How to get URL of current page in PHP

In PHP, how can I get the URL of the current page? Preferably just the parts after http://domain.com.

$_SERVER['REQUEST_URI']

For more details on what info is available in the $_SERVER array, see the PHP manual page for it.

If you also need the query string (the bit after the ? in a URL), that part is in this variable:

$_SERVER['QUERY_STRING']

if you want just the parts of url after http://domain.com, try this:

<?php echo $_SERVER['REQUEST_URI']; ?>

> if the current url was http://domain.com/some-slug/some-id, echo will return only '/some-slug/some-id'.

if you want the full url, try this:

<?php echo 'http://' . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI']; ?>

 $uri = $_SERVER['REQUEST_URI'];

This will give you the requested directory and file name. If you use mod_rewrite, this is extremely useful because it tells you what page the user was looking at.

If you need the actual file name, you might want to try either $_SERVER['PHP_SELF'], the magic constant __FILE__, or $_SERVER['SCRIPT_FILENAME']. The latter 2 give you the complete path (from the root of the server), rather than just the root of your website. They are useful for includes and such.

$_SERVER['PHP_SELF'] gives you the file name relative to the root of the website.

 $relative_path = $_SERVER['PHP_SELF'];
 $complete_path = __FILE__;
 $complete_path = $_SERVER['SCRIPT_FILENAME'];

The other answers are correct. However, a quick note: if you're looking to grab the stuff after the ? in a URI, you should use the $_GET[] array.

You can use $_SERVER['HTTP_REFERER'] this will give you whole URL for example:

suppose you want to get url of site name www.example.com then $_SERVER['HTTP_REFERER'] will give you https://www.example.com