How do you run a command for each line of a file?

For example, right now I'm using the following to change a couple of files whose Unix paths I wrote to a file:

cat file.txt | while read in; do chmod 755 "$in"; done

Is there a more elegant, safer way?

Read a file line by line and execute commands: 4 answers

This is because there is not only 1 answer...

0. Shell command line expansion
1. xargs dedicated tool
2. while read with some remarks
3. while read -u using dedicated fd, for interactive processing (sample)

Regarding the OP request: running chmod on all targets listed in file, xargs is the indicated tool. But for some other applications, small amount of files, etc...

0. Read entire file as command line argument.

If your file is not too big and all files are well named (without spaces or other special chars like quotes), you could use shell command line expansion. Simply:

chmod 755 $(<file.txt)

For small amounts of files (lines), this command is the lighter one.

1. xargs is the right tool

For bigger amount of files, or almost any number of lines in your input file...

For many binutils tools, like chown, chmod, rm, cp -t ...

xargs chmod 755 <file.txt

If you have special chars and/or a lot of lines in file.txt.

xargs -0 chmod 755 < <(tr \\n \\0 <file.txt)

If your command need to be run exactly 1 time for each entry:

xargs -0 -n 1 chmod 755 < <(tr \\n \\0 <file.txt)

This is not needed for this sample, as chmod accepts multiple files as arguments, but this matches the title of question.

For some special cases, you could even define the location of the file argument in commands generated by xargs:

xargs -0 -I '{}' -n 1 myWrapper -arg1 -file='{}' wrapCmd < <(tr \\n \\0 <file.txt)

Test with seq 1 5 as input

Try this:

xargs -n 1 -I{} echo Blah {} blabla {}.. < <(seq 1 5)
Blah 1 blabla 1..
Blah 2 blabla 2..
Blah 3 blabla 3..
Blah 4 blabla 4..
Blah 5 blabla 5..

where your command is executed once per line.

2. while read and variants.

As OP suggests,

cat file.txt |
while read in; do
    chmod 755 "$in"
done

will work, but there are 2 issues:

• cat | is a useless fork, and

• | while ... ;done will become a subshell whose environment will disapear after ;done.

So this could be better written:

while read in; do
    chmod 755 "$in"
done < file.txt

But

• You may be warned about $IFS and read flags:

help read

> read: read [-r] ... [-d delim] ... [name ...] > ... > Reads a single line from the standard input... The line is split > into fields as with word splitting, and the first word is assigned > to the first NAME, the second word to the second NAME, and so on... > Only the characters found in $IFS are recognized as word delimiters. > ... > Options: > ... > -d delim continue until the first character of DELIM is read, > rather than newline > ... > -r do not allow backslashes to escape any characters > ... > Exit Status: > The return code is zero, unless end-of-file is encountered...

In some cases, you may need to use

while IFS= read -r in;do
    chmod 755 "$in"
done <file.txt

for avoiding problems with strange filenames. And maybe if you encounter problems with UTF-8:

while LANG=C IFS= read -r in ; do
    chmod 755 "$in"
done <file.txt

While you use a redirection from standard inputfor reading file.txt`, your script cannot read other input interactively (you cannot use standard input for other input anymore).

3. while read, using dedicated fd.

Syntax: while read ...;done <file.txt will redirect standard input to come from file.txt. That means you won't be able to deal with processes until they finish.

This will let you use more than one input simultaneously, you could merge two files (like here: scriptReplay.sh), or maybe:

You plan to create an interactive tool, you have to avoid use of standard input and use some alternative file descriptor.

Constant file descriptors are:

• 0 for standard input
• 1 for standard output
• 2 for standard error.

3.1 [tag:POSIX] [tag:shell] first

You could see them by:

ls -l /dev/fd/

or

ls -l /proc/$$/fd/

From there, you have to choose unused numbers between 0 and 63 (more, in fact, depending on sysctl superuser tool) as your file descriptor.

