How should I verify a log message when testing Python code under nose?

PythonUnit TestingMockingNose

Python Problem Overview


I'm trying to write a simple unit test that will verify that, under a certain condition, a class in my application will log an error via the standard logging API. I can't work out what the cleanest way to test this situation is.

I know that nose already captures logging output through it's logging plugin, but this seems to be intended as a reporting and debugging aid for failed tests.

The two ways to do this I can see are:

  • Mock out the logging module, either in a piecemeal way (mymodule.logging = mockloggingmodule) or with a proper mocking library.
  • Write or use an existing nose plugin to capture the output and verify it.

If I go for the former approach, I'd like to know what the cleanest way to reset the global state to what it was before I mocked out the logging module.

Looking forward to your hints and tips on this one...

Python Solutions


Solution 1 - Python

From python 3.4 on, the standard unittest library offers a new test assertion context manager, assertLogs. From the docs:

with self.assertLogs('foo', level='INFO') as cm:
    logging.getLogger('foo').info('first message')
    logging.getLogger('foo.bar').error('second message')
    self.assertEqual(cm.output, ['INFO:foo:first message',
                                 'ERROR:foo.bar:second message'])

Solution 2 - Python

UPDATE: No longer any need for the answer below. Use the built-in Python way instead!

This answer extends the work done in https://stackoverflow.com/a/1049375/1286628. The handler is largely the same (the constructor is more idiomatic, using super). Further, I add a demonstration of how to use the handler with the standard library's unittest.

class MockLoggingHandler(logging.Handler):
    """Mock logging handler to check for expected logs.

    Messages are available from an instance's ``messages`` dict, in order, indexed by
    a lowercase log level string (e.g., 'debug', 'info', etc.).
    """
    
    def __init__(self, *args, **kwargs):
        self.messages = {'debug': [], 'info': [], 'warning': [], 'error': [],
                         'critical': []}
        super(MockLoggingHandler, self).__init__(*args, **kwargs)

    def emit(self, record):
        "Store a message from ``record`` in the instance's ``messages`` dict."
        try:
            self.messages[record.levelname.lower()].append(record.getMessage())
        except Exception:
            self.handleError(record)

    def reset(self):
        self.acquire()
        try:
            for message_list in self.messages.values():
                message_list.clear()
        finally:
            self.release()

Then you can use the handler in a standard-library unittest.TestCase like so:

import unittest
import logging
import foo

class TestFoo(unittest.TestCase):

    @classmethod
    def setUpClass(cls):
        super(TestFoo, cls).setUpClass()
        # Assuming you follow Python's logging module's documentation's
        # recommendation about naming your module's logs after the module's
        # __name__,the following getLogger call should fetch the same logger
        # you use in the foo module
        foo_log = logging.getLogger(foo.__name__)
        cls._foo_log_handler = MockLoggingHandler(level='DEBUG')
        foo_log.addHandler(cls._foo_log_handler)
        cls.foo_log_messages = cls._foo_log_handler.messages

    def setUp(self):
        super(TestFoo, self).setUp()
        self._foo_log_handler.reset() # So each test is independent

    def test_foo_objects_fromble_nicely(self):
        # Do a bunch of frombling with foo objects
        # Now check that they've logged 5 frombling messages at the INFO level
        self.assertEqual(len(self.foo_log_messages['info']), 5)
        for info_message in self.foo_log_messages['info']:
            self.assertIn('fromble', info_message)

Solution 3 - Python

I used to mock loggers, but in this situation I found best to use logging handlers, so I wrote this one based on the document suggested by jkp(now dead, but cached on Internet Archive)

class MockLoggingHandler(logging.Handler):
    """Mock logging handler to check for expected logs."""
    
    def __init__(self, *args, **kwargs):
        self.reset()
        logging.Handler.__init__(self, *args, **kwargs)

    def emit(self, record):
        self.messages[record.levelname.lower()].append(record.getMessage())
    
    def reset(self):
        self.messages = {
            'debug': [],
            'info': [],
            'warning': [],
            'error': [],
            'critical': [],
        }

Solution 4 - Python

Brandon's answer:

pip install testfixtures

snippet:

import logging
from testfixtures import LogCapture
logger = logging.getLogger('')


with LogCapture() as logs:
    # my awesome code
    logger.error('My code logged an error')
assert 'My code logged an error' in str(logs)

Note: the above does not conflict with calling nosetests and getting the output of logCapture plugin of the tool

Solution 5 - Python

Simplest answer of all

Pytest has a built-in fixture called caplog. No setup needed.

def test_foo(foo, caplog, expected_msgs):

    foo.bar()

    assert [r.msg for r in caplog.records] == expected_msgs

I wish I'd known about caplog before I wasted 6 hours.

> Warning, though - it resets, so you need to perform your SUT action in the same test where you make assertions about caplog.

