How to get unique device id in flutter?

Flutter Problem Overview

In Android we have, Settings.Secure.ANDROID_ID. I do not know the iOS equivalent. Is there a flutter plugin or a way to get a unique device id for both Android and IOS in flutter?

Flutter Solutions

Solution 1 - Flutter

Null safe code

Use device_info_plus plugin developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
  device_info_plus: ^3.2.3

Create a method:

Future<String?> _getId() async {
  var deviceInfo = DeviceInfoPlugin();
  if (Platform.isIOS) { // import 'dart:io'
    var iosDeviceInfo = await deviceInfo.iosInfo;
    return iosDeviceInfo.identifierForVendor; // unique ID on iOS
  } else if(Platform.isAndroid) {
    var androidDeviceInfo = await deviceInfo.androidInfo;
    return androidDeviceInfo.androidId; // unique ID on Android
  }
}

Usage:

String? deviceId = await _getId();

Solution 2 - Flutter

There is a plugin called device_info. You can get it here.

Check the official example here

 static Future<List<String>> getDeviceDetails() async {
    String deviceName;
    String deviceVersion;
    String identifier;
    final DeviceInfoPlugin deviceInfoPlugin = new DeviceInfoPlugin();
    try {
      if (Platform.isAndroid) {
        var build = await deviceInfoPlugin.androidInfo;
        deviceName = build.model;
        deviceVersion = build.version.toString();
        identifier = build.androidId;  //UUID for Android
      } else if (Platform.isIOS) {
        var data = await deviceInfoPlugin.iosInfo;
        deviceName = data.name;
        deviceVersion = data.systemVersion;
        identifier = data.identifierForVendor;  //UUID for iOS
      }
    } on PlatformException {
      print('Failed to get platform version');
    }

//if (!mounted) return;
return [deviceName, deviceVersion, identifier];
}

You can store this UUID in the Keychain. This way you can set an unique ID for your device.

Solution 3 - Flutter

I just published a plugin to provide a solution to your problem. It uses Settings.Secure.ANDROID_ID for Android and relies on identifierForVendor and the keychain for iOS to make the behaviour equivalent to Android's. Here's the link.

Solution 4 - Flutter

Update 1/3/2021: The recommended way is now the extended community plugin called device_info_plus. It supports more platforms than device_info and aims to support all that are supported by flutter. Here is an example usage:

import 'package:flutter/foundation.dart' show kIsWeb;
import 'package:device_info_plus/device_info_plus.dart';
import 'dart:io';

Future<String> getDeviceIdentifier() async {
  String deviceIdentifier = "unknown";
  DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();

  if (Platform.isAndroid) {
    AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
    deviceIdentifier = androidInfo.androidId;
  } else if (Platform.isIOS) {
    IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
    deviceIdentifier = iosInfo.identifierForVendor;
  } else if (kIsWeb) {
    // The web doesnt have a device UID, so use a combination fingerprint as an example
    WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
    deviceIdentifier = webInfo.vendor + webInfo.userAgent + webInfo.hardwareConcurrency.toString();
  } else if (Platform.isLinux) {
    LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
    deviceIdentifier = linuxInfo.machineId;
  } 
  return deviceIdentifier;
}

Solution 5 - Flutter

Use device_id plugin

Add in your following code in your .yaml file.
```
device_id: ^0.1.3
```

Add import in your class

import 'package:device_id/device_id.dart';

Now get device id from:

String deviceid = await DeviceId.getID;

Solution 6 - Flutter

Latest:

The plugin device_info has given deprecation notice and replaced by device_info_plus

Example:

dependencies:
  device_info_plus: ^2.1.0

How to use:

import 'package:device_info_plus/device_info_plus.dart';

DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();

AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
print('Running on ${androidInfo.model}');  // e.g. "Moto G (4)"

IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
print('Running on ${iosInfo.utsname.machine}');  // e.g. "iPod7,1"

WebBrowserInfo webBrowserInfo = await deviceInfo.webBrowserInfo;
print('Running on ${webBrowserInfo.userAgent}');  // e.g. "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:61.0) Gecko/20100101 Firefox/61.0"

You can check here full example:

For Unique ID:

You can use following code to get Unique ID:

if (kIsWeb) {
  WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
  deviceIdentifier = webInfo.vendor +
      webInfo.userAgent +
      webInfo.hardwareConcurrency.toString();
} else {
  if (Platform.isAndroid) {
    AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
    deviceIdentifier = androidInfo.androidId;
  } else if (Platform.isIOS) {
    IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
    deviceIdentifier = iosInfo.identifierForVendor;
  } else if (Platform.isLinux) {
    LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
    deviceIdentifier = linuxInfo.machineId;
  }
}

