How to do case insensitive string comparison?

JavascriptString

Javascript Problem Overview


How do I perform case insensitive string comparison in JavaScript?

Javascript Solutions


Solution 1 - Javascript

The simplest way to do it (if you're not worried about special Unicode characters) is to call toUpperCase:

var areEqual = string1.toUpperCase() === string2.toUpperCase();

Solution 2 - Javascript

EDIT: This answer was originally added 9 years ago. Today you should use localeCompare with the sensitivity: 'accent' option:

function ciEquals(a, b) {
    return typeof a === 'string' && typeof b === 'string'
        ? a.localeCompare(b, undefined, { sensitivity: 'accent' }) === 0
        : a === b;
}

console.log("'a' = 'a'?", ciEquals('a', 'a'));
console.log("'AaA' = 'aAa'?", ciEquals('AaA', 'aAa'));
console.log("'a' = 'á'?", ciEquals('a', 'á'));
console.log("'a' = 'b'?", ciEquals('a', 'b'));

The { sensitivity: 'accent' } tells localeCompare() to treat two variants of the same base letter as the same unless they have different accents (as in the third example) above.

Alternatively, you can use { sensitivity: 'base' }, which treats two characters as equivalent as long as their base character is the same (so A would be treated as equivalent to á).

Note that the third parameter of localeCompare is not supported in IE10 or lower or certain mobile browsers (see the compatibility chart on the page linked above), so if you need to support those browsers, you'll need some kind of fallback:

function ciEqualsInner(a, b) {
    return a.localeCompare(b, undefined, { sensitivity: 'accent' }) === 0;
}

function ciEquals(a, b) {
    if (typeof a !== 'string' || typeof b !== 'string') {
        return a === b;
    }

    //      v--- feature detection
    return ciEqualsInner('A', 'a')
        ? ciEqualsInner(a, b)
        : /*  fallback approach here  */;
}

Original answer

The best way to do a case insensitive comparison in JavaScript is to use RegExp match() method with the i flag.

https://stackoverflow.com/questions/177719/javascript-case-insensitive-search

When both strings being compared are variables (not constants), then it's a little more complicated 'cause you need to generate a RegExp from the string but passing the string to RegExp constructor can result in incorrect matches or failed matches if the string has special regex characters in it.

If you care about internationalization don't use toLowerCase() or toUpperCase() as it doesn't provide accurate case-insensitive comparisons in all languages.

http://www.i18nguy.com/unicode/turkish-i18n.html

Solution 3 - Javascript

As said in recent comments, string::localeCompare supports case insensitive comparisons (among other powerful things).

Here's a simple example

'xyz'.localeCompare('XyZ', undefined, { sensitivity: 'base' }); // returns 0

And a generic function you could use

function equalsIgnoringCase(text, other) {
    return text.localeCompare(other, undefined, { sensitivity: 'base' }) === 0;
}

Note that instead of undefined you should probably enter the specific locale you are working with. This is important as denoted in the MDN docs

> in Swedish, ä and a are separate base letters

Sensitivity options

Sensitivity options tabulated from MDN

Browser support

As of time of posting, UC Browser for Android and Opera Mini do not support locale and options parameters. Please check https://caniuse.com/#search=localeCompare for up to date info.

Solution 4 - Javascript

Update:

As per the comments, previous answer checks for source contains keyword, to make it equality check added ^ and $.

(/^keyword$/i).test(source)

With the help of regular expression also we can achieve.

(/keyword/i).test(source)

/i is for ignoring case. If not necessary we can ignore and test for NOT case sensitive matches like

(/keyword/).test(source)

Solution 5 - Javascript

Remember that casing is a locale specific operation. Depending on scenario you may want to take that in to account. For example, if you are comparing names of two people you may want to consider locale but if you are comparing machine generated values such as UUID then you might not. This why I use following function in my utils library (note that type checking is not included for performance reason).

function compareStrings (string1, string2, ignoreCase, useLocale) {
	if (ignoreCase) {
		if (useLocale) {
			string1 = string1.toLocaleLowerCase();
			string2 = string2.toLocaleLowerCase();
		}
		else {
			string1 = string1.toLowerCase();
			string2 = string2.toLowerCase();
		}
	}

	return string1 === string2;
}

Solution 6 - Javascript

if you are concerned about the direction of the inequality (perhaps you want to sort a list) you pretty-much have to do case-conversion, and as there are more lowercase characters in unicode than uppercase toLowerCase is probably the best conversion to use.

