How do you determine what SQL Tables have an identity column programmatically

I want to create a list of columns in SQL Server 2005 that have identity columns and their corresponding table in T-SQL.

Results would be something like:

TableName, ColumnName

Another potential way to do this for SQL Server, which has less reliance on the system tables (which are subject to change, version to version) is to use the INFORMATION_SCHEMA views:

select COLUMN_NAME, TABLE_NAME
from INFORMATION_SCHEMA.COLUMNS
where COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
order by TABLE_NAME 

sys.columns.is_identity = 1

e.g.,

select o.name, c.name
from sys.objects o inner join sys.columns c on o.object_id = c.object_id
where c.is_identity = 1

Another way (for 2000 / 2005/2012/2014):

IF ((SELECT OBJECTPROPERTY( OBJECT_ID(N'table_name_here'), 'TableHasIdentity')) = 1)
    PRINT 'Yes'
ELSE
    PRINT 'No'

NOTE: table_name_here should be schema.table, unless the schema is dbo.

In SQL 2005:

select object_name(object_id), name
from sys.columns
where is_identity = 1

This query seems to do the trick:

SELECT 
    sys.objects.name AS table_name, 
    sys.columns.name AS column_name
FROM sys.columns JOIN sys.objects 
    ON sys.columns.object_id=sys.objects.object_id
WHERE 
    sys.columns.is_identity=1
    AND
    sys.objects.type in (N'U')

List of tables without Identity column based on Guillermo answer:

SELECT DISTINCT TABLE_NAME
FROM            INFORMATION_SCHEMA.COLUMNS
WHERE        (TABLE_SCHEMA = 'dbo') AND (OBJECTPROPERTY(OBJECT_ID(TABLE_NAME), 'TableHasIdentity') = 0)
ORDER BY TABLE_NAME

here's a working version for MSSQL 2000. I've modified the 2005 code found here: http://sqlfool.com/2011/01/identity-columns-are-you-nearing-the-limits/

/* Define how close we are to the value limit
   before we start throwing up the red flag.
   The higher the value, the closer to the limit. */
DECLARE @threshold DECIMAL(3,2);
SET @threshold = .85;

/* Create a temp table */
CREATE TABLE #identityStatus
(
      database_name     VARCHAR(128)
    , table_name        VARCHAR(128)
    , column_name       VARCHAR(128)
    , data_type         VARCHAR(128)
    , last_value        BIGINT
    , max_value         BIGINT
);

DECLARE @dbname sysname;
DECLARE @sql nvarchar(4000);
 
-- Use an cursor to iterate through the databases since in 2000 there's no sp_MSForEachDB command...
   
DECLARE c cursor FAST_FORWARD FOR
SELECT
	name
FROM
	master.dbo.sysdatabases 
WHERE 
	name NOT IN('master', 'model', 'msdb', 'tempdb');
	
OPEN c;

FETCH NEXT FROM c INTO @dbname;

WHILE @@FETCH_STATUS = 0
BEGIN
	SET @sql = N'Use [' + @dbname + '];
	Insert Into #identityStatus
	Select ''' + @dbname + ''' As [database_name]
		, Object_Name(id.id) As [table_name]
		, id.name As [column_name]
		, t.name As [data_type]
		, IDENT_CURRENT(Object_Name(id.id)) As [last_value]
		, Case 
			When t.name = ''tinyint''   Then 255 
			When t.name = ''smallint''  Then 32767 
			When t.name = ''int''       Then 2147483647 
			When t.name = ''bigint''    Then 9223372036854775807
		  End As [max_value]
	From 
		syscolumns As id
		Join systypes As t On id.xtype = t.xtype
	Where 
		id.colstat&1 = 1	-- this identifies the identity columns (as far as I know)
	';

	EXECUTE sp_executesql @sql;

	FETCH NEXT FROM c INTO @dbname;
END

CLOSE c;
DEALLOCATE c;
 
