How to change figuresize using seaborn factorplot
PythonMatplotlibSeabornPython Problem Overview
%pylab inline
import pandas as pd
import numpy as np
import matplotlib as mpl
import seaborn as sns
typessns = pd.DataFrame.from_csv('C:/data/testesns.csv', index_col=False, sep=';')
mpl.rc("figure", figsize=(45, 10))
sns.factorplot("MONTH", "VALUE", hue="REGION", data=typessns, kind="box", palette="OrRd");
I always get a small size figure, no matter what size I 've specified in figsize... How to fix it?
Python Solutions
Solution 1 - Python
> Note added in 2019: In modern seaborn versions the size
argument has been renamed to height
.
To be a little more concrete:
%matplotlib inline
import seaborn as sns
exercise = sns.load_dataset("exercise")
# Defaults are size=5, aspect=1
sns.factorplot("kind", "pulse", "diet", exercise, kind="point", size=2, aspect=1)
sns.factorplot("kind", "pulse", "diet", exercise, kind="point", size=4, aspect=1)
sns.factorplot("kind", "pulse", "diet", exercise, kind="point", size=4, aspect=2)
You want to pass in the arguments 'size' or 'aspect' to the sns.factorplot() when constructing your plot.
Size will change the height, while maintaining the aspect ratio (so it will also also get wider if only size is changed.)
Aspect will change the width while keeping the height constant.
The above code should be able to be run locally in an ipython notebook.
Plot sizes are reduced in these examples to show the effects, and because the plots from the above code were fairly large when saved as png's. This also shows that size/aspect includes the legend in the margin.
size=2, aspect=1
size=4, aspect=1
size=4, aspect=2
Also, all other useful parameters/arguments and defaults for this plotting function can be viewed with once the 'sns' module is loaded:
help(sns.factorplot)
Solution 2 - Python
mpl.rc
is stored in a global dictionary (see http://matplotlib.org/users/customizing.html).
So, if you only want to change the size of one figure (locally), it will do the trick:
plt.figure(figsize=(45,10))
sns.factorplot(...)
It worked for me using matplotlib-1.4.3
and seaborn-0.5.1
Solution 3 - Python
The size of the figure is controlled by the size
and aspect
arguments to factorplot
. They correspond to the size of each facet ("size
" really means "height" and then size * aspect
gives the width), so if you are aiming for a particularl size for the whole figure you'll need to work backwards from there.
Solution 4 - Python
import seaborn as sns
sns.set(rc={'figure.figsize':(12.7,8.6)})
plt.figure(figsize=(45,10))
Solution 5 - Python
- Do not use
%pylab inline
, it is deprecated, use%matplotlib inline
- The question is not specific to IPython.
- use seaborn
.set_style
function, pass it your rc as second parameter or kwarg.: http://web.stanford.edu/~mwaskom/software/seaborn/generated/seaborn.set_style.html
Solution 6 - Python
If you just want to scale the figure use the below code:
import matplotlib.pyplot as plt
plt.figure(figsize=(8, 6))
sns.factorplot("MONTH", "VALUE", hue="REGION", data=typessns, kind="box", palette="OrRd"); // OR any plot code
Solution 7 - Python
Note as of July 2018:
seaborn.__version__ == 0.9.0
Two main changes which affect the above answers
-
The
factorplot
function has been renamed tocatplot()
-
The
size
parameter has been renamed toheight
for multi plot grid functions and those that use them.
> https://seaborn.pydata.org/whatsnew.html
Meaning the answer provided by @Fernando Hernandez should be adjusted as per below:
%matplotlib inline
import seaborn as sns
exercise = sns.load_dataset("exercise")
# Defaults are hieght=5, aspect=1
sns.catplot("kind", "pulse", "diet", exercise, kind="point", height=4, aspect=2)