How to find processes based on port and kill them all?
BashShellBash Problem Overview
Find processes based on port number and kill them all.
ps -efl | grep PORT_NUMBER | kill -9 process_found_previously
how to complete the last column?
Bash Solutions
Solution 1 - Bash
The problem with ps -efl | grep PORT_NUMBER is that PORT_NUMBER may match other columns in the output of ps as well (date, time, pid, ...). A potential killing spree if run by root!
I would do this instead :
PORT_NUMBER=1234
lsof -i tcp:${PORT_NUMBER} | awk 'NR!=1 {print $2}' | xargs kill
Breakdown of command
- (
lsof -i tcp:${PORT_NUMBER}) -- list all processes that is listening on that tcp port - (
awk 'NR!=1 {print $2}') -- ignore first line, print second column of each line - (
xargs kill) -- pass on the results as an argument tokill. There may be several.
Solution 2 - Bash
1.) lsof -w -n -i tcp:8080
2.) kill -9 processId
Solution 3 - Bash
kill $( lsof -i:6000 -t )
Or if you need permissions:
sudo kill $( sudo lsof -i:6000 -t )
Solution 4 - Bash
Propose to use fuser command:
fuser -k -TERM -n tcp ${PORT_NUMBER}
Solution 5 - Bash
sudo fuser -k 8080/tcp
An easy one to remember.
This syntax is probably much more recent than the date of the question!
Solution 6 - Bash
... | awk '{ print $4 }' | xargs kill -9
please test with "echo" instead of "kill" before running
Solution 7 - Bash
To kill all processes listening on a particular port, e.g. port 8864
kill -9 $ \`lsof -i:8864 -t\`
Replace 8864 by the port you want.