How to echo shell commands as they are executed

BashShellShPosixTrace

Bash Problem Overview


In a shell script, how do I echo all shell commands called and expand any variable names?

For example, given the following line:

ls $DIRNAME

I would like the script to run the command and display the following

ls /full/path/to/some/dir

The purpose is to save a log of all shell commands called and their arguments. Is there perhaps a better way of generating such a log?

Bash Solutions


Solution 1 - Bash

set -x or set -o xtrace expands variables and prints a little + sign before the line.

set -v or set -o verbose does not expand the variables before printing.

Use set +x and set +v to turn off the above settings.

On the first line of the script, one can put #!/bin/sh -x (or -v) to have the same effect as set -x (or -v) later in the script.

The above also works with /bin/sh.

See the bash-hackers' wiki on set attributes, and on debugging.

$ cat shl
#!/bin/bash                                                                     

DIR=/tmp/so
ls $DIR

$ bash -x shl 
+ DIR=/tmp/so
+ ls /tmp/so
$

Solution 2 - Bash

set -x will give you what you want.

Here is an example shell script to demonstrate:

#!/bin/bash
set -x #echo on

ls $PWD

This expands all variables and prints the full commands before output of the command.

Output:

+ ls /home/user/
file1.txt file2.txt

Solution 3 - Bash

I use a function to echo and run the command:

#!/bin/bash
# Function to display commands
exe() { echo "\$ $@" ; "$@" ; }

exe echo hello world

Which outputs

$ echo hello world
hello world

For more complicated commands pipes, etc., you can use eval:

#!/bin/bash
# Function to display commands
exe() { echo "\$ ${@/eval/}" ; "$@" ; }

exe eval "echo 'Hello, World!' | cut -d ' ' -f1"

Which outputs

$  echo 'Hello, World!' | cut -d ' ' -f1
Hello

Solution 4 - Bash

You can also toggle this for select lines in your script by wrapping them in set -x and set +x, for example,

#!/bin/bash
...
if [[ ! -e $OUT_FILE ]];
then
   echo "grabbing $URL"
   set -x
   curl --fail --noproxy $SERV -s -S $URL -o $OUT_FILE
   set +x
fi

Solution 5 - Bash

shuckc's answer for echoing select lines has a few downsides: you end up with the following set +x command being echoed as well, and you lose the ability to test the exit code with $? since it gets overwritten by the set +x.

Another option is to run the command in a subshell:

echo "getting URL..."
( set -x ; curl -s --fail $URL -o $OUTFILE )

if [ $? -eq 0 ] ; then
    echo "curl failed"
    exit 1
fi

which will give you output like:

getting URL...
+ curl -s --fail http://example.com/missing -o /tmp/example
curl failed

This does incur the overhead of creating a new subshell for the command, though.

Solution 6 - Bash

According to TLDP's Bash Guide for Beginners: Chapter 2. Writing and debugging scripts:

>2.3.1. Debugging on the entire script > $ bash -x script1.sh ...

> There is now a full-fledged debugger for Bash, available at SourceForge. These debugging features are available in most modern versions of Bash, starting from 3.x.

>2.3.2. Debugging on part(s) of the script > > set -x # Activate debugging from here > w > set +x # Stop debugging from here ... > Table 2-1. Overview of set debugging options

    Short  | Long notation | Result
    -------+---------------+--------------------------------------------------------------
    set -f | set -o noglob | Disable file name generation using metacharacters (globbing).
    set -v | set -o verbose| Prints shell input lines as they are read.
    set -x | set -o xtrace | Print command traces before executing command.

> ... > > Alternatively, these modes can be specified in the script itself, by > adding the desired options to the first line shell declaration. > Options can be combined, as is usually the case with UNIX commands: > > #!/bin/bash -xv

Solution 7 - Bash

Another option is to put "-x" at the top of your script instead of on the command line:

$ cat ./server
#!/bin/bash -x
ssh user@server

$ ./server
+ ssh user@server
user@server's password: ^C
$

Solution 8 - Bash

You can execute a Bash script in debug mode with the -x option.

