How to cast Object to its actual type?
C#ObjectTypesCastingTypeofC# Problem Overview
If I have:
void MyMethod(Object obj) { ... }
How can I cast obj
to what its actual type is?
C# Solutions
Solution 1 - C#
If you know the actual type, then just:
SomeType typed = (SomeType)obj;
typed.MyFunction();
If you don't know the actual type, then: not really, no. You would have to instead use one of:
- reflection
- implementing a well-known interface
- dynamic
For example:
// reflection
obj.GetType().GetMethod("MyFunction").Invoke(obj, null);
// interface
IFoo foo = (IFoo)obj; // where SomeType : IFoo and IFoo declares MyFunction
foo.MyFunction();
// dynamic
dynamic d = obj;
d.MyFunction();
Solution 2 - C#
I don't think you can (not without reflection), you should provide a type to your function as well:
void MyMethod(Object obj, Type t)
{
var convertedObject = Convert.ChangeType(obj, t);
...
}
UPD:
This may work for you:
void MyMethod(Object obj)
{
if (obj is A)
{
A a = obj as A;
...
}
else if (obj is B)
{
B b = obj as B;
...
}
}
Solution 3 - C#
How about
JsonConvert.DeserializeObject<SomeType>(object.ToString());
Solution 4 - C#
If your MyFunction()
method is defined only in one class (and its descendants), try
void MyMethod(Object obj)
{
var o = obj as MyClass;
if (o != null)
o.MyFunction();
}
If you have a large number in unrelated classes defining the function you want to call, you should define an interface and make your classes define that interface:
interface IMyInterface
{
void MyFunction();
}
void MyMethod(Object obj)
{
var o = obj as IMyInterface;
if (o != null)
o.MyFunction();
}
Solution 5 - C#
In my case AutoMapper works well.
AutoMapper can map to/from dynamic objects without any explicit configuration:
public class Foo {
public int Bar { get; set; }
public int Baz { get; set; }
}
dynamic foo = new MyDynamicObject();
foo.Bar = 5;
foo.Baz = 6;
Mapper.Initialize(cfg => {});
var result = Mapper.Map<Foo>(foo);
result.Bar.ShouldEqual(5);
result.Baz.ShouldEqual(6);
dynamic foo2 = Mapper.Map<MyDynamicObject>(result);
foo2.Bar.ShouldEqual(5);
foo2.Baz.ShouldEqual(6);
Similarly you can map straight from dictionaries to objects, AutoMapper will line up the keys with property names.
more info https://github.com/AutoMapper/AutoMapper/wiki/Dynamic-and-ExpandoObject-Mapping
Solution 6 - C#
Cast it to its real type if you now the type for example it is oriented from class named abc. You can call your function in this way :
(abc)(obj)).MyFunction();
if you don't know the function it can be done in a different way. Not easy always. But you can find it in some way by it's signature. If this is your case, you should let us know.
Solution 7 - C#
If multiple types are possible, the method itself does not know the type to cast, but the caller does, you might use something like this:
void TheObliviousHelperMethod<T>(object obj) {
(T)obj.ThatClassMethodYouWantedToInvoke();
}
// Meanwhile, where the method is called:
TheObliviousHelperMethod<ActualType>(obj);
Restrictions on the type could be added using the where
keyword after the parentheses.
Solution 8 - C#
You could use also Pattern Matching
void MyMethod(Object obj) {
if(obj is SomeType myVar){
myVar.MyFunction();
}
}
Solution 9 - C#
Implement an interface to call your function in your method
interface IMyInterface
{
void MyinterfaceMethod();
}
IMyInterface MyObj = obj as IMyInterface;
if ( MyObj != null)
{
MyMethod(IMyInterface MyObj );
}
Solution 10 - C#
Casting to actual type is easy:
void MyMethod(Object obj) {
ActualType actualyType = (ActualType)obj;
}