For this demo, I will use file descriptor 7:

while read <&7 filename; do
    ans=
    while [ -z "$ans" ]; do
        read -p "Process file '$filename' (y/n)? " foo
        [ "$foo" ] && [ -z "${foo#[yn]}" ] && ans=$foo || echo '??'
    done
    if [ "$ans" = "y" ]; then
        echo Yes
        echo "Processing '$filename'."
    else
        echo No
    fi
done 7<file.txt

If you want to read your input file in more differents steps, you have to use:

exec 7<file.txt      # Without spaces between `7` and `<`!
# ls -l /dev/fd/

read <&7 headLine
while read <&7 filename; do
    case "$filename" in
        *'----' ) break ;;  # break loop when line end with four dashes.
    esac
    ....
done

read <&7 lastLine

exec 7<&-            # This will close file descriptor 7.
# ls -l /dev/fd/

3.2 Same under [tag:bash]

Under [tag:bash], you could let him choose any free fd for you and store into a variable:
exec {varname}</path/to/input:

while read -ru ${fle} filename;do
    ans=
    while [ -z "$ans" ]; do
        read -rp "Process file '$filename' (y/n)? " -sn 1 foo
        [ "$foo" ] && [ -z "${foo/[yn]}" ] && ans=$foo || echo '??'
    done
    if [ "$ans" = "y" ]; then
        echo Yes
        echo "Processing '$filename'."
    else
        echo No
    fi
done {fle}<file.txt

Or

exec {fle}<file.txt
# ls -l /dev/fd/
read -ru ${fle} headline

while read -ru ${fle} filename;do
    [[ -n "$filename" ]] && [[ -z ${filename//*----} ]] && break
    ....
done

read -ru ${fle} lastLine

exec {fle}<&-
# ls -l /dev/fd/

Yes.

while read in; do chmod 755 "$in"; done < file.txt

This way you can avoid a cat process.

cat is almost always bad for a purpose such as this. You can read more about Useless Use of Cat.

if you have a nice selector (for example all .txt files in a dir) you could do:

for i in *.txt; do chmod 755 "$i"; done

bash for loop

or a variant of yours:

while read line; do chmod 755 "$line"; done < file.txt

If you want to run your command in parallel for each line you can use GNU Parallel

parallel -a <your file> <program>

Each line of your file will be passed to program as an argument. By default parallel runs as many threads as your CPUs count. But you can specify it with -j

If you know you don't have any whitespace in the input:

xargs chmod 755 < file.txt

If there might be whitespace in the paths, and if you have GNU xargs:

tr '\n' '\0' < file.txt | xargs -0 chmod 755

You can also use AWK which can give you more flexibility to handle the file

awk '{ print "chmod 755 "$0"" | "/bin/sh"}' file.txt

if your file has a field separator like:

> field1,field2,field3

To get only the first field you do

awk -F, '{ print "chmod 755 "$1"" | "/bin/sh"}' file.txt

You can check more details on GNU Documentation https://www.gnu.org/software/gawk/manual/html_node/Very-Simple.html#Very-Simple

Now days xargs still the answer for this, but ... you can now use the -a option to read directly input from a file:

xargs -a file.txt -n 1 -I {} chmod 775 {}

I see that you tagged bash, but Perl would also be a good way to do this:

perl -p -e '`chmod 755 $_`' file.txt

You could also apply a regex to make sure you're getting the right files, e.g. to only process .txt files:

perl -p -e 'if(/\.txt$/) `chmod 755 $_`' file.txt

To "preview" what's happening, just replace the backticks with double quotes and prepend print:

perl -p -e 'if(/\.txt$/) print "chmod 755 $_"' file.txt

The logic applies to many other objectives. And how to read .sh_history of each user from /home/ filesystem? What if there are thousand of them?

#!/bin/ksh
last |head -10|awk '{print $1}'|
 while IFS= read -r line
 do
su - "$line" -c 'tail .sh_history'
 done

Here is the script https://github.com/imvieira/SysAdmin_DevOps_Scripts/blob/master/get_and_run.sh