How do I wrap a string in a file in Python?
PythonStringFileStringioPython Problem Overview
How do I create a file-like object (same duck type as File) with the contents of a string?
Python Solutions
Solution 1 - Python
For Python 2.x, use the StringIO module. For example:
>>> from cStringIO import StringIO
>>> f = StringIO('foo')
>>> f.read()
'foo'
I use cStringIO (which is faster), but note that it doesn't accept Unicode strings that cannot be encoded as plain ASCII strings. (You can switch to StringIO by changing "from cStringIO" to "from StringIO".)
For Python 3.x, use the io module.
f = io.StringIO('foo')
Solution 2 - Python
In Python 3.0:
import io
with io.StringIO() as f:
f.write('abcdef')
print('gh', file=f)
f.seek(0)
print(f.read())
The output is:
'abcdefgh'
Solution 3 - Python
This works for Python2.7 and Python3.x:
io.StringIO(u'foo')
Solution 4 - Python
If your file-like object is expected to contain bytes, the string should first be encoded as bytes, and then a BytesIO object can be used instead. In Python 3:
from io import BytesIO
string_repr_of_file = 'header\n byline\n body\n body\n end'
function_that_expects_bytes(BytesIO(bytes(string_repr_of_file,encoding='utf-8')))