How to check if $_GET is empty?
PhpGetPhp Problem Overview
How to check if $_GET is empty?
Php Solutions
Solution 1 - Php
You said it yourself, check that it's empty:
if (empty($_GET)) {
// no data passed by get
}
See, PHP is so straightforward. You may simply write, what you think ;)
This method is quite secure. !$_GET could give you an undefined variable E_NOTICE if $_GET was unset (not probable, but possible).
Solution 2 - Php
i guess the simplest way which doesn't require any operators is
if($_GET){
//do something if $_GET is set
}
if(!$_GET){
//do something if $_GET is NOT set
}
Solution 3 - Php
Just to provide some variation here: You could check for
if ($_SERVER["QUERY_STRING"] == null)
it is completely identical to testing $_GET.
Solution 4 - Php
<?php
if (!isset($_GET) || empty($_GET))
{
// do stuff here
}
Solution 5 - Php
if (!$_GET) echo "empty";
why do you need such a checking?
lol
you guys too direct-minded.
don't take as offense but sometimes not-minded at all
$_GET is very special variable, not like others.
it is supposed to be always set. no need to treat it as other variables.
when $_GET is not set and it's expected - it is emergency case and that's what "Undefined variable" notice invented for
Solution 6 - Php
Easy.
if (empty($_GET)) {
// $_GET is empty
}
Solution 7 - Php
I would use the following if statement because it is easier to read (and modify in the future)
if(!isset($_GET) || !is_array($_GET) || count($_GET)==0) {
// empty, let's make sure it's an empty array for further reference
$_GET=array();
// or unset it
// or set it to null
// etc...
}
Solution 8 - Php
Here are 3 different methods to check this
<?php
//Method 1
if(!empty($_GET))
echo "exist";
else
echo "do not exist";
//Method 2
echo "<br>";
if($_GET)
echo "exist";
else
echo "do not exist";
//Method 3
if(count($_GET))
echo "exist";
else
echo "do not exist";
?>