function my_strcasecmp( a, b ) 
{
	if((a+'').toLowerCase() > (b+'').toLowerCase()) return 1  
	if((a+'').toLowerCase() < (b+'').toLowerCase()) return -1
	return 0
}

Javascript seems to use locale "C" for string comparisons so the resulting ordering will be ugly if the strings contain other than ASCII letters. there's not much that can be done about that without doing much more detailed inspection of the strings.

Solution 7 - Javascript

I have recently created a micro library that provides case-insensitive string helpers: https://github.com/nickuraltsev/ignore-case. (It uses toUpperCase internally.)

var ignoreCase = require('ignore-case');

ignoreCase.equals('FOO', 'Foo'); // => true
ignoreCase.startsWith('foobar', 'FOO'); // => true
ignoreCase.endsWith('foobar', 'BaR'); // => true
ignoreCase.includes('AbCd', 'c'); // => true
ignoreCase.indexOf('AbCd', 'c'); // => 2

Solution 8 - Javascript

Suppose we want to find the string variable needle in the string variable haystack. There are three gotchas:

  1. Internationalized applications should avoid string.toUpperCase and string.toLowerCase. Use a regular expression which ignores case instead. For example, var needleRegExp = new RegExp(needle, "i"); followed by needleRegExp.test(haystack).
  2. In general, you might not know the value of needle. Be careful that needle does not contain any regular expression special characters. Escape these using needle.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, "\\$&");.
  3. In other cases, if you want to precisely match needle and haystack, just ignoring case, make sure to add "^" at the start and "$" at the end of your regular expression constructor.

Taking points (1) and (2) into consideration, an example would be:

var haystack = "A. BAIL. Of. Hay.";
var needle = "bail.";
var needleRegExp = new RegExp(needle.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, "\\$&"), "i");
var result = needleRegExp.test(haystack);
if (result) {
    // Your code here
}

Solution 9 - Javascript

Lots of answers here, but I like to add a sollution based on extending the String lib:

String.prototype.equalIgnoreCase = function(str)
{
    return (str != null 
            && typeof str === 'string'
            && this.toUpperCase() === str.toUpperCase());
}

This way you can just use it like you do in Java!

Example:

var a = "hello";
var b = "HeLLo";
var c = "world";

if (a.equalIgnoreCase(b)) {
    document.write("a == b");
}
if (a.equalIgnoreCase(c)) {
    document.write("a == c");
}
if (!b.equalIgnoreCase(c)) {
    document.write("b != c");
}

Output will be:

"a == b"
"b != c"

String.prototype.equalIgnoreCase = function(str) {
  return (str != null &&
    typeof str === 'string' &&
    this.toUpperCase() === str.toUpperCase());
}


var a = "hello";
var b = "HeLLo";
var c = "world";

if (a.equalIgnoreCase(b)) {
  document.write("a == b");
  document.write("<br>");
}
if (a.equalIgnoreCase(c)) {
  document.write("a == c");
}
if (!b.equalIgnoreCase(c)) {
  document.write("b != c");
}

Solution 10 - Javascript

Use RegEx for string match or comparison.

In JavaScript, you can use match() for string comparison, don't forget to put i in RegEx.

Example:

var matchString = "Test";
if (matchString.match(/test/i)) {
    alert('String matched');
}
else {
    alert('String not matched');
}

Solution 11 - Javascript

There are two ways for case insensitive comparison:

  1. Convert strings to upper case and then compare them using the strict operator (===).
  2. Pattern matching using string methods:

Use the "search" string method for case insensitive search.

<!doctype html>
<html>

<head>
  <script>
    // 1st way

    var a = "apple";
    var b = "APPLE";
    if (a.toUpperCase() === b.toUpperCase()) {
      alert("equal");
    }

    //2nd way

    var a = " Null and void";
    document.write(a.search(/null/i));
  </script>
</head>

</html>

Solution 12 - Javascript

If both strings are of the same known locale, you may want to use Intl.Collator object like this:

function equalIgnoreCase(s1: string, s2: string) {
    return new Intl.Collator("en-US", { sensitivity: "base" }).compare(s1, s2) === 0;
}

Obviously, you may want to cache the Collator for better efficiency.

