starting point -- the matching between the query and the other fields will also be taken into account in determining the final relevance score of each doc in the search.  But, __all else being equal, the higher the boosting field, the more relevant the document__.  

Anyone have an idea on how to do this?

Thanks a lot!



ElasticSearch -- boosting relevance based on field value

I have a ArrayList with custom objects. I want to search inside this ArrayList for Strings.

The class for the objects look like this:

    public class Datapoint implements Serializable {
      
      private String stateBased;
      private String name;
      private String priority;
      private String mainNumber;
      private String groupadress;
      private String dptID;
    
      public Datapoint(){
      }
    
      public String getMainNumber() {
        return mainNumber;
      }
    
      public void setMainNumber(String mainNumber) {
        this.mainNumber = mainNumber;
      }
    
      public String getName() {
        return name;
      }
       
      ..and so on

I know how to search for a string in a ArrayList&lt;String&gt; but how to do that in a ArrayList with my custom objects:

    ArrayList&lt;String&gt; searchList = new ArrayList&lt;String&gt;();
    String search = &quot;a&quot;;
    int searchListLength = searchList.size();
    for (int i = 0; i &lt; searchListLength; i++) {
    if (searchList.get(i).contains(search)) {
    //Do whatever you want here
    }
    }


So I want to have a function to search in my ArrayList with for example five objects for all &quot;name&quot; strings. 


Searching in a ArrayList with custom objects for certain strings

I&#39;m stuck and cannot escape. It says:

    &quot;type :quit&lt;Enter&gt; to quit VIM&quot;

But when I type that it simply appears in the object body.


How do I exit the Vim editor?

I usually use 
&lt;kbd&gt;d&lt;/kbd&gt;&lt;kbd&gt;^&lt;/kbd&gt; to delete to the beginning of line.

But if the line starts with space or tabulations, the deletion does not go all the way to start of line.

Example: 
&gt;&amp;nbsp;&amp;nbsp;foo foo

The line starts with two spaces, and the cursor is between the two &quot;foo&quot;

&lt;kbd&gt;d&lt;/kbd&gt;&lt;kbd&gt;^&lt;/kbd&gt; deletes the first foo, but not the two spaces before it.

It is obviously useful most of the time, but what if I do want to delete everything?


Deleting to the beginning of line when line starts with whitespace characters

How can I delete a line without putting it into my default buffer?

Example:

    line that will be copied.

    line that I want to be substitued with the previous one.

What I&#39;m trying to do:

    yy
    dd
    p

But Vim replaces the recent copied string with the deleted (cutted) one. I know that I can use buffers like, `&quot;1yy`, `dd` then `&quot;1p`, but I always forget to put the copied string in a buffer then I need to paste my contents first (line that will be copied) and then delete what I want (line that I want to be substituted with the previous one.)

How can I really delete a text in Vi(m) without copying it?

Another related question is how I can forward delete a word in insert mode? I want something similar to &lt;kbd&gt;Ctrl&lt;/kbd&gt;+&lt;kbd&gt;w&lt;/kbd&gt;.

How to delete (not cut) in Vim?

Is there a way to profile Vim plugins?

My MacVim becomes slower and slower when I open a large `.py`. I know I could deselect all plugins and reselect one by one to check which plugin is the culprit, but is there a faster way?

My dotvim is here: https://github.com/charlax/dotvim

How to see which plugins are making Vim slow?

I would like to remove specific characters from strings within a vector, similar to the *Find and Replace* feature in Excel. 

Here are the data I start with:

    group &lt;- data.frame(c(&quot;12357e&quot;, &quot;12575e&quot;, &quot;197e18&quot;, &quot;e18947&quot;)

I start with just the first column; I want to produce the second column by removing the `e`&#39;s:

    group     	group.no.e
    12357e		12357
    12575e		12575
    197e18		19718
    e18947		18947



Replace specific characters within strings

My code uses `String.Replace` several times in a row:

    mystring = mystring.Replace(&quot;somestring&quot;, variable1);
    mystring = mystring.Replace(&quot;somestring2&quot;, variable2);
    mystring = mystring.Replace(&quot;somestring3&quot;, variable1);

I suspect there&#39;s a better and faster way to do it. What would you suggest?

Alternative to multiple String.Replaces

Relative newcomer to Javascript and looking for a way to remove the last character of a string if it is a colon.

I know `myString = myString.replace(&#39;/^\\:/&#39;);` will work for the start of the line but not sure how to swap in the `$` character to change to the end of a line… can anybody correct it?

Thanks


Javascript: Remove last character if a colon

I have a string that is built out of three parts. The word I want the string to be (changes), a seperating part (doesn&#39;t change) and the last part which changes. I want to delete the seperating part and the ending part. The seperating part is &quot; - &quot; so what I&#39;m wondering is if theres a way to delete everything after a certaint part of the string.

An example of this scenario would be if I wanted to turn this: &quot;Stack Overflow - A place to ask stuff&quot; into this: &quot;Stack Overflow&quot;. Any help is appreciated!

Delete everything after part of a string

I have a file containing a certain number of lines. Each line looks like this:

&lt;!-- language: none --&gt;

    TF_list_to_test10004/Nus_k0.345_t0.1_e0.1.adj:PKMYT1

I would like to remove all before &quot;:&quot; character in order  to retain only PKMYT1 that is a gene name. 
Since I&#39;m not an expert in regex scripting can anyone help me to do this using Unix (sed or awk) or in R?

Remove all text before colon

In normal text editors [with all due respect to Vim] there is a shortcut &lt;kbd&gt;Ctrl&lt;/kbd&gt;+&lt;kbd&gt;Z&lt;/kbd&gt; when you have done something nasty and want to return to the previous version of the text. Like BACK button in Word. I wonder how can you achieve this behaviour in Vim.

How to go back (ctrl+z) in vi/vim

In vi/vim editor, I need to copy a block. There are many ways, but one way is very quick.

1. label the first line by some way,

2. then label the end line by some way,

3. then put some command to copy the labeled lines.

4. then copy, may using &#39;p&#39;, but not sure.

Anybody know the commands (not yy or 10yy)? Thanks in advance. 

vi/vim editor, copy a block (not usual action)

How can we use vim to delete characters from the beginning of the line till the cursor.
Say, we have a string &quot;hello world&quot; while the cursor is on &quot;w&quot;. How can we delete from &quot;h&quot; till &quot;w&quot;.

vi to delete from the beginning of the line till the cursor

When reading a long file by vi editor, it would be very nice to get back to the beginning of the file by some short cuts when you really need to do so. Even &lt;kbd&gt;ctrl&lt;/kbd&gt;+&lt;kbd&gt;B&lt;/kbd&gt; sometimes is too slow. Does anyone know such a tool?

Content Type	Original Author	Original Content on Stackoverflow
Question	user1578447	View Question on Stackoverflow
Solution 1 - Search	pb2q	View Answer on Stackoverflow

How to include forward slash in vi search & replace

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Solution 1 - Search

Alt or title attribute for i tag

Redirect using AngularJS

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