How do I split a string so I can access item x?

Using SQL Server, how do I split a string so I can access item x?

Take a string "Hello John Smith". How can I split the string by space and access the item at index 1 which should return "John"?

I don't believe SQL Server has a built-in split function, so other than a UDF, the only other answer I know is to hijack the PARSENAME function:

SELECT PARSENAME(REPLACE('Hello John Smith', ' ', '.'), 2) 

PARSENAME takes a string and splits it on the period character. It takes a number as its second argument, and that number specifies which segment of the string to return (working from back to front).

SELECT PARSENAME(REPLACE('Hello John Smith', ' ', '.'), 3)  --return Hello

Obvious problem is when the string already contains a period. I still think using a UDF is the best way...any other suggestions?

You may find the solution in SQL User Defined Function to Parse a Delimited String helpful (from The Code Project).

You can use this simple logic:

Declare @products varchar(200) = '1|20|3|343|44|6|8765'
Declare @individual varchar(20) = null

WHILE LEN(@products) > 0
BEGIN
	IF PATINDEX('%|%', @products) > 0
	BEGIN
		SET @individual = SUBSTRING(@products,
                                    0,
                                    PATINDEX('%|%', @products))
		SELECT @individual

		SET @products = SUBSTRING(@products,
                                  LEN(@individual + '|') + 1,
                                  LEN(@products))
	END
	ELSE
	BEGIN
		SET @individual = @products
		SET @products = NULL
		SELECT @individual
	END
END

First, create a function (using CTE, common table expression does away with the need for a temp table)

 create function dbo.SplitString 
    (
    	@str nvarchar(4000), 
    	@separator char(1)
    )
    returns table
    AS
    return (
        with tokens(p, a, b) AS (
    		select 
    			1, 
    			1, 
    			charindex(@separator, @str)
    		union all
    		select
    			p + 1, 
    			b + 1, 
    			charindex(@separator, @str, b + 1)
    		from tokens
    		where b > 0
        )
        select
    		p-1 zeroBasedOccurance,
    		substring(
    			@str, 
    			a, 
    			case when b > 0 then b-a ELSE 4000 end) 
    		AS s
        from tokens
      )
    GO

Then, use it as any table (or modify it to fit within your existing stored proc) like this.

select s 
from dbo.SplitString('Hello John Smith', ' ')
where zeroBasedOccurance=1

Update

Previous version would fail for input string longer than 4000 chars. This version takes care of the limitation:

create function dbo.SplitString 
(
	@str nvarchar(max), 
	@separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
    select 
        cast(1 as bigint), 
        cast(1 as bigint), 
        charindex(@separator, @str)
    union all
    select
        p + 1, 
        b + 1, 
        charindex(@separator, @str, b + 1)
    from tokens
    where b > 0
)
select
    p-1 ItemIndex,
    substring(
        @str, 
        a, 
        case when b > 0 then b-a ELSE LEN(@str) end) 
    AS s
from tokens
);

GO

Usage remains the same.

Most of the solutions here use while loops or recursive CTEs. A set-based approach will be superior, I promise, if you can use a delimiter other than a space:

CREATE FUNCTION [dbo].[SplitString]
    (
        @List NVARCHAR(MAX),
        @Delim VARCHAR(255)
    )
    RETURNS TABLE
    AS
        RETURN ( SELECT [Value], idx = RANK() OVER (ORDER BY n) FROM 
          ( 
            SELECT n = Number, 
              [Value] = LTRIM(RTRIM(SUBSTRING(@List, [Number],
              CHARINDEX(@Delim, @List + @Delim, [Number]) - [Number])))
            FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
              FROM sys.all_objects) AS x
              WHERE Number <= LEN(@List)
              AND SUBSTRING(@Delim + @List, [Number], LEN(@Delim)) = @Delim
          ) AS y
        );

Sample usage:

SELECT Value FROM dbo.SplitString('foo,bar,blat,foo,splunge',',')
  WHERE idx = 3;

Results:

----
blat

You could also add the idx you want as an argument to the function, but I'll leave that as an exercise to the reader.

