How to get all of the IDs with jQuery?

JavascriptJquery

Javascript Problem Overview


I am trying to gather a list (array) of ids in a sector

<div id="mydiv">
 <span id='span1'>
 <span id='span2'>
</div>

$("#mydiv").find("span"); 

gives me a jQuery object, but not a real array;

I can do

var array = jQuery.makeArray($("#mydiv").find("span"));

and then use a for loop to put the id attributes into another array

or I can do

$("#mydiv").find("span").each(function(){}); //but i cannot really get the id and assign it to an array that is not with in the scope?(or can I)

Anyhow, I just wanna see if there is a shorthand in jQuery to do that;

Javascript Solutions


Solution 1 - Javascript

> //but i cannot really get the id and assign it to an array that is not with in the scope?(or can I)

Yes, you can!

var IDs = [];
$("#mydiv").find("span").each(function(){ IDs.push(this.id); });

This is the beauty of closures.

Note that while you were on the right track, sighohwell and cletus both point out more reliable and concise ways of accomplishing this, taking advantage of attribute filters (to limit matched elements to those with IDs) and jQuery's built-in map() function:

var IDs = $("#mydiv span[id]")         // find spans with ID attribute
  .map(function() { return this.id; }) // convert to set of IDs
  .get(); // convert to instance of Array (optional)

Solution 2 - Javascript

The .get() method will return an array from a jQuery object. In addition you can use .map to project to something before calling get()

var idarray = $("#myDiv")
             .find("span") //Find the spans
             .map(function() { return this.id; }) //Project Ids
             .get(); //ToArray

Solution 3 - Javascript

My suggestion?

var arr = $.map($("#mydiv [id]"), function(n, i) {
  return n.id;
});

you could also do this as:

var arr = $.map($("#mydiv span"), function(n, i) {

or

var arr = $.map($("#mydiv span[id]"), function(n, i) {

or even just:

var arr = $("#mydiv [id]").map(function() {
  return this.id;
});

Lots of ways basically.

Solution 4 - Javascript

The best way I can think of to answer this is to make a custom jquery plugin to do this:

jQuery.fn.getIdArray = function() {
  var ret = [];
  $('[id]', this).each(function() {
    ret.push(this.id);
  });
  return ret;
};

Then do something like

var array = $("#mydiv").getIdArray();

Solution 5 - Javascript

It's a late answer but now there is an easy way. Current version of jquery lets you search if attribute exists. For example

$('[id]')

will give you all the elements if they have id. If you want all spans with id starting with span you can use

$('span[id^="span"]')

Solution 6 - Javascript

Not a real array, but objs are all associative arrays in javascript.

I chose not to use a real array with [] and [].push because technically, you can have multiple ID's on a page even though that is incorrect to do so. So just another option in case some html has duplicated ID's

$(function() {

       var oArr = {};
       $("*[id]").each(function() {
           var id = $(this).attr('id');
           if (!oArr[id]) oArr[id] = true;
       });

       for (var prop in oArr)
           alert(prop);

   });

Solution 7 - Javascript

HTML

<div id="mydiv">
 <span id='span1'>
 <span id='span2'>
</div>

JQuery

var IDs = [];
$("#mydiv").find("span").each(function(){ IDs.push($(this).attr("id")); });

Solution 8 - Javascript

You can get the ids of specifict tags and send it to a annother element. For exemple:

$("input").map(function() {
    $( "textarea" ).append(this.id+"\n");
});

It will get all input ids and send it to textarea.

Solution 9 - Javascript

for(i=1;i<13;i++)     
{
  
   alert($("#tdt"+i).val());  

}  

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRoy ChanView Question on Stackoverflow
Solution 1 - JavascriptShog9View Answer on Stackoverflow
Solution 2 - JavascriptJohn FosterView Answer on Stackoverflow
Solution 3 - JavascriptcletusView Answer on Stackoverflow
Solution 4 - JavascriptgnarfView Answer on Stackoverflow
Solution 5 - JavascriptCihad TurhanView Answer on Stackoverflow
Solution 6 - JavascriptChad GrantView Answer on Stackoverflow
Solution 7 - JavascriptSoliQuiDView Answer on Stackoverflow
Solution 8 - JavascriptGeraldo VilgerView Answer on Stackoverflow
Solution 9 - JavascriptdskView Answer on Stackoverflow