How to convert an H:MM:SS time string to seconds in Python?
PythonPython Problem Overview
Basically I have the inverse of this problem: Python Time Seconds to h:m:s
I have a string in the format H:MM:SS (always 2 digits for minutes and seconds), and I need the integer number of seconds that it represents. How can I do this in python?
For example:
- "1:23:45" would produce an output of 5025
- "0:04:15" would produce an output of 255
- "0:00:25" would produce an output of 25
etc
Python Solutions
Solution 1 - Python
def get_sec(time_str):
"""Get seconds from time."""
h, m, s = time_str.split(':')
return int(h) * 3600 + int(m) * 60 + int(s)
print(get_sec('1:23:45'))
print(get_sec('0:04:15'))
print(get_sec('0:00:25'))
Solution 2 - Python
ts = '1:23:45'
secs = sum(int(x) * 60 ** i for i, x in enumerate(reversed(ts.split(':'))))
print(secs)
Solution 3 - Python
Using datetime module
import datetime
t = '10:15:30'
h,m,s = t.split(':')
print(int(datetime.timedelta(hours=int(h),minutes=int(m),seconds=int(s)).total_seconds()))
Output: 36930
Solution 4 - Python
Without many checks, and assuming it's either "SS" or "MM:SS" or "HH:MM:SS" (although not necessarily two digits per part):
def to_seconds(timestr):
seconds= 0
for part in timestr.split(':'):
seconds= seconds*60 + int(part, 10)
return seconds
>>> to_seconds('09')
9
>>> to_seconds('2:09')
129
>>> to_seconds('1:02:09')
3729
This is a different “spelling” of FMc's answer :)
Solution 5 - Python
Using datetime
module is also posible and more robust
import datetime as dt
def get_total_seconds(stringHMS):
timedeltaObj = dt.datetime.strptime(stringHMS, "%H:%M:%S") - dt.datetime(1900,1,1)
return timedeltaObj.total_seconds()
datetime.strptime
parses the string according to format %H:%M:%S, and it creates a datetime object as year 1900, month1, day 1, hour H, minute M, and second S.
That's why to get the total of seconds is necessary to subtract the year, month and day.
print(get_total_seconds('1:23:45'))
>>> 5025.0
print(get_total_seconds('0:04:15'))
>>> 255.0
print(get_total_seconds('0:00:25'))
>>>25.0
Solution 6 - Python
You can use lambda and reduce a list and the fact that m=60s and h=60m. (see "Reducing a List" at http://www.python-course.eu/lambda.php)
timestamp = "1:23:45"
seconds = reduce(lambda x, y: x*60+y, [int(i) for i in (timestamp.replace(':',',')).split(',')])
Solution 7 - Python
You can split the time into a list and add each individual time component, multiplying the hours component by 3600 (the number of seconds in an hour) and the minutes component by 60 (number of seconds in a minute), like:
timeInterval ='00:35:01'
list = timeInterval.split(':')
hours = list[0]
minutes = list[1]
seconds = list[2]
total = (int(hours) * 3600 + int(minutes) * 60 + int(seconds))
print("total = ", total)
Solution 8 - Python
For %H:%M:%S.%f
def get_sec(time_str):
h, m, s = time_str.split(':')
return int(h) * 3600 + int(m) * 60 + float(s)
Solution 9 - Python
parts = time_string.split(":")
seconds = int(parts[0])*(60*60) + int(parts[1])*60 + int(parts[2])
Solution 10 - Python
I didn't really like any of the given answers, so I used the following:
def timestamp_to_seconds(t):
return sum(float(n) * m for n,
m in zip(reversed(time.split(':')), (1, 60, 3600))
)
Solution 11 - Python
Expanding on @FMc's solution which embodies half of Horner's method. Advantage of Horner's method: Skip reversing the list, avoid power calculation.
from functools import reduce
timestamp = "1:23:45"
seconds = reduce(lambda s, d: s * 60 + int(d), timestamp.split(":"), 0)
or, if you dislike reduce (as does Guido van Rossum and @0xc0de below):
timestamp = "1:23:45"
seconds = 0
for d in timestamp.split(":"):
seconds = seconds * 60 + int(d)
If you prefer zip (as does @nathan-rice below):
from itertools import accumulate, repeat
from operator import mul
def timestamp_to_seconds(t):
return sum(int(n) * m for n, m in
zip(reversed(t.split(":")), accumulate(repeat(60), func=mul, initial=1)))
Solution 12 - Python
Another alternative if you have days on string:
def duration2sec(string):
if "days" in string:
days = string.split()[0]
hours = string.split()[2].split(':')
return int(days) * 86400 + int(hours[0]) * 3600 + int(hours[1]) * 60 + int(hours[2])
else:
hours = string.split(':')
return int(hours[0]) * 3600 + int(hours[1]) * 60 + int(hours[2])
Solution 13 - Python
Just a simple generalization to the great response of taskinoor
In the context of my problem the format is similar, but includes AM or PM.
Format 'HH:MM:SS AM' or 'HH:MM:SS PM'
For this case the function changes to:
def get_sec(time_str):
"""Get Seconds from time."""
if 'AM' in time_str:
time_str = time_str.strip('AM')
h, m, s = time_str.split(':')
seconds = int(h) * 3600 + int(m) * 60 + int(s)
if 'PM' in time_str:
time_str = time_str.strip('PM')
h, m, s = time_str.split(':')
seconds = (12 + int(h)) * 3600 + int(m) * 60 + int(s)
return seconds
Solution 14 - Python
In Pandas using @JayRizzo 's cool function and a list comprehension:
def get_sec(time_str):
"""Get Seconds from time."""
h, m, s = time_str.split(':')
return int(h) * 3600 + int(m) * 60 + int(s)
df['secs']=[get_sec(x) for x in df['original_time_string']]