Solution 7 - Flutter

I release a new flutter plugin client_information might help. It provide a simple way to get some basic device information from your application user.

add to pubspec.yaml

  dependencies:
    ...
    client_information: ^1.0.1

import to your project

import 'package:client_information/client_information.dart';

then you can get device ID like this

/// Support on iOS, Android and web project
Future<String> getDeviceId() async {
  return (await ClientInformation.fetch()).deviceId;
}

Solution 8 - Flutter

Add the following code in your .yaml file.

device_info_plus: ^1.0.0

I used the following approach to get the device info that support in all platforms (i.e.) Android, IOS and Web.

import 'dart:io';  
import 'package:device_info_plus/device_info_plus.dart';  
import 'package:flutter/foundation.dart' show kIsWeb;  

Future<String> getDeviceIdentifier() async { 

    String deviceIdentifier = "unknown";  
    DeviceInfoPlugin deviceInfo = DeviceInfoPlugin();  

    if (kIsWeb) {
      WebBrowserInfo webInfo = await deviceInfo.webBrowserInfo;
      deviceIdentifier = webInfo.vendor +
          webInfo.userAgent +
          webInfo.hardwareConcurrency.toString();
    } else {
      if (Platform.isAndroid) {
        AndroidDeviceInfo androidInfo = await deviceInfo.androidInfo;
        deviceIdentifier = androidInfo.androidId;
      } else if (Platform.isIOS) {
        IosDeviceInfo iosInfo = await deviceInfo.iosInfo;
        deviceIdentifier = iosInfo.identifierForVendor;
      } else if (Platform.isLinux) {
        LinuxDeviceInfo linuxInfo = await deviceInfo.linuxInfo;
        deviceIdentifier = linuxInfo.machineId;
      }
    }
    return deviceIdentifier;
}

Solution 9 - Flutter

Use device_info_plus package developed by Flutter community. This is how you can get IDs on both platform.

In your pubspec.yaml file add this:

dependencies:
  device_info_plus: ^3.2.3

Create a method:

Future<String> getUniqueDeviceId() async {
  String uniqueDeviceId = '';

  var deviceInfo = DeviceInfoPlugin();

  if (Platform.isIOS) { // import 'dart:io'
    var iosDeviceInfo = await deviceInfo.iosInfo;
    uniqueDeviceId = '${iosDeviceInfo.name}:${iosDeviceInfo.identifierForVendor}'; // unique ID on iOS
  } else if(Platform.isAndroid) {
    var androidDeviceInfo = await deviceInfo.androidInfo;
    uniqueDeviceId = '${androidDeviceInfo.name}:${androidDeviceInfo.id}' ; // unique ID on Android
  }
  
  return uniqueDeviceId;

}

Usage:

String deviceId = await getUniqueDeviceId();

Output:

M2102J20SG::SKQ1.211006.001

Note:

Do not use androidDeviceInfo.androidId. This would change when your mac address changes. Mobile devices above Android OS 10/11 will generate a randomized MAC. This feature is enabled by default unless disabled manually. This would cause the androidId to change when switiching networks. You can confirm this by yourself by changing androidDeviceInfo.id to androidDeviceInfo.androidId above.
you can probably get away with using only androidDeviceInfo.name as it would not change ever.
androidDeviceInfo.id can also change if OS is updated as it is an android os version.
androidDeviceInfo.androidId should only be used if device uses fix mac address as mentioned in point 1. Otherwise, either use *.name only or androidDeviceInfo.id alongside with *.name.

Solution 10 - Flutter

If you're serving ads you can use ASIdentifierManager. You should only use it for ads. There is no general UDID mechanism provided by the OS on iOS, for privacy reasons.

If you're using firebase_auth plugin you could signInAnonymously and then use the id of the FirebaseUser. This will give you an identifier that is specific to your Firebase app.

Content Type	Original Author	Original Content on Stackoverflow
Question	karan vs	View Question on Stackoverflow
Solution 1 - Flutter	CopsOnRoad	View Answer on Stackoverflow
Solution 2 - Flutter	Chaythanya Nair	View Answer on Stackoverflow
Solution 3 - Flutter	user3517658	View Answer on Stackoverflow
Solution 4 - Flutter	Oswin Noetzelmann	View Answer on Stackoverflow
Solution 5 - Flutter	user9740540	View Answer on Stackoverflow
Solution 6 - Flutter	Pratik Butani	View Answer on Stackoverflow
Solution 7 - Flutter	KentChien	View Answer on Stackoverflow
Solution 8 - Flutter	Gowtham. R	View Answer on Stackoverflow
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Solution 10 - Flutter	Collin Jackson	View Answer on Stackoverflow