How to convert an Object {} to an Array [] of key-value pairs in JavaScript

JavascriptArraysType Conversion

Javascript Problem Overview


I want to convert an object like this:

{"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

into an array of key-value pairs like this:

[[1,5],[2,7],[3,0],[4,0]...].

How can I convert an Object to an Array of key-value pairs in JavaScript?

Javascript Solutions


Solution 1 - Javascript

You can use Object.keys() and map() to do this

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.keys(obj).map((key) => [Number(key), obj[key]]);

console.log(result);

Solution 2 - Javascript

The best way is to do:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.entries(obj);

console.log(result);

Calling entries, as shown here, will return [key, value] pairs, as the caller requested.

Alternatively, you could call Object.values(obj), which would return only values.

Solution 3 - Javascript

> Object.entries() returns an array whose elements are arrays corresponding to the enumerable property [key, value] pairs found directly upon object. The ordering of the properties is the same as that given by looping over the property values of the object manually. > > - https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/entries#Description</sup>

The Object.entries function returns almost the exact output you're asking for, except the keys are strings instead of numbers.

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

console.log(Object.entries(obj));

If you need the keys to be numbers, you could map the result to a new array with a callback function that replaces the key in each pair with a number coerced from it.

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const toNumericPairs = input => {
    const entries = Object.entries(input);
    return entries.map(entry => Object.assign(entry, { 0: +entry[0] }));
}

console.log(toNumericPairs(obj));

I use an arrow function and Object.assign for the map callback in the example above so that I can keep it in one instruction by leveraging the fact that Object.assign returns the object being assigned to, and a single instruction arrow function's return value is the result of the instruction.

This is equivalent to:

entry => {
    entry[0] = +entry[0];
    return entry;
}

As mentioned by @TravisClarke in the comments, the map function could be shortened to:

entry => [ +entry[0], entry[1] ]

However, that would create a new array for each key-value pair, instead of modifying the existing array in place, hence doubling the amount of key-value pair arrays created. While the original entries array is still accessible, it and its entries will not be garbage collected.

Now, even though using our in-place method still uses two arrays that hold the key-value pairs (the input and the output arrays), the total number of arrays only changes by one. The input and output arrays aren't actually filled with arrays, but rather references to arrays and those references take up a negligible amount of space in memory.

  • Modifying each key-value pair in-place results in a negligible amount of memory growth, but requires typing a few more characters.
  • Creating a new array for each key-value pair results in doubling the amount of memory required, but requires typing a few less characters.

You could go one step further and eliminate growth altogether by modifying the entries array in-place instead of mapping it to a new array:

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const toNumericPairs = input => {
  const entries = Object.entries(obj);
  entries.forEach(entry => entry[0] = +entry[0]);
  return entries;
}

console.log(toNumericPairs(obj));

Solution 4 - Javascript

To recap some of these answers now on 2018, where ES6 is the standard.

Starting with the object:

let const={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
  • Just blindly getting the values on an array, do not care of the keys:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.values(obj));
//[9,8,7,6,5,4,3,2,1,0,5]

  • Simple getting the pairs on an array:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj));
//[["1",9],["2",8],["3",7],["4",6],["5",5],["6",4],["7",3],["8",2],["9",1],["10",0],["12",5]]

  • Same as previous, but with numeric keys on each pair:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj).map(([k,v])=>[+k,v]));
//[[1,9],[2,8],[3,7],[4,6],[5,5],[6,4],[7,3],[8,2],[9,1],[10,0],[12,5]]

  • Using the object property as key for a new array (could create sparse arrays):

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj).reduce((ini,[k,v])=>(ini[k]=v,ini),[]));
//[undefined,9,8,7,6,5,4,3,2,1,0,undefined,5]

This last method, it could also reorganize the array order depending the value of keys. Sometimes this could be the desired behaviour (sometimes don't). But the advantage now is that the values are indexed on the correct array slot, essential and trivial to do searches on it.

  • Map instead of Array

Finally (not part of the original question, but for completeness), if you need to easy search using the key or the value, but you don't want sparse arrays, no duplicates and no reordering without the need to convert to numeric keys (even can access very complex keys), then array (or object) is not what you need. I will recommend Map instead:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map

let r=new Map(Object.entries(obj));
r.get("4"); //6
r.has(8); //true

Solution 5 - Javascript

In Ecmascript 6,

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

var res = Object.entries(obj);

console.log(res);

var obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};
var res = Object.entries(obj);
console.log(res);

Solution 6 - Javascript

Yet another solution if Object.entries won't work for you.

const obj = {
      '1': 29,
      '2': 42
    };
const arr = Array.from(Object.keys(obj), k=>[`${k}`, obj[k]]);
console.log(arr);

Solution 7 - Javascript

I would suggest this simplest solution to use Object.entries()

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result =Object.entries(obj)

console.log(result);

Solution 8 - Javascript

Use Object.keys and Array#map methods.

var obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};
// get all object property names
var res = Object.keys(obj)
  // iterate over them and generate the array
  .map(function(k) {
    // generate the array element 
    return [+k, obj[k]];
  });

console.log(res);

Solution 9 - Javascript

Use Object.entries to get each element of Object in key & value format, then map through them like this:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

var res = Object.entries(obj).map(([k, v]) => ([Number(k), v]));

console.log(res);

But, if you are certain that the keys will be in progressive order you can use Object.values and Array#map to do something like this:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}; 

                        // idx is the index, you can use any logic to increment it (starts from 0)
let result = Object.values(obj).map((e, idx) => ([++idx, e]));

console.log(result);

Solution 10 - Javascript

You can use Object.values([]), you might need this polyfill if you don't already:

const objectToValuesPolyfill = (object) => {
  return Object.keys(object).map(key => object[key]);
};
Object.values = Object.values || objectToValuesPolyfill;

https://stackoverflow.com/a/54822153/846348

Then you can just do:

var object = {1: 'hello', 2: 'world'};
var array = Object.values(object);

Just remember that arrays in js can only use numerical keys so if you used something else in the object then those will become `0,1,2...x``

It can be useful to remove duplicates for example if you have a unique key.

var obj = {};
object[uniqueKey] = '...';

Solution 11 - Javascript

With lodash, in addition to the answer provided above, you can also have the key in the output array.

