How to find the size of a table in SQL?

How to find the size of a table in SQL?

SQL Server:-

sp_spaceused 'TableName'

Or in management studio: Right Click on table -> Properties -> Storage

MySQL:-

SELECT table_schema, table_name, data_length, index_length FROM information_schema.tables

Sybase:-

sp_spaceused 'TableName'

Oracle:- how-do-i-calculate-tables-size-in-oracle

Combining the answers from ratty's and Haim's posts (including comments) I've come up with this, which for SQL Server seems to be the most elegant so far:

-- DROP TABLE #tmpTableSizes
CREATE TABLE #tmpTableSizes
(
    tableName varchar(100),
    numberofRows varchar(100),
    reservedSize varchar(50),
    dataSize varchar(50),
    indexSize varchar(50),
    unusedSize varchar(50)
)
insert #tmpTableSizes
EXEC sp_MSforeachtable @command1="EXEC sp_spaceused '?'"


select  * from #tmpTableSizes
order by cast(LEFT(reservedSize, LEN(reservedSize) - 4) as int)  desc

This gives you a list of all your tables in order of reserved size, ordered from largest to smallest.

A query (modification of https://stackoverflow.com/a/7892349/1737819) to find a custom name table size in GB. You might try this, replace 'YourTableName' with the name of your table.

SELECT 
    t.NAME AS TableName,    
    p.rows AS RowCounts,
    CONVERT(DECIMAL,SUM(a.total_pages)) * 8 / 1024 / 1024 AS TotalSpaceGB, 
    SUM(a.used_pages)  * 8 / 1024 / 1024 AS UsedSpaceGB , 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 / 1024 / 1024 AS UnusedSpaceGB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME = 'YourTable'
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    UsedSpaceGB DESC, t.Name

SQL Server provides a built-in stored procedure that you can run to easily show the size of a table, including the size of the indexes… which might surprise you.

Syntax:

 sp_spaceused 'Tablename'

see in :

http://www.howtogeek.com/howto/database/determine-size-of-a-table-in-sql-server/

Do you by size mean the number of records in the table, by any chance? In that case:

SELECT COUNT(*) FROM your_table_name

I know that in SQL 2012 (may work in other versions) you can do the following:

1. Right click on the database name in the Object Explorer.
2. Select Reports > Standard Reports > Disk Usage by Top Tables.

That will give you a list of the top 1000 tables and then you can order it by data size etc.

And in PostgreSQL:

SELECT pg_size_pretty(pg_relation_size('tablename'));

SQL Server, nicely formatted table for all tables in KB/MB:

SELECT 
    t.NAME AS TableName,
    s.Name AS SchemaName,
    p.rows AS RowCounts,
    SUM(a.total_pages) * 8 AS TotalSpaceKB, 
    CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
    SUM(a.used_pages) * 8 AS UsedSpaceKB, 
    CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB, 
    (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
    CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN 
    sys.schemas s ON t.schema_id = s.schema_id
WHERE 
    t.NAME NOT LIKE 'dt%' 
    AND t.is_ms_shipped = 0
    AND i.OBJECT_ID > 255 
GROUP BY 
    t.Name, s.Name, p.Rows
ORDER BY 
    t.Name

You may refer the answer by Marc_s in another thread, Very useful.

https://stackoverflow.com/questions/7892334/get-size-of-all-tables-in-database

Here's a simple query, if you are just trying to find the largest tables.

  -- Find largest table partitions
 SELECT top 20 obj.name, LTRIM (STR ( sz.in_row_data_page_count * 8, 15, 0) + ' KB') as Size, * FROM sys.dm_db_partition_stats sz
inner join sys.objects obj on obj.object_id = sz.object_id
  order by sz.in_row_data_page_count desc