How do I view all commits for a specific day?

GitGit Log

Git Problem Overview


I've already looked at the relevant docs from git-scm.com and gitref.org, but I can't seem to figure this out.

Let's say I want to get all commits for Tuesday, November 12th, 2013. Using an existing repo as an example, I know for a fact that I have commits on that day, as well as commits the day before and the day after.

With 2013-11-11 and 2013-11-12

All the following give me commits for both November 11th and 12th:

  • git log --after="2013-11-11" --until="2013-11-12"
  • git log --since="2013-11-11" --until="2013-11-12"
  • git log --after="2013-11-11" --before="2013-11-12"
  • git log --since="2013-11-11" --before="2013-11-12"
With 2013-11-12 only

All the following give me no commits:

  • git log --since="2013-11-12" --until="2013-11-12"
  • git log --since="2013-11-12" --before="2013-11-12"
  • git log --after="2013-11-12" --until="2013-11-12"
  • git log --after="2013-11-12" --before="2013-11-12"
With 2013-11-12 and 2013-11-13

As expected (from the results of 2013-11-11 and 2013-11-12 above), all of the following give me results from both November 12th and 13th:

  • git log --since="2013-11-12" --before="2013-11-13"
  • git log --after="2013-11-12" --before="2013-11-13"
  • git log --since="2013-11-12" --until="2013-11-13"
  • git log --after="2013-11-12" --before="2013-11-13"

...and so on and so forth. I feel like I've tried every possible combination of since, after, before, and until but still can't find the answer, nor do I understand whether those options are inclusive or exclusive, since they seem to be inclusive if the two dates are different, but exclusive if they're on the same day. Did I miss something / what am I doing wrong?!

Git Solutions


Solution 1 - Git

Thanks John Bartholomew!

The answer is to specify the time, e.g. git log --after="2013-11-12 00:00" --before="2013-11-12 23:59"

Solution 2 - Git

I usually check my git log and see what I was working on a specific day and update my timesheet based on that, but it's a pain in the ass to type in the full date in ISO format so I just do it like this

git log --after=jun9 --before=jun10

and I add --author to only print my commits

git log --since=jun9 --until=jun10 --author=Robert 

This prints commits that happened on the last 9th of June (so for 2016 in this case and not for 2015 or 2014 and so on).

The --since/--after and --until/--before parameters can also take stuff like 3 days ago, yesterday, etc.

Solution 3 - Git

Nothing wrong with the accepted answer (which I upvoted), but... we're here for science!

The output below can be expanded/customised with pretty=format:<string> placeholders:

git log --pretty='format:%H %an %ae %ai' | grep 2013-11-12

Not 100% immune to errors as the same string could have been entered by a user. But acceptable depending on which placeholders are used. The snippet above would not fail, for instance.

One could as well just parse the whole git log to JSON and consume/manipulate its data to one's heart content. Check https://github.com/dreamyguy/gitlogg out and never look back!

Disclaimer: that's one of my projects.

Solution 4 - Git

I made a git alias for that specific purpose:

commitsAtDate = "!f() { git log --pretty='format:%C(yellow)%h %G? %ad%Cred%d %Creset%s%C(cyan) [%cn]' --decorate --after=\"$1 0:00\" --before=\"$1 23:59\" --author \"`git config user.name`\"; }; f"

Usage:

git commitsAtDate 2017-08-18

Solution 5 - Git

This script displays the available date range of commits for the current repo, then prompts for the date that you want to see commits from. It displays a short SHA and the full SHA, the author, the commit timestamp, and the comments in single quotes.

The script keeps prompting for dates until you press Enter or Control-D.

Mac users: requires gnu date.

#!/bin/bash

COMMITS=`git log --abbrev-commit --pretty="format:%h %H %ai" | sort -k3 -k4`
FIRST=`echo "$COMMITS" | head -n 1`
LAST=`echo "$COMMITS" | tail -n 1`
echo "First commit: $FIRST"
echo "Last commit: $LAST"
printf "Date to search for commits: "
read DATE
while [[ "$DATE" ]]; do
  NEXT_DATE=`date +%Y-%m-%d -d "$DATE +1 day"`
  #echo "Searching for commits from $DATE to $NEXT_DATE"
  echo `git log --after="$DATE" --before="$NEXT_DATE" --pretty="format:%h %H %an %ci '%s'"`
  printf "\nDate to search for commits: "
  read DATE
done

I called the script commitsOnDates, and here it is in action. The first date I enter has no commits, so the response is just an empty line:

$ commitsOnDates
First commit: 375bcfb 375bcfbbf548134a4e34c36e3f28d87c53b2445f 2015-08-03 13:37:16 -0700
Last commit: 1d4c88c 1d4c88ce6a15efaceda1d653eed3346fcae8f5e6 2018-10-13 21:32:27 -0700
Date to search for commits: 2015-08-13


Date to search for commits: 2015-08-03
375bcfb 375bcfbbf548134a4e34c36e3f28d87c53b2445f Mike Slinn 2015-08-03 13:37:16 -0700 'this is a comment'

Date to search for commits: 2018-10-13
1d4c88c 1d4c88ce6a15efaceda1d653eed3346fcae8f5e6 Mike Slinn 2018-10-13 21:32:27 -0700 'a comment' 64d6e16 64d6e16338657b82c91ac94bea8ebf7b80dc4c28 Mike Slinn 2018-10-13 18:28:41 -0700 'nother comment' d5eb26e d5eb26e49fc9dceee9b9f5a2d8fa052bff2cfbbc Mike Slinn 2018-10-13 18:16:20 -0700 'no comment' d8a4992 d8a4992df208ba5efb50728311820bdad5ba5332 Mike Slinn 2018-10-13 12:02:00 -0700 'commented'

Date to search for commits:

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Question3cheesewheelView Question on Stackoverflow
Solution 1 - Git3cheesewheelView Answer on Stackoverflow
Solution 2 - GitKohányi RóbertView Answer on Stackoverflow
Solution 3 - GitWallace SidhréeView Answer on Stackoverflow
Solution 4 - GitMichael GroßeView Answer on Stackoverflow
Solution 5 - GitMike SlinnView Answer on Stackoverflow