You can't do this with just the native STRING_SPLIT function added in SQL Server 2016, because there is no guarantee that the output will be rendered in the order of the original list. In other words, if you pass in 3,6,1 the result will likely be in that order, but it could be 1,3,6. I have asked for the community's help in improving the built-in function here:

• Please help with STRING_SPLIT improvements

With enough qualitative feedback, they may actually consider making some of these enhancements:

• STRING_SPLIT is not feature complete

More on split functions, why (and proof that) while loops and recursive CTEs don't scale, and better alternatives, if splitting strings coming from the application layer:

• Split strings the right way – or the next best way
• Splitting Strings : A Follow-Up
• Splitting Strings : Now with less T-SQL
• Comparing string splitting / concatenation methods
• Processing a list of integers : my approach
• Splitting a list of integers : another roundup
• More on splitting lists : custom delimiters, preventing duplicates, and maintaining order
• Removing Duplicates from Strings in SQL Server

On SQL Server 2016 or above, though, you should look at STRING_SPLIT() and STRING_AGG():

• Performance Surprises and Assumptions : STRING_SPLIT()
• STRING_SPLIT() in SQL Server 2016 : Follow-Up #1
• STRING_SPLIT() in SQL Server 2016 : Follow-Up #2
• SQL Server v.Next : STRING_AGG() performance
• Solve old problems with SQL Server’s new STRING_AGG and STRING_SPLIT functions

You can leverage a Number table to do the string parsing.

Create a physical numbers table:

    create table dbo.Numbers (N int primary key);
    insert into dbo.Numbers
    	select top 1000 row_number() over(order by number) from master..spt_values
    go
    

Create test table with 1000000 rows

    create table #yak (i int identity(1,1) primary key, array varchar(50))
    
    insert into #yak(array)
    	select 'a,b,c' from dbo.Numbers n cross join dbo.Numbers nn
    go
    

Create the function

    create function [dbo].[ufn_ParseArray]
        (   @Input      nvarchar(4000), 
            @Delimiter  char(1) = ',',
            @BaseIdent  int
        )
    returns table as
    return  
        (   select  row_number() over (order by n asc) + (@BaseIdent - 1) [i],
                    substring(@Input, n, charindex(@Delimiter, @Input + @Delimiter, n) - n) s
            from    dbo.Numbers
            where   n <= convert(int, len(@Input)) and
                    substring(@Delimiter + @Input, n, 1) = @Delimiter
        )
    go

Usage (outputs 3mil rows in 40s on my laptop)

    select * 
    from #yak 
    cross apply dbo.ufn_ParseArray(array, ',', 1)
    
    

cleanup

    drop table dbo.Numbers;
    drop function  [dbo].[ufn_ParseArray]

Performance here is not amazing, but calling a function over a million row table is not the best idea. If performing a string split over many rows I would avoid the function.

This question is not about a string split approach, but about how to get the nth element.

All answers here are doing some kind of string splitting using recursion, CTEs, multiple CHARINDEX, REVERSE and PATINDEX, inventing functions, call for CLR methods, number tables, CROSS APPLYs ... Most answers cover many lines of code.

But - if you really want nothing more than an approach to get the nth element - this can be done as real one-liner, no UDF, not even a sub-select... And as an extra benefit: type safe

Get part 2 delimited by a space:

DECLARE @input NVARCHAR(100)=N'part1 part2 part3';
SELECT CAST(N'<x>' + REPLACE(@input,N' ',N'</x><x>') + N'</x>' AS XML).value('/x[2]','nvarchar(max)')

Of course you can use variables for delimiter and position (use sql:column to retrieve the position directly from a query's value):

DECLARE @dlmt NVARCHAR(10)=N' ';
DECLARE @pos INT = 2;
SELECT CAST(N'<x>' + REPLACE(@input,@dlmt,N'</x><x>') + N'</x>' AS XML).value('/x[sql:variable("@pos")][1]','nvarchar(max)')

If your string might include forbidden characters (especially one among &><), you still can do it this way. Just use FOR XML PATH on your string first to replace all forbidden characters with the fitting escape sequence implicitly.

