How do you add a Dictionary of items into another Dictionary

Arrays in Swift support the += operator to add the contents of one Array to another. Is there an easy way to do that for a dictionary?

eg:

var dict1 = ["a" : "foo"]
var dict2 = ["b" : "bar"]

var combinedDict = ... (some way of combining dict1 & dict2 without looping)

You can define += operator for Dictionary, e.g.,

func += <K, V> (left: inout [K:V], right: [K:V]) { 
	for (k, v) in right { 
    	left[k] = v
    } 
}

In Swift 4, one should use merging(_:uniquingKeysWith:):

Example:

let dictA = ["x" : 1, "y": 2, "z": 3]
let dictB = ["x" : 11, "y": 22, "w": 0]

let resultA = dictA.merging(dictB, uniquingKeysWith: { (first, _) in first })
let resultB = dictA.merging(dictB, uniquingKeysWith: { (_, last) in last })

print(resultA) // ["x": 1, "y": 2, "z": 3, "w": 0]
print(resultB) // ["x": 11, "y": 22, "z": 3, "w": 0]

How about

dict2.forEach { (k,v) in dict1[k] = v }

That adds all of dict2's keys and values into dict1.

Swift 4 provides merging(_:uniquingKeysWith:), so for your case:

let combinedDict = dict1.merging(dict2) { $1 }

The shorthand closure returns $1, therefore dict2's value will be used when there is a conflict with the keys.

Currently, looking at the Swift Standard Library Reference for Dictionary, there is no way to easy update a dictionary with another one.

You can write an extension to do it

var dict1 = ["a" : "foo"]
var dict2 = ["b" : "bar"]

extension Dictionary {
    mutating func update(other:Dictionary) {
        for (key,value) in other {
            self.updateValue(value, forKey:key)
        }
    }
}

dict1.update(dict2)
// dict1 is now ["a" : "foo", "b" : "bar]

It's not built into the Swift library but you can add what you want with operator overloading, e.g:

func + <K,V>(left: Dictionary<K,V>, right: Dictionary<K,V>) 
    -> Dictionary<K,V> 
{
    var map = Dictionary<K,V>()
    for (k, v) in left {
        map[k] = v
    }
    for (k, v) in right {
        map[k] = v
    }
    return map
}

This overloads the + operator for Dictionaries which you can now use to add dictionaries with the + operator, e.g:

var dict1 = ["a" : "foo"]
var dict2 = ["b" : "bar"]

var dict3 = dict1 + dict2 // ["a": "foo", "b": "bar"]

Swift 3:

extension Dictionary {
    
    mutating func merge(with dictionary: Dictionary) {
        dictionary.forEach { updateValue($1, forKey: $0) }
    }
    
    func merged(with dictionary: Dictionary) -> Dictionary {
        var dict = self
        dict.merge(with: dictionary)
        return dict
    }
}

let a = ["a":"b"]
let b = ["1":"2"]
let c = a.merged(with: b)

print(c) //["a": "b", "1": "2"]

Swift 2.0

extension Dictionary {
    
    mutating func unionInPlace(dictionary: Dictionary) {
        dictionary.forEach { self.updateValue($1, forKey: $0) }
    }

    func union(var dictionary: Dictionary) -> Dictionary {
        dictionary.unionInPlace(self)
        return dictionary
    }
}

No need to have any dictionary extensions now. Swift(Xcode 9.0+) dictionary has got a functionality for this. Have a look here. Below here is an example on how to use it

  var oldDictionary = ["a": 1, "b": 2]
  var newDictionary = ["a": 10000, "b": 10000, "c": 4]

  oldDictionary.merge(newDictionary) { (oldValue, newValue) -> Int in
        // This closure return what value to consider if repeated keys are found
        return newValue 
  }
  print(oldDictionary) // Prints ["b": 10000, "a": 10000, "c": 4]

#Immutable

I prefer to combine/unite immutable dictionaries with + operator so I implemented it like:

// Swift 2
func + <K,V> (left: Dictionary<K,V>, right: Dictionary<K,V>?) -> Dictionary<K,V> {
    guard let right = right else { return left }
    return left.reduce(right) {
        var new = $0 as [K:V]
        new.updateValue($1.1, forKey: $1.0)
        return new
    }
}

let moreAttributes: [String:AnyObject] = ["Function":"authenticate"]
let attributes: [String:AnyObject] = ["File":"Auth.swift"]

attributes + moreAttributes + nil //["Function": "authenticate", "File": "Auth.swift"]    
attributes + moreAttributes //["Function": "authenticate", "File": "Auth.swift"]
attributes + nil //["File": "Auth.swift"]

#Mutable

// Swift 2
func += <K,V> (inout left: Dictionary<K,V>, right: Dictionary<K,V>?) {
    guard let right = right else { return }
    right.forEach { key, value in
        left.updateValue(value, forKey: key)
    }
}

let moreAttributes: [String:AnyObject] = ["Function":"authenticate"]
var attributes: [String:AnyObject] = ["File":"Auth.swift"]

attributes += nil //["File": "Auth.swift"]
attributes += moreAttributes //["File": "Auth.swift", "Function": "authenticate"]

