How to convert string to integer in PowerShell

Powershell

Powershell Problem Overview


I have a list of directories with numbers. I have to find the highest number and and increment it by 1 and create a new directory with that increment value. I am able to sort the below array, but I am not able to increment the last element as it is a string.

How do I convert this below array element to an integer?

PS C:\Users\Suman\Desktop> $FileList

Name
----
11
2
1

Powershell Solutions


Solution 1 - Powershell

You can specify the type of a variable before it to force its type. It's called (dynamic) casting (more information is here):

$string = "1654"
$integer = [int]$string

$string + 1
# Outputs 16541

$integer + 1
# Outputs 1655

As an example, the following snippet adds, to each object in $fileList, an IntVal property with the integer value of the Name property, then sorts $fileList on this new property (the default is ascending), takes the last (highest IntVal) object's IntVal value, increments it and finally creates a folder named after it:

# For testing purposes
#$fileList = @([PSCustomObject]@{ Name = "11" }, [PSCustomObject]@{ Name = "2" }, [PSCustomObject]@{ Name = "1" })
# OR
#$fileList = New-Object -TypeName System.Collections.ArrayList
#$fileList.AddRange(@([PSCustomObject]@{ Name = "11" }, [PSCustomObject]@{ Name = "2" }, [PSCustomObject]@{ Name = "1" })) | Out-Null

$highest = $fileList |
    Select-Object *, @{ n = "IntVal"; e = { [int]($_.Name) } } |
    Sort-Object IntVal |
    Select-Object -Last 1

$newName = $highest.IntVal + 1

New-Item $newName -ItemType Directory

Sort-Object IntVal is not needed so you can remove it if you prefer.

[int]::MaxValue = 2147483647 so you need to use the [long] type beyond this value ([long]::MaxValue = 9223372036854775807).

Solution 2 - Powershell

Example: >2.032 MB (2,131,022 bytes)

$u=($mbox.TotalItemSize.value).tostring()

$u=$u.trimend(" bytes)") #yields 2.032 MB (2,131,022

$u=$u.Split("(") #yields `$u[1]` as 2,131,022

$uI=[int]$u[1]

The result is 2131022 in integer form.

Solution 3 - Powershell

Use:

$filelist = @(11, 1, 2)
$filelist | sort @{expression={$_[0]}} | 
  % {$newName = [string]([int]$($_[0]) + 1)}
  New-Item $newName -ItemType Directory

Solution 4 - Powershell

Use:

$filelist = @("11", "1", "2")
$filelist | sort @{expression={[int]$_}} | % {$newName = [string]([int]$_ + 1)}
New-Item $newName -ItemType Directory

Solution 5 - Powershell

Once you have selected the highest value, which is "12" in my example, you can then declare it as integer and increment your value:

$FileList = "1", "2", "11"
$foldername = [int]$FileList[2] + 1
$foldername

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionSuman GhoshView Question on Stackoverflow
Solution 1 - PowershellsodawillowView Answer on Stackoverflow
Solution 2 - PowershelltitantooView Answer on Stackoverflow
Solution 3 - PowershellSunny WongView Answer on Stackoverflow
Solution 4 - PowershellSunny WongView Answer on Stackoverflow
Solution 5 - PowershellkekimianView Answer on Stackoverflow