How do I turn a C# object into a JSON string in .NET?
C#.NetJsonSerializationC# Problem Overview
I have classes like these:
class MyDate
{
int year, month, day;
}
class Lad
{
string firstName;
string lastName;
MyDate dateOfBirth;
}
And I would like to turn a Lad
object into a JSON string like this:
{
"firstName":"Markoff",
"lastName":"Chaney",
"dateOfBirth":
{
"year":"1901",
"month":"4",
"day":"30"
}
}
(Without the formatting). I found this link, but it uses a namespace that's not in .NET 4. I also heard about JSON.NET, but their site seems to be down at the moment, and I'm not keen on using external DLL files.
Are there other options besides manually creating a JSON string writer?
C# Solutions
Solution 1 - C#
Since we all love one-liners
... this one depends on the Newtonsoft NuGet package, which is popular and better than the default serializer.
Newtonsoft.Json.JsonConvert.SerializeObject(new {foo = "bar"})
Documentation: Serializing and Deserializing JSON
Solution 2 - C#
Please Note
Microsoft recommends that you DO NOT USE JavaScriptSerializer
See the header of the documentation page:
>For .NET Framework 4.7.2 and later versions, use the APIs in the System.Text.Json namespace for serialization and deserialization. For earlier versions of .NET Framework, use Newtonsoft.Json.
Original answer:
You could use the JavaScriptSerializer
class (add reference to System.Web.Extensions
):
using System.Web.Script.Serialization;
var json = new JavaScriptSerializer().Serialize(obj);
A full example:
using System;
using System.Web.Script.Serialization;
public class MyDate
{
public int year;
public int month;
public int day;
}
public class Lad
{
public string firstName;
public string lastName;
public MyDate dateOfBirth;
}
class Program
{
static void Main()
{
var obj = new Lad
{
firstName = "Markoff",
lastName = "Chaney",
dateOfBirth = new MyDate
{
year = 1901,
month = 4,
day = 30
}
};
var json = new JavaScriptSerializer().Serialize(obj);
Console.WriteLine(json);
}
}
Solution 3 - C#
Use Json.Net library, you can download it from Nuget Packet Manager.
Serializing to Json String:
var obj = new Lad
{
firstName = "Markoff",
lastName = "Chaney",
dateOfBirth = new MyDate
{
year = 1901,
month = 4,
day = 30
}
};
var jsonString = Newtonsoft.Json.JsonConvert.SerializeObject(obj);
Deserializing to Object:
var obj = Newtonsoft.Json.JsonConvert.DeserializeObject<Lad>(jsonString );
Solution 4 - C#
Use the DataContractJsonSerializer
class: MSDN1, MSDN2.
My example: HERE.
It can also safely deserialize objects from a JSON string, unlike JavaScriptSerializer
. But personally I still prefer Json.NET.
Solution 5 - C#
A new JSON serializer is available in the System.Text.Json
namespace. It's included in the .NET Core 3.0 shared framework and is in a NuGet package for projects that target .NET Standard or .NET Framework or .NET Core 2.x.
Example code:
using System;
using System.Text.Json;
public class MyDate
{
public int year { get; set; }
public int month { get; set; }
public int day { get; set; }
}
public class Lad
{
public string FirstName { get; set; }
public string LastName { get; set; }
public MyDate DateOfBirth { get; set; }
}
class Program
{
static void Main()
{
var lad = new Lad
{
FirstName = "Markoff",
LastName = "Chaney",
DateOfBirth = new MyDate
{
year = 1901,
month = 4,
day = 30
}
};
var json = JsonSerializer.Serialize(lad);
Console.WriteLine(json);
}
}
In this example the classes to be serialized have properties rather than fields; the System.Text.Json
serializer currently doesn't serialize fields.
