How to check if a String contains any letter from a to z?

> Possible Duplicate:
> C# Regex: Checking for “a-z” and “A-Z”

I could just use the code below:

String hello = "Hello1";
Char[] convertedString = String.ToCharArray();
int errorCounter = 0;
for (int i = 0; i < CreateAccountPage_PasswordBox_Password.Password.Length; i++) {
	if (convertedString[i].Equals('a') || convertedString[i].Equals('A') .....
	                        || convertedString[i].Equals('z') || convertedString[i].Equals('Z')) {
		errorCounter++;
	}
}
if(errorCounter > 0) {
	//do something
}

but I suppose it takes too much line for just a simple purpose, I believe there is a way which is much more simple, the way which I have not yet mastered.

What about:

//true if it doesn't contain letters
bool result = hello.Any(x => !char.IsLetter(x));

Replace your for loop by this :

errorCounter = Regex.Matches(yourstring,@"[a-zA-Z]").Count;

Remember to use Regex class, you have to using System.Text.RegularExpressions; in your import

You could use RegEx:

Regex.IsMatch(hello, @"^[a-zA-Z]+$");

If you don't like that, you can use LINQ:

hello.All(Char.IsLetter);

Or, you can loop through the characters, and use isAlpha:

Char.IsLetter(character);

You can look for regular expression

Regex.IsMatch(str, @"^[a-zA-Z]+$");

For a minimal change:

for(int i=0; i<str.Length; i++ )
   if(str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z')
      errorCount++;

You could use regular expressions, at least if speed is not an issue and you do not really need the actual exact count.

Use regular expression no need to convert it to char array

if(Regex.IsMatch("yourString",".*?[a-zA-Z].*?"))
{
errorCounter++;
}