You can try this

var dict1 = ["a" : "foo"]
var dict2 = ["b" : "bar"]
        
var temp = NSMutableDictionary(dictionary: dict1);
temp.addEntriesFromDictionary(dict2)

A more readable variant using an extension.

extension Dictionary {    
    func merge(dict: Dictionary<Key,Value>) -> Dictionary<Key,Value> {
        var mutableCopy = self        
        for (key, value) in dict {
	        // If both dictionaries have a value for same key, the value of the other dictionary is used.			
            mutableCopy[key] = value 
        }        
        return mutableCopy
    }    
}

You can also use reduce to merge them. Try this in the playground

let d1 = ["a":"foo","b":"bar"]
let d2 = ["c":"car","d":"door"]

let d3 = d1.reduce(d2) { (var d, p) in
   d[p.0] = p.1
   return d
}

Some even more streamlined overloads for Swift 4:

extension Dictionary {
    static func += (lhs: inout [Key:Value], rhs: [Key:Value]) {
        lhs.merge(rhs){$1}
    }
    static func + (lhs: [Key:Value], rhs: [Key:Value]) -> [Key:Value] {
        return lhs.merging(rhs){$1}
    }
}

I recommend the SwifterSwift Library. However, if you don't want to use the entire library and all its great additions you can just make use of their extension of Dictionary:

Swift 3+

public extension Dictionary {
    public static func +=(lhs: inout [Key: Value], rhs: [Key: Value]) {
        rhs.forEach({ lhs[$0] = $1})
    }
}

You can iterate over the Key Value combinations ob the value you want to merge and add them via the updateValue(forKey:) method:

dictionaryTwo.forEach {
    dictionaryOne.updateValue($1, forKey: $0)
}

Now all values of dictionaryTwo got added to dictionaryOne.

There is no need extension or any extra func anymore. You can write like that :

firstDictionary.merge(secondDictionary) { (value1, value2) -> AnyObject in
        return object2 // what you want to return if keys same.
    }

The same as @farhadf's answer but adopted for Swift 3:

let sourceDict1 = [1: "one", 2: "two"]
let sourceDict2 = [3: "three", 4: "four"]

let result = sourceDict1.reduce(sourceDict2) { (partialResult , pair) in
    var partialResult = partialResult //without this line we could not modify the dictionary
    partialResult[pair.0] = pair.1
    return partialResult
}

Swift 3, dictionary extension:

public extension Dictionary {

    public static func +=(lhs: inout Dictionary, rhs: Dictionary) {
        for (k, v) in rhs {
            lhs[k] = v
        }
    }

}

You can use,

func addAll(from: [String: Any], into: [String: Any]){
    from.forEach {into[$0] = $1}
}

You can add a Dictionary extension like this:

extension Dictionary {
    func mergedWith(otherDictionary: [Key: Value]) -> [Key: Value] {
        var mergedDict: [Key: Value] = [:]
        [self, otherDictionary].forEach { dict in
            for (key, value) in dict {
                mergedDict[key] = value
            }
        }
        return mergedDict
    }
}

Then usage is as simple as the following:

var dict1 = ["a" : "foo"]
var dict2 = ["b" : "bar"]

var combinedDict = dict1.mergedWith(dict2)
// => ["a": "foo", "b": "bar"]

---

If you prefer a framework that also includes some more handy features then checkout HandySwift. Just import it to your project and you can use the above code without adding any extensions to the project yourself.

You can use the bridgeToObjectiveC() function to make the dictionary a NSDictionary.

Will be like the following:

var dict1 = ["a":"Foo"]
var dict2 = ["b":"Boo"]

var combinedDict = dict1.bridgeToObjectiveC()
var mutiDict1 : NSMutableDictionary! = combinedDict.mutableCopy() as NSMutableDictionary

var combineDict2 = dict2.bridgeToObjectiveC()

var combine = mutiDict1.addEntriesFromDictionary(combineDict2)

Then you can convert the NSDictionary(combine) back or do whatever.

All of these responses are complicated. This is my solution for swift 2.2 :

    //get first dictionnary
    let finalDictionnary : NSMutableDictionary = self.getBasicDict()
    //cast second dictionnary as [NSObject : AnyObject]
    let secondDictionnary : [NSObject : AnyObject] = self.getOtherDict() as [NSObject : AnyObject]
    //merge dictionnary into the first one
    finalDictionnary.addEntriesFromDictionary(secondDictionnary) 

import Foundation

let x = ["a":1]
let y = ["b":2]

let out = NSMutableDictionary(dictionary: x)
out.addEntriesFromDictionary(y)

The result is an NSMutableDictionary not a Swift typed dictionary, but the syntax to use it is the same (out["a"] == 1 in this case) so you'd only have a problem if you're using third-party code which expects a Swift dictionary, or really need the type checking.

The short answer here is that you actually do have to loop. Even if you're not entering it explicitly, that's what the method you're calling (addEntriesFromDictionary: here) will do. I'd suggest if you're a bit unclear on why that would be the case you should consider how you would merge the leaf nodes of two B-trees.