Personally, I want my console output clean, so I like this to silence the log-to-stderr:

from logging import getLogger
from pytest import fixture


@fixture
def logger(caplog):

    logger = getLogger()
    _ = [logger.removeHandler(h) for h in logger.handlers if h != caplog.handler]       # type: ignore
    return logger


@fixture
def foo(logger):

    return Foo(logger=logger)


@fixture
def expected_msgs():

    # return whatever it is you expect from the SUT


def test_foo(foo, caplog, expected_msgs):

    foo.bar()

    assert [r.msg for r in caplog.records] == expected_msgs

There is a lot to like about pytest fixtures if you're sick of horrible unittest code.

Solution 6 - Python

As a follow up to Reef's answer, I took a liberty of coding up an example using pymox. It introduces some extra helper functions that make it easier to stub functions and methods.

import logging



Code under test:



class Server(object):
def init(self):
self._payload_count = 0
def do_costly_work(self, payload):
# resource intensive logic elided...
pass
def process(self, payload):
self.do_costly_work(payload)
self._payload_count += 1
logging.info("processed payload: %s", payload)
logging.debug("payloads served: %d", self._payload_count)



Here are some helper functions


that are useful if you do a lot


of pymox-y work.



import mox
import inspect
import contextlib
import unittest




def stub_all(self, *targets):
for target in targets:
if inspect.isfunction(target):
module = inspect.getmodule(target)
self.StubOutWithMock(module, target.name)
elif inspect.ismethod(target):
self.StubOutWithMock(target.im_self or target.im_class, target.name)
else:
raise NotImplementedError("I don't know how to stub %s" % repr(target))



Monkey-patch Mox class with our helper 'StubAll' method.


Yucky pymox naming convention observed.



setattr(mox.Mox, 'StubAll', stub_all)




@contextlib.contextmanager
def mocking():
mocks = mox.Mox()
try:
yield mocks
finally:
mocks.UnsetStubs() # Important!
mocks.VerifyAll()



The test case example:



class ServerTests(unittest.TestCase):
def test_logging(self):
s = Server()
with mocking() as m:
m.StubAll(s.do_costly_work, logging.info, logging.debug)
# expectations
s.do_costly_work(mox.IgnoreArg()) # don't care, we test logging here.
logging.info("processed payload: %s", 'hello')
logging.debug("payloads served: %d", 1)
# verified execution
m.ReplayAll()
s.process('hello')




if name == 'main':
unittest.main()

if name == 'main': unittest.main()

Solution 7 - Python

If you define a helper method like this:

import logging

def capture_logging():
    records = []

    class CaptureHandler(logging.Handler):
        def emit(self, record):
            records.append(record)

        def __enter__(self):
            logging.getLogger().addHandler(self)
            return records

        def __exit__(self, exc_type, exc_val, exc_tb):
            logging.getLogger().removeHandler(self)

    return CaptureHandler()

Then you can write test code like this:

    with capture_logging() as log:
        ... # trigger some logger warnings
    assert len(log) == ...
    assert log[0].getMessage() == ...

Solution 8 - Python

You should use mocking, as someday You might want to change Your logger to a, say, database one. You won't be happy if it'll try to connect to the database during nosetests.

Mocking will continue to work even if standard output will be suppressed.

I have used pyMox's stubs. Remember to unset the stubs after the test.

Solution 9 - Python

The ExpectLog class implemented in tornado is a great utility:

with ExpectLog('channel', 'message regex'):
    do_it()

http://tornado.readthedocs.org/en/latest/_modules/tornado/testing.html#ExpectLog

Solution 10 - Python

Keying off @Reef's answer, I did tried the code below. It works well for me both for Python 2.7 (if you install mock) and for Python 3.4.

"""
Demo using a mock to test logging output.
"""

import logging
try:
    import unittest
except ImportError:
    import unittest2 as unittest

try:
    # Python >= 3.3
    from unittest.mock import Mock, patch
except ImportError:
    from mock import Mock, patch

logging.basicConfig()
LOG=logging.getLogger("(logger under test)")

class TestLoggingOutput(unittest.TestCase):
    """ Demo using Mock to test logging INPUT. That is, it tests what
    parameters were used to invoke the logging method, while still
    allowing actual logger to execute normally.

    """
    def test_logger_log(self):
        """Check for Logger.log call."""
        original_logger = LOG
        patched_log = patch('__main__.LOG.log',
                            side_effect=original_logger.log).start()

        log_msg = 'My log msg.'
        level = logging.ERROR
        LOG.log(level, log_msg)

        # call_args is a tuple of positional and kwargs of the last call
        # to the mocked function.
        # Also consider using call_args_list
        # See: https://docs.python.org/3/library/unittest.mock.html#unittest.mock.Mock.call_args
        expected = (level, log_msg)
        self.assertEqual(expected, patched_log.call_args[0])


if __name__ == '__main__':
    unittest.main()

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