How to hide ticks label in python but keep the ticks in place?
PythonMatplotlibAxisLabelsPython Problem Overview
I want to hide my ticks label on a plot I created, but keep this tick itself (the little marks on the axis). When I try to use what I've found here, for example, the entire tick is removed, and not just the labels. How can I remove only the labels then?
Python Solutions
Solution 1 - Python
Here is a slightly simpler answer, using ax.tick_params
import matplotlib.pylab as plt
fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])
ax.tick_params(labelbottom=False)
plt.show()
Here is the resulting output in Matplotlib 3
As commented by @chris, one can similarly hide the labels on any of the other axes using labeltop, labelleft, labelright, in the above example, instead of labelbottom.
Solution 2 - Python
Set the tick labels not to be an empty array, but to be a list of empty strings. In the example below, I've replaced the xtick labels with empty strings, leaving the y axis untouched. From here you can selectively keep certain labels if you wished.
import pylab as plt
fig, ax = plt.subplots()
ax.plot([1,2,3],[4,5,6])
labels = [item.get_text() for item in ax.get_xticklabels()]
empty_string_labels = ['']*len(labels)
ax.set_xticklabels(empty_string_labels)
plt.show()
This code is adapted from a previous answer.
Solution 3 - Python
I didn't find divenex's answer to work for me. This answer creates ticks without triggering any automatic labeling, hence no requirement to use "labelbottom= False":
if the bottom and left ticks already exist:
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])
ax.tick_params(right= True,top= True)
if no ticks already exist:
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])
ax.tick_params(right= True,top= True,left= True, bottom= True)
Solution 4 - Python
import matplotlib.pylab as plt
fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])
ax.set_xticklabels([])
plt.show()