How to change the figure size of a seaborn axes or figure level plot
PythonMatplotlibSeabornFigsizePython Problem Overview
How do I change the size of my image so it's suitable for printing?
For example, I'd like to use to A4 paper, whose dimensions are 11.7 inches by 8.27 inches in landscape orientation.
Python Solutions
Solution 1 - Python
You can also set figure size by passing dictionary to rc
parameter with key 'figure.figsize'
in seaborn set
method:
import seaborn as sns
sns.set(rc={'figure.figsize':(11.7,8.27)})
Other alternative may be to use figure.figsize
of rcParams
to set figure size as below:
from matplotlib import rcParams
# figure size in inches
rcParams['figure.figsize'] = 11.7,8.27
More details can be found in matplotlib documentation
Solution 2 - Python
You need to create the matplotlib Figure and Axes objects ahead of time, specifying how big the figure is:
from matplotlib import pyplot
import seaborn
import mylib
a4_dims = (11.7, 8.27)
df = mylib.load_data()
fig, ax = pyplot.subplots(figsize=a4_dims)
seaborn.violinplot(ax=ax, data=df, **violin_options)
Solution 3 - Python
Note that if you are trying to pass to a "figure level" method in seaborn (for example lmplot
, catplot
/ factorplot
, jointplot
) you can and should specify this within the arguments using height
and aspect
.
sns.catplot(data=df, x='xvar', y='yvar',
hue='hue_bar', height=8.27, aspect=11.7/8.27)
See https://github.com/mwaskom/seaborn/issues/488 and https://stackoverflow.com/questions/23969619/plotting-with-seaborn-using-the-matplotlib-object-oriented-interface for more details on the fact that figure level methods do not obey axes specifications.
Solution 4 - Python
first import matplotlib and use it to set the size of the figure
from matplotlib import pyplot as plt
import seaborn as sns
plt.figure(figsize=(15,8))
ax = sns.barplot(x="Word", y="Frequency", data=boxdata)
Solution 5 - Python
You can set the context to be poster
or manually set fig_size
.
import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt
np.random.seed(0)
n, p = 40, 8
d = np.random.normal(0, 2, (n, p))
d += np.log(np.arange(1, p + 1)) * -5 + 10
# plot
sns.set_style('ticks')
fig, ax = plt.subplots()
# the size of A4 paper
fig.set_size_inches(11.7, 8.27)
sns.violinplot(data=d, inner="points", ax=ax)
sns.despine()
fig.savefig('example.png')
Solution 6 - Python
This can be done using:
plt.figure(figsize=(15,8))
sns.kdeplot(data,shade=True)
Solution 7 - Python
In addition to elz answer regarding "figure level" methods that return multi-plot grid objects it is possible to set the figure height and width explicitly (that is without using aspect ratio) using the following approach:
import seaborn as sns
g = sns.catplot(data=df, x='xvar', y='yvar', hue='hue_bar')
g.fig.set_figwidth(8.27)
g.fig.set_figheight(11.7)
Solution 8 - Python
This shall also work.
from matplotlib import pyplot as plt
import seaborn as sns
plt.figure(figsize=(15,16))
sns.countplot(data=yourdata, ...)
Solution 9 - Python
For my plot (a sns factorplot) the proposed answer didn't works fine.
Thus I use
plt.gcf().set_size_inches(11.7, 8.27)
Just after the plot with seaborn (so no need to pass an ax to seaborn or to change the rc settings).
Solution 10 - Python
# Sets the figure size temporarily but has to be set again the next plot
plt.figure(figsize=(18,18))
sns.barplot(x=housing.ocean_proximity, y=housing.median_house_value)
plt.show()
Solution 11 - Python
- Adjusting the size of the plot depends if the plot is a figure-level plot like
seaborn.displot
, or an axes-level plot likeseaborn.histplot
. This answer applies to any figure or axes level plots.- See the the seaborn API reference
seaborn
is a high-level API formatplotlib
, so seaborn works with matplotlib methods- Tested in
python 3.8.12
,matplotlib 3.4.3
,seaborn 0.11.2
Imports and Data
import seaborn as sns
import matplotlib.pyplot as plt
# load data
df = sns.load_dataset('penguins')
sns.displot
- The size of a figure-level plot can be adjusted with the
height
and/oraspect
parameters - Additionally, the
dpi
of the figure can be set by accessing thefig
object and using.set_dpi()
p = sns.displot(data=df, x='flipper_length_mm', stat='density', height=4, aspect=1.5)
p.fig.set_dpi(100)
- Without
p.fig.set_dpi(100)
- With
p.fig.set_dpi(100)
sns.histplot
- The size of an axes-level plot can be adjusted with
figsize
and/ordpi
# create figure and axes
fig, ax = plt.subplots(figsize=(6, 5), dpi=100)
# plot to the existing fig, by using ax=ax
p = sns.histplot(data=df, x='flipper_length_mm', stat='density', ax=ax)
- Without
dpi=100
- With
dpi=100
Solution 12 - Python
The top answers by Paul H and J. Li do not work for all types of seaborn figures. For the FacetGrid
type (for instance sns.lmplot()
), use the size
and aspect
parameter.
Size
changes both the height and width, maintaining the aspect ratio.
Aspect
only changes the width, keeping the height constant.
You can always get your desired size by playing with these two parameters.
Solution 13 - Python
Some tried out ways:
import seaborn as sns
import matplotlib.pyplot as plt
ax, fig = plt.subplots(figsize=[15,7])
sns.boxplot(x="feature1", y="feature2",data=df) # where df would be your dataframe
or
import seaborn as sns
import matplotlib.pyplot as plt
plt.figure(figsize=[15,7])
sns.boxplot(x="feature1", y="feature2",data=df) # where df would be your dataframe