JavaScript has a `Number` type which is a 64 bit floating point number*. 

If you&#39;re looking to convert a string to a number, use 

1. either [`parseInt`][1] or [`parseFloat`][2]. If using `parseInt`, I&#39;d recommend always passing the radix too.
2. use the Unary `+` operator e.g. `+&quot;123456&quot;`
3. use the `Number` constructor e.g. `var n = Number(&quot;12343&quot;)`

**there are situations where the number will internally be held as an integer.*


  [1]: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/parseInt
  [2]: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/parseFloat

`BigInt(&quot;1274836528318476135&quot;)`

I understand exactly why unused variable warnings occur. I don&#39;t want to suppress them in general, because they are incredibly useful in most cases. However, consider the following (contrived) code.

    NSError *error = nil;
    BOOL saved = [moc save:&amp;error];
    NSAssert1(saved, @&quot;Dude!!1! %@!!!&quot;, error);

Xcode reports that `saved` is an unused variable, when of course it isn&#39;t. I suspect this is because `NSAssert1` is a macro. The `NS_BLOCK_ASSERTIONS` macro is _not_ defined, so Objective C assertions are definitely enabled.

While it doesn&#39;t hurt anything, I find it untidy and annoying, and I want to suppress it, but I&#39;m not sure how to do so. Assigning the variable to itself gets rid of the compiler warning, but I&#39;d rather do it the &quot;right&quot; way if such a thing exists.

How can I get rid of an &quot;unused variable&quot; warning in Xcode?

I can&#39;t seem to figure out how to setup a &quot;default&quot; logger for my Django installation. I would like to use Django 1.3&#39;s new `LOGGING` setting in `settings.py`.

I&#39;ve looked at the [Django Logging Doc&#39;s example](https://docs.djangoproject.com/en/2.0/topics/logging/#examples), but it looks to me like they only setup handlers which will do logging for particular loggers. In the case of their example they setup handler for the loggers named &#39;django&#39;,&#39;django.request&#39;, and &#39;myproject.custom&#39;.

All I want to do is setup a default `logging.handlers.RotatingFileHandler` which will handle all loggers by default. i.e., if I make a new module somewhere in my project and it is denoted by something like: `my_app_name.my_new_module`, I should be able to do this and have all logging goto the rotating file logs.

    # In file &#39;./my_app_name/my_new_module.py&#39;
    import logging
    logger = logging.getLogger(&#39;my_app_name.my_new_module&#39;)
    logger.debug(&#39;Hello logs!&#39;) # &lt;-- This should get logged to my RotatingFileHandler that I setup in `settings.py`!

Django Setup Default Logging

I have a millisecond timestamp that I need to convert from a string to long. JavaScript has a `parseInt` but not a `parseLong`. So how can I do this?

To expand on my question slightly: given that apparently JavaScript doesn&#39;t have a long type, how can I do simple arithmetic with longs that are initially expressed as strings? E.g subtract one from the other to get a time delta?

How to convert a String to long in javascript?

<p>I have a millisecond timestamp that I need to convert from a string to long. JavaScript has a <code>parseInt</code> but not a <code>parseLong</code>. So how can I do this?</p>
<p>To expand on my question slightly: given that apparently JavaScript doesn't have a long type, how can I do simple arithmetic with longs that are initially expressed as strings? E.g subtract one from the other to get a time delta?</p>


If unary `+`/`-` operators are used to perform conversions as the `Number()` casting function, then why do we need unary operators? What&#39;s the special need of these unary operators? 

What&#39;s the significant use of unary plus and minus operators?

I have some JavaScript code in an HTML page with a button. I have a function called `click()` that handles the `onClick` event of the button. The code for the button is as follows:  

    &lt;input type=&quot;button&quot; onClick=&quot;click()&quot;&gt;button text&lt;/input&gt;  

The problem is that when the button is clicked, the function is not called. What am I doing wrong here?  


onclick event function in JavaScript

I&#39;m not very good with string manipulation in JavaScript, and I was wondering how you would go about shortening a string without cutting any word off. I know how to use substring, but not indexOf or anything really well.

	
Say I had the following string:

    text = &quot;this is a long string I cant display&quot;

I want to trim it down to 10 characters, but if it doesn&#39;t end with a space, finish the word. I don&#39;t want the string variable to look like this:

&gt; &quot;this is a long string I cant dis&quot;

I want it to finish the word until a space occurs.