It's a very special case if - additionally - your delimiter is the semicolon. In this case I replace the delimiter first to '#DLMT#', and replace this to the XML tags finally:

SET @input=N'Some <, > and &;Other äöü@€;One more';
SET @dlmt=N';';
SELECT CAST(N'<x>' + REPLACE((SELECT REPLACE(@input,@dlmt,'#DLMT#') AS [*] FOR XML PATH('')),N'#DLMT#',N'</x><x>') + N'</x>' AS XML).value('/x[sql:variable("@pos")][1]','nvarchar(max)');

UPDATE for SQL-Server 2016+

Regretfully the developers forgot to return the part's index with STRING_SPLIT. But, using SQL-Server 2016+, there is JSON_VALUE and OPENJSON.

With JSON_VALUE we can pass in the position as the index' array.

For OPENJSON the documentation states clearly:

>When OPENJSON parses a JSON array, the function returns the indexes of the elements in the JSON text as keys.

A string like 1,2,3 needs nothing more than brackets: [1,2,3].
A string of words like this is an example needs to be ["this","is","an","example"].
These are very easy string operations. Just try it out:

DECLARE @str VARCHAR(100)='Hello John Smith';
DECLARE @position INT = 2;

--We can build the json-path '$[1]' using CONCAT
SELECT JSON_VALUE('["' + REPLACE(@str,' ','","') + '"]',CONCAT('$[',@position-1,']'));

--See this for a position safe string-splitter (zero-based):

SELECT  JsonArray.[key] AS [Position]
       ,JsonArray.[value] AS [Part]
FROM OPENJSON('["' + REPLACE(@str,' ','","') + '"]') JsonArray

In this post I tested various approaches and found, that OPENJSON is really fast. Even much faster than the famous "delimitedSplit8k()" method...

UPDATE 2 - Get the values type-safe

We can use an array within an array simply by using doubled [[]]. This allows for a typed WITH-clause:

DECLARE  @SomeDelimitedString VARCHAR(100)='part1|1|20190920';

DECLARE @JsonArray NVARCHAR(MAX)=CONCAT('[["',REPLACE(@SomeDelimitedString,'|','","'),'"]]');

SELECT @SomeDelimitedString          AS TheOriginal
      ,@JsonArray                    AS TransformedToJSON
      ,ValuesFromTheArray.*
FROM OPENJSON(@JsonArray)
WITH(TheFirstFragment  VARCHAR(100) '$[0]'
    ,TheSecondFragment INT          '$[1]'
    ,TheThirdFragment  DATE         '$[2]') ValuesFromTheArray

Here is a UDF which will do it. It will return a table of the delimited values, haven't tried all scenarios on it but your example works fine.

CREATE FUNCTION SplitString
(
-- Add the parameters for the function here
@myString varchar(500),
@deliminator varchar(10)
)
RETURNS
@ReturnTable TABLE
(
-- Add the column definitions for the TABLE variable here
[id] [int] IDENTITY(1,1) NOT NULL,
[part] varchar NULL
)
AS
BEGIN
Declare @iSpaces int
Declare @part varchar(50)



	--initialize spaces
	Select @iSpaces = charindex(@deliminator,@myString,0)
	While @iSpaces > 0

	Begin
		Select @part = substring(@myString,0,charindex(@deliminator,@myString,0))

		Insert Into @ReturnTable(part)
		Select @part

Select @myString = substring(@mystring,charindex(@deliminator,@myString,0)+ len(@deliminator),len(@myString) - charindex(' ',@myString,0))


