How to get a URL parameter in Express?

Javascriptnode.jsExpressUrl ParametersQuery Parameters

Javascript Problem Overview


I am facing an issue on getting the value of tagid from my URL: localhost:8888/p?tagid=1234.

Help me out to correct my controller code. I am not able to get the tagid value.

My code is as follows:

app.js:

var express = require('express'),
  http = require('http'),
  path = require('path');
var app = express();
var controller = require('./controller')({
  app: app
});

// all environments
app.configure(function() {
  app.set('port', process.env.PORT || 8888);
  app.use(express.json());
  app.use(express.urlencoded());
  app.use(express.methodOverride());
  app.use(app.router);
  app.use(express.static(path.join(__dirname, 'public')));
  app.set('view engine', 'jade');
  app.set('views', __dirname + '/views');
  app.use(app.router);
  app.get('/', function(req, res) {
    res.render('index');
  });
});
http.createServer(app).listen(app.get('port'), function() {
  console.log('Express server listening on port ' + app.get('port'));
});

Controller/index.js:

function controller(params) {
  var app = params.app;
  //var query_string = request.query.query_string;

  app.get('/p?tagId=/', function(request, response) {
    // userId is a parameter in the url request
    response.writeHead(200); // return 200 HTTP OK status
    response.end('You are looking for tagId' + request.route.query.tagId);
  });
}

module.exports = controller;

routes/index.js:

require('./controllers');
/*
 * GET home page.
 */

exports.index = function(req, res) {
  res.render('index', {
    title: 'Express'
  });
};

Javascript Solutions


Solution 1 - Javascript

Express 4.x

To get a URL parameter's value, use req.params

app.get('/p/:tagId', function(req, res) {
  res.send("tagId is set to " + req.params.tagId);
});

// GET /p/5
// tagId is set to 5

If you want to get a query parameter ?tagId=5, then use req.query

app.get('/p', function(req, res) {
  res.send("tagId is set to " + req.query.tagId);
});

// GET /p?tagId=5
// tagId is set to 5

Express 3.x

URL parameter

app.get('/p/:tagId', function(req, res) {
  res.send("tagId is set to " + req.param("tagId"));
});

// GET /p/5
// tagId is set to 5

Query parameter

app.get('/p', function(req, res) {
  res.send("tagId is set to " + req.query("tagId"));
});

// GET /p?tagId=5
// tagId is set to 5

Solution 2 - Javascript

You can do something like req.param('tagId')

Solution 3 - Javascript

If you want to grab the query parameter value in the URL, follow below code pieces

//url.localhost:8888/p?tagid=1234
req.query.tagid
OR
req.param.tagid

If you want to grab the URL parameter using Express param function

Express param function to grab a specific parameter. This is considered middleware and will run before the route is called.

This can be used for validations or grabbing important information about item.

An example for this would be:

// parameter middleware that will run before the next routes
app.param('tagid', function(req, res, next, tagid) {

// check if the tagid exists
// do some validations
// add something to the tagid
var modified = tagid+ '123';

// save name to the request
req.tagid= modified;

next();
});

// http://localhost:8080/api/tags/98
app.get('/api/tags/:tagid', function(req, res) {
// the tagid was found and is available in req.tagid
res.send('New tag id ' + req.tagid+ '!');
});

Solution 4 - Javascript

This will work if your route looks like this: localhost:8888/p?tagid=1234

var tagId = req.query.tagid;
console.log(tagId); // outputs: 1234
console.log(req.query.tagid); // outputs: 1234

Otherwise use the following code if your route looks like this: localhost:8888/p/1234

var tagId = req.params.tagid;
console.log(tagId); // outputs: 1234
console.log(req.params.tagid); // outputs: 1234

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser2834795View Question on Stackoverflow
Solution 1 - JavascriptmačekView Answer on Stackoverflow
Solution 2 - JavascripttomahimView Answer on Stackoverflow
Solution 3 - JavascriptMalatesh PatilView Answer on Stackoverflow
Solution 4 - Javascriptajay sainiView Answer on Stackoverflow