How to cancel a subscription in Angular2

JavascriptAngularRxjs

Javascript Problem Overview


How does one cancel a subscription in Angular2? RxJS seems to have a dispose method, but I can't figure out how to access it. So I have code that has access to an EventEmitter and subscribes to it, like this:

var mySubscription = someEventEmitter.subscribe(
    (val) => {
        console.log('Received:', val);
    },
    (err) => {
        console.log('Received error:', err);
    },
    () => {
        console.log('Completed');
    }
);

How can I use mySubscription to cancel the subscription?

Javascript Solutions


Solution 1 - Javascript

Are you looking to unsubscribe?

mySubscription.unsubscribe();

Solution 2 - Javascript

I thought I put in my two cents too. I use this pattern:

import { Component, OnInit, OnDestroy } from '@angular/core';
import { Subscription } from 'rxjs/Subscription';

@Component({
    selector: 'my-component',
    templateUrl: 'my.component.html'
})
export class MyComponent implements OnInit, OnDestroy {

    private subscriptions: Array<Subscription> = [];

    public ngOnInit(): void {
        this.subscriptions.push(this.someService.change.subscribe(() => {
		    [...]
        }));

	    this.subscriptions.push(this.someOtherService.select.subscribe(() => {
		    [...]
        }));
    }

    public ngOnDestroy(): void {
        this.subscriptions.forEach((subscription: Subscription) => {
            subscription.unsubscribe();
        });
    }
}

EDIT

I read the documentation the other day and found a more recommended pattern:

ReactiveX/RxJS/Subscription

Pros:

It manages the new subscriptions internally and adds some neat checks. Would prefer this method in the feature :).

Cons:

It isn't 100% clear what the code flow is and how subscriptions are affected. Nor is it clear (just from looking at the code) how it deals with closed subscriptions and if all subscriptions are getting closed if unsubscribe is called.

import { Component, OnInit, OnDestroy } from '@angular/core';
import { Subscription } from 'rxjs/Subscription';

@Component({
    selector: 'my-component',
    templateUrl: 'my.component.html'
})
export class MyComponent implements OnInit, OnDestroy {

    private subscription: Subscription = new Subscription();

    public ngOnInit(): void {
        this.subscription.add(this.someService.change.subscribe(() => {
		    [...]
        }));

	    this.subscription.add(this.someOtherService.select.subscribe(() => {
		    [...]
        }));
    }

    public ngOnDestroy(): void {
        /*
         * magic kicks in here: All subscriptions which were added
         * with "subscription.add" are canceled too!
         */
        this.subscription.unsubscribe();
    }
}

Solution 3 - Javascript

EDIT: This does not apply to RxJS 5, which is what angular2 is using.

I would have thought you are looking for the dispose method on Disposable.

> the subscribe method returns a Disposable (link)

I can't seem to find it more explicitly in the docs, but this works (jsbin):

var observable = Rx.Observable.interval(100);

var subscription = observable.subscribe(function(value) {
   console.log(value);
});

setTimeout(function() {
  subscription.dispose();           
}, 1000)

Weirdly, unsubscribe seems to be working for you while it's not working for me...

Solution 4 - Javascript

Far too many different explanations of unsubscribe on Observables for ng2, took me ages to find the right answer. Below is a working example (I was trying to throttle mousemove).

import {Injectable, OnDestroy} from "@angular/core";
import {Subscription} from "rxjs";

@Injectable()
export class MyClass implements OnDestroy {
  
  mouseSubscription: Subscription; //Set a variable for your subscription
  
  myFunct() {
    // I'm trying to throttle mousemove
    const eachSecond$ = Observable.timer(0, 1000);
    const mouseMove$ = Observable.fromEvent<MouseEvent>(document, 'mousemove');
    const mouseMoveEachSecond$ = mouseMove$.sample(eachSecond$);
    
    this.mouseSubscription = mouseMoveEachSecond$.subscribe(() => this.doSomethingElse());
  }

  doSomethingElse() {
    console.log("mouse moved");
  }
  
  stopNow() {
    this.mouseSubscription.unsubscribe();
  }
  
  ngOnDestroy() {
    this.mouseSubscription.unsubscribe();
  }
  
}

Solution 5 - Javascript

ngOnDestroy(){
   mySubscription.unsubscribe();
}

Prefer unsubscribing rxjs unsubscribe's while destroying the component i.e., removing from DOM for avoiding unecessary memory leaks

