How do I use Java's bitwise operators in Kotlin?
JavaKotlinBitwise OperatorsBitwise AndBitwise OrJava Problem Overview
Java has binary-or | and binary-and & operators:
int a = 5 | 10;
int b = 5 & 10;
They do not seem to work in Kotlin:
val a = 5 | 10;
val b = 5 & 10;
How do I use Java's bitwise operators in Kotlin?
Java Solutions
Solution 1 - Java
You have named functions for them.
Directly from Kotlin docs
>Bitwise operations are represented by functions that can be called in infix form. They can be applied only to Int and Long.
for example:
val x = (1 shl 2) and 0x000FF000
Here is the complete list of bitwise operations:
shl(bits) – signed shift left (Java's <<)
shr(bits) – signed shift right (Java's >>)
ushr(bits) – unsigned shift right (Java's >>>)
and(bits) – bitwise and
or(bits) – bitwise or
xor(bits) – bitwise xor
inv() – bitwise inversion
Solution 2 - Java
you can do this in Kotlin
val a = 5 or 10;
val b = 5 and 10;
here list of operations that you can use
shl(bits) – signed shift left (Java's <<)
shr(bits) – signed shift right (Java's >>)
ushr(bits) – unsigned shift right (Java's >>>)
and(bits) – bitwise and
or(bits) – bitwise or
xor(bits) – bitwise xor
inv() – bitwise inversion
Solution 3 - Java
This is currently not supported, but most probably will be by the new Kotlin compiler K2, see Roman Elizarov's comment on the YouTrack issue KT-1440.
See KT-46756 for the upcoming alpha release and keep an eye on the roadmap.
Solution 4 - Java
Another example:
Java:
byte dataHigh = (byte) ((data[byteOffset] & 0xF0) >> 4);
Kotlin
val d = (data[byteOffset] and 0xF0.toByte())
val dataHigh = (d.toInt() shr 4).toByte()