How to check if a string is a substring of items in a list of strings?
PythonStringListPython Problem Overview
I have a list:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
and want to search for items that contain the string 'abc'
. How can I do that?
if 'abc' in my_list:
would check if 'abc'
exists in the list but it is a part of 'abc-123'
and 'abc-456'
, 'abc'
does not exist on its own. So how can I get all items that contain 'abc'
?
Python Solutions
Solution 1 - Python
If you only want to check for the presence of abc
in any string in the list, you could try
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any("abc" in s for s in some_list):
# whatever
If you really want to get all the items containing abc
, use
matching = [s for s in some_list if "abc" in s]
Solution 2 - Python
Just throwing this out there: if you happen to need to match against more than one string, for example abc
and def
, you can combine two comprehensions as follows:
matchers = ['abc','def']
matching = [s for s in my_list if any(xs in s for xs in matchers)]
Output:
['abc-123', 'def-456', 'abc-456']
Solution 3 - Python
Use filter
to get at the elements that have abc
.
>>> lst = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
>>> print filter(lambda x: 'abc' in x, lst)
['abc-123', 'abc-456']
You can also use a list comprehension.
>>> [x for x in lst if 'abc' in x]
By the way, don't use the word list
as a variable name since it is already used for the list
type.
Solution 4 - Python
If you just need to know if 'abc' is in one of the items, this is the shortest way:
if 'abc' in str(my_list):
Note: this assumes 'abc' is an alphanumeric text. Do not use it if 'abc' could be just a special character (i.e. []', ).
Solution 5 - Python
This is quite an old question, but I offer this answer because the previous answers do not cope with items in the list that are not strings (or some kind of iterable object). Such items would cause the entire list comprehension to fail with an exception.
To gracefully deal with such items in the list by skipping the non-iterable items, use the following:
[el for el in lst if isinstance(el, collections.Iterable) and (st in el)]
then, with such a list:
lst = [None, 'abc-123', 'def-456', 'ghi-789', 'abc-456', 123]
st = 'abc'
you will still get the matching items (['abc-123', 'abc-456']
)
The test for iterable may not be the best. Got it from here: https://stackoverflow.com/questions/1952464/in-python-how-do-i-determine-if-a-variable-is-iterable
Solution 6 - Python
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]
Solution 7 - Python
for item in my_list:
if item.find("abc") != -1:
print item
Solution 8 - Python
any('abc' in item for item in mylist)
Solution 9 - Python
I am new to Python. I got the code below working and made it easy to understand:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if 'abc' in item:
print(item)
Solution 10 - Python
Use the __contains__()
method of Pythons string class.:
a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for i in a:
if i.__contains__("abc") :
print(i, " is containing")
Solution 11 - Python
If you want to get list of data for multiple substrings
you can change it this way
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element]
# Output ['abc-123', 'ghi-789', 'abc-456']
Solution 12 - Python
I needed the list indices that correspond to a match as follows:
lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']
[n for n, x in enumerate(lst) if 'abc' in x]
output
[0, 3]
Solution 13 - Python
mylist=['abc','def','ghi','abc']
pattern=re.compile(r'abc')
pattern.findall(mylist)
Solution 14 - Python
Adding nan to list, and the below works for me:
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any([i for i in [x for x in some_list if str(x) != 'nan'] if "abc" in i])
Solution 15 - Python
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if (item.find('abc')) != -1:
print ('Found at ', item)
Solution 16 - Python
I did a search, which requires you to input a certain value, then it will look for a value from the list which contains your input:
my_list = ['abc-123',
'def-456',
'ghi-789',
'abc-456'
]
imp = raw_input('Search item: ')
for items in my_list:
val = items
if any(imp in val for items in my_list):
print(items)
Try searching for 'abc'.
Solution 17 - Python
def find_dog(new_ls):
splt = new_ls.split()
if 'dog' in splt:
print("True")
else:
print('False')
find_dog("Is there a dog here?")
Solution 18 - Python
Question : Give the informations of abc
a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
aa = [ string for string in a if "abc" in string]
print(aa)
Output => ['abc-123', 'abc-456']