Documentation:
Solution 6 - C#
You can achieve this by using Newtonsoft.json. Install Newtonsoft.json from NuGet. And then:
using Newtonsoft.Json;
var jsonString = JsonConvert.SerializeObject(obj);
Solution 7 - C#
Wooou! Really better using a JSON framework :)
Here is my example using Json.NET (http://james.newtonking.com/json):
using System;
using System.Collections.Generic;
using System.Text;
using Newtonsoft.Json;
using System.IO;
namespace com.blogspot.jeanjmichel.jsontest.model
{
public class Contact
{
private Int64 id;
private String name;
List<Address> addresses;
public Int64 Id
{
set { this.id = value; }
get { return this.id; }
}
public String Name
{
set { this.name = value; }
get { return this.name; }
}
public List<Address> Addresses
{
set { this.addresses = value; }
get { return this.addresses; }
}
public String ToJSONRepresentation()
{
StringBuilder sb = new StringBuilder();
JsonWriter jw = new JsonTextWriter(new StringWriter(sb));
jw.Formatting = Formatting.Indented;
jw.WriteStartObject();
jw.WritePropertyName("id");
jw.WriteValue(this.Id);
jw.WritePropertyName("name");
jw.WriteValue(this.Name);
jw.WritePropertyName("addresses");
jw.WriteStartArray();
int i;
i = 0;
for (i = 0; i < addresses.Count; i++)
{
jw.WriteStartObject();
jw.WritePropertyName("id");
jw.WriteValue(addresses[i].Id);
jw.WritePropertyName("streetAddress");
jw.WriteValue(addresses[i].StreetAddress);
jw.WritePropertyName("complement");
jw.WriteValue(addresses[i].Complement);
jw.WritePropertyName("city");
jw.WriteValue(addresses[i].City);
jw.WritePropertyName("province");
jw.WriteValue(addresses[i].Province);
jw.WritePropertyName("country");
jw.WriteValue(addresses[i].Country);
jw.WritePropertyName("postalCode");
jw.WriteValue(addresses[i].PostalCode);
jw.WriteEndObject();
}
jw.WriteEndArray();
jw.WriteEndObject();
return sb.ToString();
}
public Contact()
{
}
public Contact(Int64 id, String personName, List<Address> addresses)
{
this.id = id;
this.name = personName;
this.addresses = addresses;
}
public Contact(String JSONRepresentation)
{
//To do
}
}
}
The test:
using System;
using System.Collections.Generic;
using com.blogspot.jeanjmichel.jsontest.model;
namespace com.blogspot.jeanjmichel.jsontest.main
{
public class Program
{
static void Main(string[] args)
{
List<Address> addresses = new List<Address>();
addresses.Add(new Address(1, "Rua Dr. Fernandes Coelho, 85", "15º andar", "São Paulo", "São Paulo", "Brazil", "05423040"));
addresses.Add(new Address(2, "Avenida Senador Teotônio Vilela, 241", null, "São Paulo", "São Paulo", "Brazil", null));
Contact contact = new Contact(1, "Ayrton Senna", addresses);
Console.WriteLine(contact.ToJSONRepresentation());
Console.ReadKey();
}
}
}
The result:
{
"id": 1,
"name": "Ayrton Senna",
"addresses": [
{
"id": 1,
"streetAddress": "Rua Dr. Fernandes Coelho, 85",
"complement": "15º andar",
"city": "São Paulo",
"province": "São Paulo",
"country": "Brazil",
"postalCode": "05423040"
},
{
"id": 2,
"streetAddress": "Avenida Senador Teotônio Vilela, 241",
"complement": null,
"city": "São Paulo",
"province": "São Paulo",
"country": "Brazil",
"postalCode": null
}
]
}
Now I will implement the constructor method that will receives a JSON string and populates the class' fields.
Solution 8 - C#
If they are not very big, what's probably your case export it as JSON.