Shorten string without cutting words in JavaScript

How can I use a condition inside a switch statement for JavaScript?
In the example below, a case should match when the variable `liCount` is `&lt;= 5` and `&gt; 0`; however, my code does not work:

```
switch (liCount) {
  case 0:
    setLayoutState(&quot;start&quot;);
    var api = $(&quot;#UploadList&quot;).data(&quot;jsp&quot;);
    api.reinitialise();
    break;
  case liCount &lt;= 5 &amp;&amp; liCount &gt; 0:
    setLayoutState(&quot;upload1Row&quot;);
    var api = $(&quot;#UploadList&quot;).data(&quot;jsp&quot;);
    api.reinitialise();
    break;
  case liCount &lt;= 10 &amp;&amp; liCount &gt; 5:
    setLayoutState(&quot;upload2Rows&quot;);
    var api = $(&quot;#UploadList&quot;).data(&quot;jsp&quot;);
    api.reinitialise();
    break;
  case liCount &gt; 10:
    var api = $(&quot;#UploadList&quot;).data(&quot;jsp&quot;);
    api.reinitialise();
    break;
  default:
    break;
}
```

Appreciate any advice!

JavaScript: using a condition in switch case

I know there are a lot of regex threads out there by I need a specific pattern I couldn&#39;t fin anywhere 

This regex validates in a YYYY-MM-DD format 

    /^\d{4}[\/\-](0?[1-9]|1[012])[\/\-](0?[1-9]|[12][0-9]|3[01])$/

I need the pattern to be DD/MM/YYYY
(day first since it&#39;s in spanish and only &quot;/&quot;, &quot;-&quot; should not be allowed)

I searched several regex libraries and I think this one should work... but since I&#39;m not familiar with regex I&#39;m not sure it validates like that

    (0[1-9]|[12][0-9]|3[01])[ \.-](0[1-9]|1[012])[ \.-](19|20|)\d\d


I also don&#39;t know ho to escape the slashes, I try to &quot;see&quot; the logic in the string but it&#39;s like trying &quot;see&quot; the Matrix code for me. I&#39;m placing the regex string in a options .js
 

    [...]  },
    &quot;date&quot;: {
                        &quot;regex&quot;: (0[1-9]|[12][0-9]|3[01])[ \.-](0[1-9]|1[012])[ \.-](19|20|)\d\d,
                        &quot;alertText&quot;: &quot;Alert text AAAA-MM-DD&quot;
                    },
    &quot;other type...&quot;[...]

So, if the regex is ok, how would I escape it? 
if it&#39;s not, what&#39;s the correct regex and how do I escape it? :P

Thanks a lot

Javascript date regex DD/MM/YYYY

What&#39;s the simplest way to get the String representation of a XML Document (`org.w3c.dom.Document`)? That is all nodes will be on a single line.

As an example, from

    &lt;root&gt;
      &lt;a&gt;trge&lt;/a&gt;
      &lt;b&gt;156&lt;/b&gt;
    &lt;/root&gt;

(this is only a tree representation, in my code it&#39;s a `org.w3c.dom.Document` object, so I can&#39;t treat it as a String)

to

    &quot;&lt;root&gt; &lt;a&gt;trge&lt;/a&gt; &lt;b&gt;156&lt;/b&gt; &lt;/root&gt;&quot;

Thanks!

XML Document to String

How do I remove a character from a string?  

If I have the string `&quot;abcdef&quot;` and I want to remove `&quot;b&quot;` how do I do that?

Removing the **first** character is easy with this code:

    #include &lt;stdio.h&gt;
    #include &lt;stdlib.h&gt;
    #include &lt;string.h&gt;

    int main()
    {
       char word[] = &quot;abcdef&quot;;
       char word2[10];
   
       strcpy(word2,&amp;word[1]);
   
       printf(&quot;%s\n&quot;, word2);
     
       return 0;
    }

and

    strncpy(word2,word,strlen(word)-1);

will give me the string without the **last** character, but I still didn&#39;t figure out how to remove a char in the **middle** of a string.

How to remove the character at a given index from a string in C?

Non-working example:

    print(&quot; \{ Hello \} {0} &quot;.format(42))

Desired output:

```none
 {Hello} 42 
```

How do I print curly-brace characters in a string while using .format?

&lt;!-- language: lang-python --&gt;

    plaintext = input(&quot;Please enter the text you want to compress&quot;)
    filename = input(&quot;Please enter the desired filename&quot;)
    with gzip.open(filename + &quot;.gz&quot;, &quot;wb&quot;) as outfile:
        outfile.write(plaintext) 

The above python code is giving me following error:

&lt;!-- language: lang-none --&gt;

    Traceback (most recent call last):
      File &quot;C:/Users/Ankur Gupta/Desktop/Python_works/gzip_work1.py&quot;, line 33, in &lt;module&gt;
        compress_string()
      File &quot;C:/Users/Ankur Gupta/Desktop/Python_works/gzip_work1.py&quot;, line 15, in compress_string
        outfile.write(plaintext)
      File &quot;C:\Python32\lib\gzip.py&quot;, line 312, in write
        self.crc = zlib.crc32(data, self.crc) &amp; 0xffffffff
    TypeError: &#39;str&#39; does not support the buffer interface


TypeError: &#39;str&#39; does not support the buffer interface

How could i convert data from string to long in C#?

