How should I check if the input is a email address with dart?


Dart Problem Overview

According to RegExp documentation, we must use JavaScript (Perl 5) regular expressions : ECMA Specification. What method should I use in Dart to check if the input is an email?

Dart Solutions

Solution 1 - Dart

For that simple regex works pretty good.

var email = "[email protected]"
bool emailValid = RegExp(r"^[a-zA-Z0-9.a-zA-Z0-9.!#$%&'*+-/=?^_`{|}~]+@[a-zA-Z0-9]+\.[a-zA-Z]+").hasMatch(email);

Solution 2 - Dart

I'd recommend everyone standardize on the HTML5 email validation spec, which differs from RFC822 by disallowing several very seldom-used features of email addresses (like comments!), but can be recognized by regexes.

Here's the section on email validation in the HTML5 spec:

And this is the regex:


Solution 3 - Dart

Using the RegExp from the answers by Eric and Justin,
I made a extension method for String:

extension EmailValidator on String {
  bool isValidEmail() {
    return RegExp(

  autovalidate: true,
  validator: (input) => input.isValidEmail() ? null : "Check your email",

Solution 4 - Dart

I use this pattern : validate-email-address-in-javascript. (Remove slash / delimiters and add the Dart delimiters : r' ').

bool isEmail(String em) {

  String p = r'^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$';
  RegExp regExp = new RegExp(p);

  return regExp.hasMatch(em);


For more information on email validation, look at these posts : and . This tool may also be very useful : gskinner RegExr.

EDIT : Justin has a better one. I'm using the pattern he proposed.

Solution 5 - Dart

The best regEx pattern I've found is the RFC2822 Email Validation:


Taken from:

All the other regEx I've tested, mark the string email@email as a positive, which is false.

Solution 6 - Dart

I used a simple and not so rigorous validator which also allows [email protected] and [email protected] domains:

var email = "[email protected]";
  bool emailValid = RegExp(r'^.+@[a-zA-Z]+\.{1}[a-zA-Z]+(\.{0,1}[a-zA-Z]+)$').hasMatch(email);
  print (emailValid);

Solution 7 - Dart

2019 Correct Answer

To properly support email validation in Dart/Flutter, please see the package email_validator.



This properly supports:

  • TLDs [optionally]
  • International Domains [optionally]
  • Filtered domains (e.g. [email protected])
  • Domainless addresses (e.g. user@localhost)

Solution 8 - Dart

Email validation in Dart, follow the Regex:

bool validateEmail(String value) {
  Pattern pattern =
  RegExp regex = new RegExp(pattern);
  return (!regex.hasMatch(value)) ? false : true;

void main() {
  print(validateEmail("[email protected]"));

Flow the below Regex:



Solution 9 - Dart

I have seen this page a few times when I was searching, and I came up with a simpler Regex for dart which might help those who will come to this page later.

here is the regex:


so in dart you can use it like


It only supports normal emails and not without TLD. for instance, [email protected] but not me@localhost. Hope it helps.

Solution 10 - Dart

I have arrived to this page in search for e-mail validation, but none of the examples found here have passed all my tests.

Therefore I decided to write my own regEx, adapting some of the concepts from other answers (standing on shoulders of giants), and it is doing great so far:


If you find any issues with that pattern, please let me know.

Solution 11 - Dart

The best regular expression i've came across till now is the following:


this approach relies on adding every domain name you want your user to be able to log in with.

i just added com and net since they are the most popular ones but you can simply add more


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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionEric LavoieView Question on Stackoverflow
Solution 1 - DartAiron TarkView Answer on Stackoverflow
Solution 2 - DartJustin FagnaniView Answer on Stackoverflow
Solution 3 - Dart763View Answer on Stackoverflow
Solution 4 - DartEric LavoieView Answer on Stackoverflow
Solution 5 - DartDavid_EView Answer on Stackoverflow
Solution 6 - DartPriyansh BrannenView Answer on Stackoverflow
Solution 7 - DartLanceView Answer on Stackoverflow
Solution 8 - DartGooglianView Answer on Stackoverflow
Solution 9 - DartMajidView Answer on Stackoverflow
Solution 10 - DartbitfreezeView Answer on Stackoverflow
Solution 11 - Dartuser11496192View Answer on Stackoverflow