Also this makes it portable among all platforms.
using Newtonsoft.Json;
[TestMethod]
public void ExportJson()
{
double[,] b = new double[,]
{
{ 110, 120, 130, 140, 150 },
{1110, 1120, 1130, 1140, 1150},
{1000, 1, 5, 9, 1000},
{1110, 2, 6, 10, 1110},
{1220, 3, 7, 11, 1220},
{1330, 4, 8, 12, 1330}
};
string jsonStr = JsonConvert.SerializeObject(b);
Console.WriteLine(jsonStr);
string path = "X:\\Programming\\workspaceEclipse\\PyTutorials\\src\\tensorflow_tutorials\\export.txt";
File.WriteAllText(path, jsonStr);
}
Solution 9 - C#
If you are in an ASP.NET MVC web controller it's as simple as:
string ladAsJson = Json(Lad);
Can't believe no one has mentioned this.
Solution 10 - C#
I would vote for ServiceStack's JSON Serializer:
using ServiceStack;
string jsonString = new { FirstName = "James" }.ToJson();
It is also the fastest JSON serializer available for .NET: http://www.servicestack.net/benchmarks/
Solution 11 - C#
It is as easy as this (it works for dynamic objects as well (type object)):
string json = new
System.Web.Script.Serialization.JavaScriptSerializer().Serialize(MYOBJECT);
Solution 12 - C#
In your Lad model class, add an override to the ToString() method that returns a JSON string version of your Lad object.
Note: you will need to import System.Text.Json;
using System.Text.Json;
class MyDate
{
int year, month, day;
}
class Lad
{
public string firstName { get; set; };
public string lastName { get; set; };
public MyDate dateOfBirth { get; set; };
public override string ToString() => JsonSerializer.Serialize<Lad>(this);
}
Solution 13 - C#
Another solution using System.Text.Json
(.NET Core 3.0+, .NET 5) where an object is self-sufficient and doesn't expose all possible fields:
A passing test:
using NUnit.Framework;
namespace Intech.UnitTests
{
public class UserTests
{
[Test]
public void ConvertsItselfToJson()
{
var userName = "John";
var user = new User(userName);
var actual = user.ToJson();
Assert.AreEqual($"{{\"Name\":\"{userName}\"}}", actual);
}
}
}
An implementation:
using System.Text.Json;
using System.Collections.Generic;
namespace Intech
{
public class User
{
private readonly string Name;
public User(string name)
{
this.Name = name;
}
public string ToJson()
{
var params = new Dictionary<string, string>{{"Name", Name}};
return JsonSerializer.Serialize(params);
}
}
}
Solution 14 - C#
Here is another solution using Cinchoo ETL - an open source library
public class MyDate
{
public int year { get; set; }
public int month { get; set; }
public int day { get; set; }
}
public class Lad
{
public string firstName { get; set; }
public string lastName { get; set; }
public MyDate dateOfBirth { get; set; }
}
static void ToJsonString()
{
var obj = new Lad
{
firstName = "Tom",
lastName = "Smith",
dateOfBirth = new MyDate
{
year = 1901,
month = 4,
day = 30
}
};
var json = ChoJSONWriter.Serialize<Lad>(obj);
Console.WriteLine(json);
}
Output:
{
"firstName": "Tom",
"lastName": "Smith",
"dateOfBirth": {
"year": 1901,
"month": 4,
"day": 30
}
}
Disclaimer: I'm the author of this library.
Solution 15 - C#
Serializer
public static void WriteToJsonFile<T>(string filePath, T objectToWrite, bool append = false) where T : new()
{
var contentsToWriteToFile = JsonConvert.SerializeObject(objectToWrite, new JsonSerializerSettings
{
Formatting = Formatting.Indented,
});
using (var writer = new StreamWriter(filePath, append))
{
writer.Write(contentsToWriteToFile);
}
}
Object
namespace MyConfig
{
public class AppConfigurationSettings
{
public AppConfigurationSettings()
{
/* initialize the object if you want to output a new document
* for use as a template or default settings possibly when
* an app is started.
*/
if (AppSettings == null) { AppSettings=new AppSettings();}
}
public AppSettings AppSettings { get; set; }
}
public class AppSettings
{
public bool DebugMode { get; set; } = false;
}
}
Implementation
var jsonObject = new AppConfigurationSettings();
WriteToJsonFile<AppConfigurationSettings>(file.FullName, jsonObject);
Output
{
"AppSettings": {
"DebugMode": false
}
}