How to check the validity of a remote git repository URL?

Within a bash script, what would be the simplest way to verify that a git URL points to a valid git repo and that the script has access to read from it?

Protocols that should be supported are git@, https://, and git://. Curl fails on the git:// protocol.

git@github.com:UserName/Example.git
https://UserName@github.com/UserName/Example.git
git://github.com/UserName/Example.git

Note: I'm not asking to check to see if a URL is syntactically correct, I need to verify that a repo exists at the URL location entered from within a bash script.

As seen in this issue, you can use git ls-remote to test your address.

> If you need to debug the git calls set GIT_TRACE=1. eg:

env GIT_PROXY_COMMAND=myproxy.sh GIT_TRACE=1 git ls-remote https://...

> "git ls-remote" is the quickest way I know to test communications with a remote repository without actually cloning it. Hence its utility as a test for this issue.

You can see it used for detecting an address issue in "git ls-remote returns 128 on any repo".

Although VonC's answer is correct, here's what I ended up using:

git ls-remote will return information about a repository, by default this is HEAD, all branches and tags, along with the commit ID for each entry. e.g.:

$ git ls-remote git://github.com/user/repo.git
<commit id>    HEAD
<commit id>    refs/heads/example_branch
<commit id>    refs/heads/master
<commit id>    refs/tags/v1.0.2
<commit id>    refs/tags/v1.0.0

git ls-remote returns code 0 on success, error code 128 on failure.

If the repo is unreachable, for example, if you don't have permission to view the repository, or if a repository doesn't exist at that location, git ls-remote will return:

fatal: The remote end hung up unexpectedly

To use this in a bash script, the following will work...

git ls-remote "$SITE_REPO_URL" > /dev/null 2>&1
if [ "$?" -ne 0 ]; then
    echo "[ERROR] Unable to read from '$SITE_REPO_URL'"
    exit 1;
fi

(Note: The > /dev/null 2>&1 silences stderr and stdout, so the command won't output anything)