The advantages of this approach is that it should be much faster than using RegExps and is based on an extremely customizable (see description of locales and options constructor parameters in the article above) set of ready-to-use collators.

Solution 13 - Javascript

I like this quick shorthand variation -

export const equalsIgnoreCase = (str1, str2) => {
    return (!str1 && !str2) || (str1 && str2 && str1.toUpperCase() == str2.toUpperCase())
}

Quick in processing, and does what it is intended to.

Solution 14 - Javascript

Even this question has already been answered. I have a different approach to using RegExp and match to ignore case sensitivity. Please see my link https://jsfiddle.net/marchdave/7v8bd7dq/27/

$("#btnGuess").click(guessWord);

function guessWord() {

  var letter = $("#guessLetter").val();
  var word = 'ABC';
  var pattern = RegExp(letter, 'gi'); // pattern: /a/gi

  var result = word.match(pattern);
  alert('Ignore case sensitive:' + result);
}

Solution 15 - Javascript

str = 'Lol', str2 = 'lOl', regex = new RegExp('^' + str + '$', 'i');
if (regex.test(str)) {
    console.log("true");
}

Solution 16 - Javascript

I wrote a extension. very trivial

if (typeof String.prototype.isEqual!= 'function') {
    String.prototype.isEqual = function (str){
        return this.toUpperCase()==str.toUpperCase();
     };
}

Solution 17 - Javascript

Convert both to lower string (only once for performance reasons) and compare them with inline ternary operator:

function strcasecmp(s1,s2){
    s1=(s1+'').toLowerCase();
    s2=(s2+'').toLowerCase();
    return s1>s2?1:(s1<s2?-1:0);
}

Solution 18 - Javascript

How about NOT throwing exceptions and NOT using slow regex?

return str1 != null && str2 != null 
    && typeof str1 === 'string' && typeof str2 === 'string'
    && str1.toUpperCase() === str2.toUpperCase();

The above snippet assumes you don't want to match if either string is null or undefined.

If you want to match null/undefined, then:

return (str1 == null && str2 == null)
    || (str1 != null && str2 != null 
        && typeof str1 === 'string' && typeof str2 === 'string'
        && str1.toUpperCase() === str2.toUpperCase());

If for some reason you care about undefined vs null:

return (str1 === undefined && str2 === undefined)
    || (str1 === null && str2 === null)
    || (str1 != null && str2 != null 
        && typeof str1 === 'string' && typeof str2 === 'string'
        && str1.toUpperCase() === str2.toUpperCase());

Solution 19 - Javascript

Since no answer clearly provided a simple code snippet for using RegExp, here's my attempt:

function compareInsensitive(str1, str2){ 
  return typeof str1 === 'string' && 
    typeof str2 === 'string' && 
    new RegExp("^" + str1.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') + "$", "i").test(str2);
}

It has several advantages:

  1. Verifies parameter type (any non-string parameter, like undefined for example, would crash an expression like str1.toUpperCase()).
  2. Does not suffer from possible internationalization issues.
  3. Escapes the RegExp string.

Solution 20 - Javascript

If you know you're dealing with ascii text then you can just use a uppercase/lowercase character offset comparison.

Just make sure the string your "perfect" string (the one you want to match against) is lowercase:

const CHARS_IN_BETWEEN = 32;
const LAST_UPPERCASE_CHAR = 90; // Z
function strMatchesIgnoreCase(lowercaseMatch, value) {
    let i = 0, matches = lowercaseMatch.length === value.length;
    while (matches && i < lowercaseMatch.length) {
        const a = lowercaseMatch.charCodeAt(i);
        const A = a - CHARS_IN_BETWEEN;
        const b = value.charCodeAt(i);
        const B = b + ((b > LAST_UPPERCASE_CHAR) ? -CHARS_IN_BETWEEN : CHARS_IN_BETWEEN);
        matches = a === b // lowerA === b
            || A === b // upperA == b
            || a === B // lowerA == ~b
            || A === B; // upperA == ~b
        i++;
    }
    return matches;
}