If you really actually need a Swift native dictionary type in return, I'd suggest:

let x = ["a":1]
let y = ["b":2]

var out = x
for (k, v) in y {
    out[k] = v
}

The downside of this approach is that the dictionary index - however it's done - may be rebuilt several times in the loop, so in practice this is about 10x slower than the NSMutableDictionary approach.

My needs were different, I needed to merge incomplete nested data sets without clobbering.

merging:
	["b": [1, 2], "s": Set([5, 6]), "a": 1, "d": ["x": 2]]
with
	["b": [3, 4], "s": Set([6, 7]), "a": 2, "d": ["y": 4]]
yields:
	["b": [1, 2, 3, 4], "s": Set([5, 6, 7]), "a": 2, "d": ["y": 4, "x": 2]]

This was harder than I wanted it to be. The challenge was in mapping from dynamic typing to static typing, and I used protocols to solve this.

Also worthy of note is that when you use the dictionary literal syntax, you actually get the foundation types, which do not pick up the protocol extensions. I aborted my efforts to support those as I couldn't find an easy to to validate the uniformity of the collection elements.

import UIKit


private protocol Mergable {
	func mergeWithSame<T>(right: T) -> T?
}



public extension Dictionary {
	
	/**
	Merge Dictionaries
	
	- Parameter left: Dictionary to update
	- Parameter right:	Source dictionary with values to be merged
	
	- Returns: Merged dictionay
	*/
	
	
	func merge(right:Dictionary) -> Dictionary {
		var merged = self
		for (k, rv) in right {
			
			// case of existing left value
			if let lv = self[k] {
				
				if let lv = lv as? Mergable where lv.dynamicType == rv.dynamicType {
					let m = lv.mergeWithSame(rv)
					merged[k] = m
				}
					
				else if lv is Mergable {
					assert(false, "Expected common type for matching keys!")
				}
					
				else if !(lv is Mergable), let _ = lv as? NSArray {
					assert(false, "Dictionary literals use incompatible Foundation Types")
				}
					
				else if !(lv is Mergable), let _ = lv as? NSDictionary {
					assert(false, "Dictionary literals use incompatible Foundation Types")
				}
				
				else {
					merged[k] = rv
				}
			}
				
				// case of no existing value
			else {
				merged[k] = rv
			}
		}
		
		return merged
	}
}




extension Array: Mergable {
	
	func mergeWithSame<T>(right: T) -> T? {
		
		if let right = right as? Array {
			return (self + right) as? T
		}
		
		assert(false)
		return nil
	}
}


extension Dictionary: Mergable {
	
	func mergeWithSame<T>(right: T) -> T? {
		
		if let right = right as? Dictionary {
			return self.merge(right) as? T
		}
		
		assert(false)
		return nil
	}
}


extension Set: Mergable {
	
	func mergeWithSame<T>(right: T) -> T? {
		
		if let right = right as? Set {
			return self.union(right) as? T
		}
		
		assert(false)
		return nil
	}
}



var dsa12 = Dictionary<String, Any>()
dsa12["a"] = 1
dsa12["b"] = [1, 2]
dsa12["s"] = Set([5, 6])
dsa12["d"] = ["c":5, "x": 2]


var dsa34 = Dictionary<String, Any>()
dsa34["a"] = 2
dsa34["b"] = [3, 4]
dsa34["s"] = Set([6, 7])
dsa34["d"] = ["c":-5, "y": 4]


//let dsa2 = ["a": 1, "b":a34]
let mdsa3 = dsa12.merge(dsa34)
print("merging:\n\t\(dsa12)\nwith\n\t\(dsa34) \nyields: \n\t\(mdsa3)")

Swift 2.2

func + <K,V>(left: [K : V], right: [K : V]) -> [K : V] {
    var result = [K:V]()

    for (key,value) in left {
        result[key] = value
    }

    for (key,value) in right {
        result[key] = value
    }
    return result
}

I would just use the Dollar library.

https://github.com/ankurp/Dollar/#merge---merge-1

Merges all of the dictionaries together and the latter dictionary overrides the value at a given key

let dict: Dictionary<String, Int> = ["Dog": 1, "Cat": 2]
let dict2: Dictionary<String, Int> = ["Cow": 3]
let dict3: Dictionary<String, Int> = ["Sheep": 4]
$.merge(dict, dict2, dict3)
=> ["Dog": 1, "Cat": 2, "Cow": 3, "Sheep": 4]

Here is a nice extension I wrote...

extension Dictionary where Value: Any {
    public func mergeOnto(target: [Key: Value]?) -> [Key: Value] {
        guard let target = target else { return self }
        return self.merging(target) { current, _ in current }
    }
}

to use:

var dict1 = ["cat": 5, "dog": 6]
var dict2 = ["dog": 9, "rodent": 10]

dict1 = dict1.mergeOnto(target: dict2)

Then, dict1 will be modified to

["cat": 5, "dog": 6, "rodent": 10]