/* Retrieve our results and format it all prettily */
SELECT database_name
    , table_name
    , column_name
    , data_type
    , last_value
    , CASE 
        WHEN last_value < 0 THEN 100
        ELSE (1 - CAST(last_value AS FLOAT(4)) / max_value) * 100 
      END AS [percentLeft]
    , CASE 
        WHEN CAST(last_value AS FLOAT(4)) / max_value >= @threshold
            THEN 'warning: approaching max limit'
        ELSE 'okay'
        END AS [id_status]
FROM #identityStatus
ORDER BY percentLeft;
 
/* Clean up after ourselves */
DROP TABLE #identityStatus;

The following query work for me:

select	TABLE_NAME tabla,COLUMN_NAME columna
from	INFORMATION_SCHEMA.COLUMNS
where	COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
order by TABLE_NAME

I think this works for SQL 2000:

SELECT 
	CASE WHEN C.autoval IS NOT NULL THEN
		'Identity'
	ELSE
		'Not Identity'
	AND
FROM
	sysobjects O
INNER JOIN
	syscolumns C
ON
	O.id = C.id
WHERE
	O.NAME = @TableName
AND
	C.NAME = @ColumnName

This worked for me using Sql Server 2008:

USE <database_name>;
GO
SELECT SCHEMA_NAME(schema_id) AS schema_name
    , t.name AS table_name
    , c.name AS column_name
FROM sys.tables AS t
JOIN sys.identity_columns c ON t.object_id = c.object_id
ORDER BY schema_name, table_name;
GO

Use this :

DECLARE @Table_Name VARCHAR(100) 
DECLARE @Column_Name VARCHAR(100)
SET @Table_Name = ''
SET @Column_Name = ''

SELECT  RowNumber = ROW_NUMBER() OVER ( PARTITION BY T.[Name] ORDER BY T.[Name], C.column_id ) ,
    SCHEMA_NAME(T.schema_id) AS SchemaName ,
    T.[Name] AS Table_Name ,
    C.[Name] AS Field_Name ,
    sysType.name ,
    C.max_length ,
    C.is_nullable ,
    C.is_identity ,
    C.scale ,
    C.precision
FROM    Sys.Tables AS T
    LEFT JOIN Sys.Columns AS C ON ( T.[Object_Id] = C.[Object_Id] )
    LEFT JOIN sys.types AS sysType ON ( C.user_type_id = sysType.user_type_id )
WHERE   ( Type = 'U' )
    AND ( C.Name LIKE '%' + @Column_Name + '%' )
    AND ( T.Name LIKE '%' + @Table_Name + '%' )
ORDER BY T.[Name] ,
    C.column_id

This worked for SQL Server 2005, 2008, and 2012. I found that the sys.identity_columns did not contain all my tables with identity columns.

SELECT a.name AS TableName, b.name AS IdentityColumn
FROM sys.sysobjects a 
JOIN sys.syscolumns b 
ON a.id = b.id
WHERE is_identity = 1
ORDER BY name;

Looking at the documentation page the status column can also be utilized. Also you can add the four part identifier and it will work across different servers.

SELECT a.name AS TableName, b.name AS IdentityColumn
FROM [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.sysobjects a 
JOIN [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.syscolumns b 
ON a.id = b.id
WHERE is_identity = 1
ORDER BY name;

Source: https://msdn.microsoft.com/en-us/library/ms186816.aspx

By some reason sql server save some identity columns in different tables, the code that work for me, is the following:

select		TABLE_NAME tabla,COLUMN_NAME columna
from		INFORMATION_SCHEMA.COLUMNS
where		COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
union all
select		o.name tabla, c.name columna
from		sys.objects o 
inner join	sys.columns c on o.object_id = c.object_id
where		c.is_identity = 1

Get all columns with Identity. Modern version for MSSQL 2017+. Locks down to specific database:

SELECT
   [COLUMN_NAME]
   , [TABLE_NAME]
   , [TABLE_CATALOG]
FROM
   [INFORMATION_SCHEMA].[COLUMNS]
WHERE
   COLUMNPROPERTY(OBJECT_ID(CONCAT_WS('.' ,[TABLE_CATALOG] ,[TABLE_SCHEMA] ,[TABLE_NAME])) ,[COLUMN_NAME] ,'IsIdentity') = 1
ORDER BY
   [TABLE_NAME]