I have data 

    String strValue[i] =&quot;1100.25&quot;;

now i want it in

    long l1;

How could I convert data from string to long in c#

I&#39;m doing a program that aproximate PI and i&#39;m trying to use long long, but it isn&#39;t working.
Here is the code

    #include&lt;stdio.h&gt;
    #include&lt;math.h&gt;
    typedef long long num;
    main(){
        num pi;
        pi=0;
        num e, n;
        scanf(&quot;%d&quot;, &amp;n);
        for(e=0; 1;e++){
          pi += ((pow((-1.0),e))/(2.0*e+1.0));
          if(e%n==0)
            printf(&quot;%15lld -&gt; %1.16lld\n&quot;,e, 4*pi);
          //printf(&quot;%lld\n&quot;,4*pi);
        }
    }



How to printf long long

[Primitive Data Types - oracle doc][1] says the range of **`long`** in Java is `-9,223,372,036,854,775,808` to `9,223,372,036,854,775,807`.
But when I do something like this in my eclipse

    long i = 12345678910;

it shows me &quot;`The literal 12345678910 of type int is out of range`&quot; error.

**There are 2 questions.**

1) How do I initialize the **`long`** with the value `12345678910`?

2) Are all numeric literals by default of type **`int`**? 


  [1]: http://download.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Initialize a long in Java

I am working with data types at the moment in Java, and if I have understood correctly the type `long` accepts a value between the ranges of -9,223,372,036,854,775,808 to +9,223,372,036,854,775,807. Now as you can see below, I have create a `long` variable called `testLong`, although when I insert 9223372036854775807 as the value, I get an error stating:

&gt; The literal 9223372036854775807  of the type int is out of range.

I don&#39;t know why it is referring to the `long` data type as an `int`.

Anyone have any ideas?

Code:

```
char testChar = 01;
byte testByte = -128;
int testInt = -2147483648;
short testShort = -32768;
long testLong = 9223372036854775807;
float testFoat;
double testDouble = 4.940656458412;
boolean testBool = true;
```

The literal xyz of type int is out of range

This is a basic question but I can&#39;t find an answer.  I&#39;ve looked into floating point arithmetic and a few other topics but nothing has seemed to address this.  I&#39;m sure I just have the wrong terminology.

Basically, I want to take two quantities - completed, and total - and divide them to come up with a percentage (of how much has been completed).  The quantities are `long`s.  Here&#39;s the setup:

    long completed = 25000;
    long total = 50000;

    System.out.println(completed/total);  // Prints 0

I&#39;ve tried reassigning the result to a double - it prints `0.0`.  Where am I going wrong?

Incidentally, the next step is to multiply this result by 100, which I assume should be easy once this small hurdle is stepped over.

BTW not homework here just plain old numskull-ness (and maybe too much coding today).

Division of integers in Java

How to sort the files according to the time stamp in unix?
I need to sort the files and also based on time they created.

How to sort the files according to the time stamp in unix?

Is there a MySQL function which can be used to convert a Unix timestamp into a human readable date? I have one field where I save Unix times and now I want to add another field for human readable dates.

Convert Unix timestamp into human readable date using MySQL

I&#39;m using the Mongo shell to query my Mongo db.  I want to use the timestamp contained in the ObjectID as part of my query and also as a column to extract into output.  I have setup Mongo to create ObjectIDs on its own.

My problem is I can not find out how to work with the ObjectID to extract its timestamp.

Here are the queries I am trying to get working.  The &#39;createdDate&#39; field is a placeholder; not sure what the correct field is:

    //Find everything created since 1/1/2011
    db.myCollection.find({date: {$gt: new Date(2011,1,1)}});
    
    //Find everything and return their createdDates
    db.myCollection.find({},{createdDate:1});

How do I extract the created date out of a Mongo ObjectID

I have an X.509 certificate which has the following 2 timestamps:

    [&#39;validFrom&#39;] = String(13) &quot;120314165227Z&quot;
    [&#39;validTo&#39;]   = String(13) &quot;130314165227Z&quot;

What does the postfix character &#39;Z&#39; mean. Does it specify the timezone?

What does the &#39;Z&#39; mean in Unix timestamp &#39;120314170138Z&#39;?

Using PHP, I want to convert UNIX timestamps to date strings similar to this: `2008-07-17T09:24:17Z`

How do I convert a timestamp such as `1333699439` to `2008-07-17T09:24:17Z`?

Content Type	Original Author	Original Content on Stackoverflow
Question	Richard H	View Question on Stackoverflow
Solution 1 - Javascript	Russ Cam	View Answer on Stackoverflow
Solution 2 - Javascript	Jamey	View Answer on Stackoverflow

How to convert a String to long in javascript?

Javascript Problem Overview

Javascript Solutions

Solution 1 - Javascript

Solution 2 - Javascript

Django Setup Default Logging

How can I get rid of an "unused variable" warning in Xcode?

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