Without the object keys in the output array

for:

const array = _.values(obj);

If obj is the following:

{ “art”: { id: 1,  title: “aaaa” }, “fiction”: { id: 22,  title: “7777”} }

Then array will be:

[ { id: 1, title: “aaaa” }, { id: 22, title: “7777” } ]

With the object keys in the output array

If you write instead ('genre' is a string that you choose):

const array= _.map(obj, (val, id) => {
    return { ...val, genre: key };
  });

You will get:

[ 
  { id: 1, title: “aaaa” , genre: “art”}, 
  { id: 22, title: “7777”, genre: “fiction” }
]

Solution 12 - Javascript

If you are using lodash, it could be as simple as this:

var arr = _.values(obj);

Solution 13 - Javascript

var obj = { "1": 5, "2": 7, "3": 0, "4": 0, "5": 0, "6": 0, "7": 0, "8": 0, "9": 0, "10": 0, "11": 0, "12": 0 }
let objectKeys = Object.keys(obj);

let answer = objectKeys.map(value => {
    return [value + ':' + obj[value]]
});

Solution 14 - Javascript

>This is my solution, i have the same issue and its seems like this solution work for me.

yourObj = [].concat(yourObj);

Solution 15 - Javascript

This is my simple barebone implementation:

let obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};    

const objectToArray = obj => {
      let sol = [];
      for (key in obj) {
        sol.push([key, obj[key]]);
      }
      return sol;
    };

objectToArray(obj)

Solution 16 - Javascript

Here is a "new" way with es6 using the spread operator in conjunction with Object.entries.

const data = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const dataSpread = [...Object.entries(data)];

// data spread value is now:
[  [ '1', 5 ],  [ '2', 7 ],
  [ '3', 0 ],  [ '4', 0 ],
  [ '5', 0 ],  [ '6', 0 ],
  [ '7', 0 ],  [ '8', 0 ],
  [ '9', 0 ],  [ '10', 0 ],
  [ '11', 0 ], [ '12', 0 ]
]

Solution 17 - Javascript

Use for in

var obj = { "10":5, "2":7, "3":0, "4":0, "5":0, "6":0, "7":0,
            "8":0, "9":0, "10":0, "11":0, "12":0 };

var objectToArray = function(obj) {
    var _arr = [];

    for (var key in obj) {
        _arr.push([key, obj[key]]);
    }
    return _arr;
}

console.log(objectToArray(obj));

Solution 18 - Javascript

Recursive convert object to array

function is_object(mixed_var) {
    if (mixed_var instanceof Array) {
        return false;
    } else {
        return (mixed_var !== null) && (typeof( mixed_var ) == 'object');
    }
}


function objectToArray(obj) {
    var array = [], tempObject;
    for (var key in obj) {

        tempObject = obj[key];

        if (is_object(obj[key])) {
            tempObject = objectToArray(obj[key]);
        }
        array[key] = tempObject;
    }
    return array;
}

Solution 19 - Javascript

We can change Number to String type for Key like below:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.keys(obj).map(function(key) {
  return [String(key), obj[key]];
});
    
console.log(result);

Solution 20 - Javascript

const persons = { 
    john: { age: 23, year:2010},
    jack: { age: 22, year:2011},
    jenny: { age: 21, year:2012}
}
const resultArray = Object.keys(persons).map(index => {
    let person = persons[index];
    return person;
});

//use this for not indexed object to change array

Solution 21 - Javascript

you can use _.castArray(obj).

example:

_.castArray({ 'a': 1 });
// => [{ 'a': 1 }]

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionSoptareanu AlexView Question on Stackoverflow
Solution 1 - JavascriptNenad VracarView Answer on Stackoverflow
Solution 2 - JavascriptPilaView Answer on Stackoverflow
Solution 3 - Javascriptuser4639281View Answer on Stackoverflow
Solution 4 - JavascriptCarlosH.View Answer on Stackoverflow
Solution 5 - JavascriptNageshwar Reddy PandemView Answer on Stackoverflow
Solution 6 - Javascriptbigh_29View Answer on Stackoverflow
Solution 7 - JavascriptIrony StackView Answer on Stackoverflow
Solution 8 - JavascriptPranav C BalanView Answer on Stackoverflow
Solution 9 - JavascriptBlackBeardView Answer on Stackoverflow
Solution 10 - JavascriptOZZIEView Answer on Stackoverflow
Solution 11 - JavascriptYossiView Answer on Stackoverflow
Solution 12 - JavascriptAdam BoostaniView Answer on Stackoverflow
Solution 13 - JavascriptMuhammad ShaeelView Answer on Stackoverflow
Solution 14 - JavascriptQui-Gon JinnView Answer on Stackoverflow
Solution 15 - JavascriptKetan RamtekeView Answer on Stackoverflow
Solution 16 - Javascriptbrff19View Answer on Stackoverflow
Solution 17 - JavascriptwkynistonView Answer on Stackoverflow
Solution 18 - JavascriptMarina LebedevaView Answer on Stackoverflow
Solution 19 - JavascriptNagnath MungadeView Answer on Stackoverflow
Solution 20 - JavascriptKATHEESKUMARView Answer on Stackoverflow
Solution 21 - JavascriptChopper LeeView Answer on Stackoverflow