Solution 6 - Javascript

I prefer personally to use a Subject to close all subscriptions a component might have at the destroy life cycle step which can be achieved this way :

import { Component} from '@angular/core';
import { Subject } from "rxjs/Rx";

@Component({
  selector:    'some-class-app',
  templateUrl: './someClass.component.html',
  providers:   []
})

export class SomeClass {  

  private ngUnsubscribe: Subject<void> = new Subject<void>(); //This subject will tell every subscriptions to stop when the component is destroyed.

  //**********
  constructor() {}

  ngOnInit() {
  
    this.http.post( "SomeUrl.com", {}, null ).map( response => {

      console.log( "Yay." );
      
    }).takeUntil( this.ngUnsubscribe ).subscribe(); //This is where you tell the subscription to stop whenever the component will be destroyed.
  }

  ngOnDestroy() {

    //This is where we close any active subscription.
    this.ngUnsubscribe.next();
    this.ngUnsubscribe.complete();
  }
}

Solution 7 - Javascript

The recommended approach is to use RxJS operators such as the takeUntil operator. Below is the code snippet showing how to use it :-

import { Component, OnInit, OnDestroy } from '@angular/core';
import { interval, Subject } from 'rxjs';
import { takeUntil } from 'rxjs/operators';

@Component({
    selector: 'app-root',
    templateUrl: './app.component.html'
})
export class AppComponent implements OnInit, OnDestroy {
    private ngUnsubscribe = new Subject();

    constructor() { }

    ngOnInit() {
        var observable1 = interval(1000);
        var observable2 = interval(2000);

        observable1.pipe(takeUntil(this.ngUnsubscribe)).subscribe(x => console.log('observable1: ' + x));
        observable2.pipe(takeUntil(this.ngUnsubscribe)).subscribe(x => console.log('observable2: ' + x));
    }

    ngOnDestroy() {
        this.ngUnsubscribe.next();
        this.ngUnsubscribe.complete();
    }
}

You can find a detailed explanation of the topic here

Solution 8 - Javascript

Use

if(mySubscription){
  mySubscription.unsubscribe();
}

Solution 9 - Javascript

import { Subject } from 'rxjs';
import { takeUntil } from 'rxjs/operators';
import { SomeAPIService } from '../some_file/someAPIService.service.ts

@Component({
  templateUrl: './your_Page.html',
  styleUrls: ['./your_Styles.scss']
})

export class (your class) implements OnInit, OnDestroy {
   // This is a subject variable at it simplest form 
     private unsubscribe$ = new Subject<void>();

     constructor (private someAPIService : SomeAPIService) {}
   
     ngOnit(): void { 
       this.someAPIService.getTODOlist({id:1})
        .pipe(takeUntil(this.unsubscribe$))
         .subscribe((value: SomeVariable) => {
         // What ever value you need is SomeVariable
      },)
    }


     ngOnDestroy(): void {
    // clears all, page subscriptions 
      this.unsubscribe$.next();
      this.unsubscribe$.complete();
     }
`}

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionMichael OrylView Question on Stackoverflow
Solution 1 - JavascriptkendaleivView Answer on Stackoverflow
Solution 2 - JavascriptNightkingView Answer on Stackoverflow
Solution 3 - JavascriptNiklas FaschingView Answer on Stackoverflow
Solution 4 - JavascriptJoe KeeneView Answer on Stackoverflow
Solution 5 - JavascriptPrithvi UppalapatiView Answer on Stackoverflow
Solution 6 - JavascriptJahrenskiView Answer on Stackoverflow
Solution 7 - JavascriptYatharth VarshneyView Answer on Stackoverflow
Solution 8 - JavascriptAnshulView Answer on Stackoverflow
Solution 9 - JavascriptJ CrainView Answer on Stackoverflow