This will echo all the commands.

bash -x example_script.sh

# Console output
+ cd /home/user
+ mv text.txt mytext.txt

You can also save the -x option in the script. Just specify the -x option in the shebang.

######## example_script.sh ###################
#!/bin/bash -x

cd /home/user
mv text.txt mytext.txt

##############################################

./example_script.sh

# Console output
+ cd /home/user
+ mv text.txt mytext.txt

Solution 9 - Bash

Type "bash -x" on the command line before the name of the Bash script. For instance, to execute foo.sh, type:

bash -x foo.sh

Solution 10 - Bash

Combining all the answers I found this to be the best, simplest

# https://stackoverflow.com/a/64644990/8608146
exe(){
    set -x
    "$@"
    { set +x; } 2>/dev/null
}
# example
exe go generate ./...

{ set +x; } 2>/dev/null from https://stackoverflow.com/a/19226038/8608146

If the exit status of the command is needed, as mentioned here

Use

{ STATUS=$?; set +x; } 2>/dev/null

And use the $STATUS later like exit $STATUS at the end

A slightly more useful one

# https://stackoverflow.com/a/64644990/8608146
_exe(){
    [ $1 == on  ] && { set -x; return; } 2>/dev/null
    [ $1 == off ] && { set +x; return; } 2>/dev/null
    echo + "$@"
    "$@"
}
exe(){
    { _exe "$@"; } 2>/dev/null
}

# examples
exe on # turn on same as set -x
echo This command prints with +
echo This too prints with +
exe off # same as set +x
echo This does not

# can also be used for individual commands
exe echo what up!

Solution 11 - Bash

For zsh, echo

setopt VERBOSE

And for debugging,

setopt XTRACE

Solution 12 - Bash

To allow for compound commands to be echoed, I use eval plus Soth's exe function to echo and run the command. This is useful for piped commands that would otherwise only show none or just the initial part of the piped command.

Without eval:

exe() { echo "\$ $@" ; "$@" ; }
exe ls -F | grep *.txt

Outputs:

$
file.txt

With eval:

exe() { echo "\$ $@" ; "$@" ; }
exe eval 'ls -F | grep *.txt'

Which outputs

$ exe eval 'ls -F | grep *.txt'
file.txt

Solution 13 - Bash

For csh and tcsh, you can set verbose or set echo (or you can even set both, but it may result in some duplication most of the time).

The verbose option prints pretty much the exact shell expression that you type.

The echo option is more indicative of what will be executed through spawning.


http://www.tcsh.org/tcsh.html/Special_shell_variables.html#verbose

http://www.tcsh.org/tcsh.html/Special_shell_variables.html#echo


Special shell variables

verbose If set, causes the words of each command to be printed, after history substitution (if any). Set by the -v command line option.

echo If set, each command with its arguments is echoed just before it is executed. For non-builtin commands all expansions occur before echoing. Builtin commands are echoed before command and filename substitution, because these substitutions are then done selectively. Set by the -x command line option.

Solution 14 - Bash

$ cat exampleScript.sh
#!/bin/bash
name="karthik";
echo $name;

bash -x exampleScript.sh

Output is as follows:

enter image description here

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionJack NockView Question on Stackoverflow
Solution 1 - BashTomView Answer on Stackoverflow
Solution 2 - BashradmanView Answer on Stackoverflow
Solution 3 - BashSothView Answer on Stackoverflow
Solution 4 - BashshuckcView Answer on Stackoverflow
Solution 5 - BashbhasselView Answer on Stackoverflow
Solution 6 - BashAfriza N. AriefView Answer on Stackoverflow
Solution 7 - BashnoojView Answer on Stackoverflow
Solution 8 - BashRenRenView Answer on Stackoverflow
Solution 9 - BashAlanView Answer on Stackoverflow
Solution 10 - BashPhani RithvijView Answer on Stackoverflow
Solution 11 - BashzzapperView Answer on Stackoverflow
Solution 12 - BashPaul HavensView Answer on Stackoverflow
Solution 13 - BashcnstView Answer on Stackoverflow
Solution 14 - BashKarthik ArunView Answer on Stackoverflow