Solution 21 - Javascript

For better browser compatibility you can rely on a regular expression. This will work in all web browsers released in the last 20 years:

String.prototype.equalsci = function(s) {
	var regexp = RegExp("^"+this.replace(/[.\\+*?\[\^\]$(){}=!<>|:-]/g, "\\$&")+"$", "i");
	return regexp.test(s);
}

"PERSON@Ü.EXAMPLE.COM".equalsci("person@ü.example.com")// returns true

This is different from the other answers found here because it takes into account that not all users are using modern web browsers.

Note: If you need to support unusual cases like the Turkish language you will need to use localeCompare because i and I are not the same letter in Turkish.

"I".localeCompare("i", undefined, { sensitivity:"accent"})===0// returns true
"I".localeCompare("i", "tr", { sensitivity:"accent"})===0// returns false

Solution 22 - Javascript

This is an improved version of this answer.

String.equal = function (s1, s2, ignoreCase, useLocale) {
    if (s1 == null || s2 == null)
        return false;

    if (!ignoreCase) {
        if (s1.length !== s2.length)
            return false;

        return s1 === s2;
    }

    if (useLocale) {
        if (useLocale.length)
            return s1.toLocaleLowerCase(useLocale) === s2.toLocaleLowerCase(useLocale)
        else
            return s1.toLocaleLowerCase() === s2.toLocaleLowerCase()
    }
    else {
        if (s1.length !== s2.length)
            return false;

        return s1.toLowerCase() === s2.toLowerCase();
    }
}



Usages & tests:

String.equal = function (s1, s2, ignoreCase, useLocale) {
    if (s1 == null || s2 == null)
        return false;

    if (!ignoreCase) {
        if (s1.length !== s2.length)
            return false;

        return s1 === s2;
    }

    if (useLocale) {
        if (useLocale.length)
            return s1.toLocaleLowerCase(useLocale) === s2.toLocaleLowerCase(useLocale)
        else
            return s1.toLocaleLowerCase() === s2.toLocaleLowerCase()
    }
    else {
        if (s1.length !== s2.length)
            return false;

        return s1.toLowerCase() === s2.toLowerCase();
    }
}

// If you don't mind extending the prototype.
String.prototype.equal = function(string2, ignoreCase, useLocale) {
  return String.equal(this.valueOf(), string2, ignoreCase, useLocale);
}

// ------------------ TESTS ----------------------
console.log("Tests...");

console.log('Case sensitive 1');
var result = "Abc123".equal("Abc123");
console.assert(result === true);

console.log('Case sensitive 2');
result = "aBC123".equal("Abc123");
console.assert(result === false);

console.log('Ignore case');
result = "AbC123".equal("aBc123", true);
console.assert(result === true);

console.log('Ignore case + Current locale');
result = "AbC123".equal("aBc123", true);
console.assert(result === true);

console.log('Turkish test 1 (ignore case, en-US)');
result = "IiiI".equal("ıiİI", true, "en-US");
console.assert(result === false);

console.log('Turkish test 2 (ignore case, tr-TR)');
result = "IiiI".equal("ıiİI", true, "tr-TR");
console.assert(result === true);

console.log('Turkish test 3 (case sensitive, tr-TR)');
result = "IiiI".equal("ıiİI", false, "tr-TR");
console.assert(result === false);

console.log('null-test-1');
result = "AAA".equal(null);
console.assert(result === false);

console.log('null-test-2');
result = String.equal(null, "BBB");
console.assert(result === false);

console.log('null-test-3');
result = String.equal(null, null);
console.assert(result === false);

Solution 23 - Javascript

We could also do this using ASCII:

function toLower(a){

    let c = "";

    
    for(let i = 0;i<a.length;i++){

        
        let f = a.charCodeAt(i);
        if(f < 95){

            c += String.fromCharCode(f+32);
        }
        else{

            c += a[i];
        }
    }

    return c;
}
function compareIt(a,b){


    return toLower(a)==toLower(b);


}
console.log(compareIt("An ExamPlE" , "an example"));

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