		Select @iSpaces = charindex(@deliminator,@myString,0)
	end

	If len(@myString) > 0
		Insert Into @ReturnTable
		Select @myString

RETURN 




END
GO
END
GO

You would call it like this:

Select * From SplitString('Hello John Smith',' ')

Edit: Updated solution to handle delimters with a len>1 as in :

select * From SplitString('HelloJohnSmith','**')

Here I post a simple way of solution

CREATE FUNCTION [dbo].[split](
          @delimited NVARCHAR(MAX),
          @delimiter NVARCHAR(100)
        ) RETURNS @t TABLE (id INT IDENTITY(1,1), val NVARCHAR(MAX))
        AS
        BEGIN
          DECLARE @xml XML
          SET @xml = N'<t>' + REPLACE(@delimited,@delimiter,'</t><t>') + '</t>'

          INSERT INTO @t(val)
          SELECT  r.value('.','varchar(MAX)') as item
          FROM  @xml.nodes('/t') as records(r)
          RETURN
        END

Execute the function like this

  select * from dbo.split('Hello John Smith',' ')

In my opinion you guys are making it way too complicated. Just create a CLR UDF and be done with it.

using System;
using System.Data;
using System.Data.SqlClient;
using System.Data.SqlTypes;
using Microsoft.SqlServer.Server;
using System.Collections.Generic;

public partial class UserDefinedFunctions {
  [SqlFunction]
  public static SqlString SearchString(string Search) {
    List<string> SearchWords = new List<string>();
    foreach (string s in Search.Split(new char[] { ' ' })) {
      if (!s.ToLower().Equals("or") && !s.ToLower().Equals("and")) {
        SearchWords.Add(s);
      }
    }

    return new SqlString(string.Join(" OR ", SearchWords.ToArray()));
  }
};

What about using string and values() statement?

DECLARE @str varchar(max)
SET @str = 'Hello John Smith'

DECLARE @separator varchar(max)
SET @separator = ' '

DECLARE @Splited TABLE(id int IDENTITY(1,1), item varchar(max))

SET @str = REPLACE(@str, @separator, '''),(''')
SET @str = 'SELECT * FROM (VALUES(''' + @str + ''')) AS V(A)' 

INSERT INTO @Splited
EXEC(@str)

SELECT * FROM @Splited

Result-set achieved.

id	item
1	Hello
2	John
3	Smith

I use the answer of frederic but this did not work in SQL Server 2005

I modified it and I'm using select with union all and it works

DECLARE @str varchar(max)
SET @str = 'Hello John Smith how are you'

DECLARE @separator varchar(max)
SET @separator = ' '

DECLARE @Splited table(id int IDENTITY(1,1), item varchar(max))

SET @str = REPLACE(@str, @separator, ''' UNION ALL SELECT ''')
SET @str = ' SELECT  ''' + @str + '''  ' 

INSERT INTO @Splited
EXEC(@str)

SELECT * FROM @Splited

And the result-set is:

id	item
1	Hello
2	John
3	Smith
4	how
5	are
6	you

This pattern works fine and you can generalize

Convert(xml,'<n>'+Replace(FIELD,'.','</n><n>')+'</n>').value('(/n[INDEX])','TYPE')
                          ^^^^^                                   ^^^^^     ^^^^

note FIELD, INDEX and TYPE.

Let some table with identifiers like

sys.message.1234.warning.A45
sys.message.1235.error.O98
....

Then, you can write

SELECT Source         = q.value('(/n[1])', 'varchar(10)'),
       RecordType     = q.value('(/n[2])', 'varchar(20)'),
       RecordNumber   = q.value('(/n[3])', 'int'),
       Status         = q.value('(/n[4])', 'varchar(5)')
FROM   (
         SELECT   q = Convert(xml,'<n>'+Replace(fieldName,'.','</n><n>')+'</n>')
         FROM     some_TABLE
       ) Q

splitting and casting all parts.

Yet another get n'th part of string by delimeter function:

create function GetStringPartByDelimeter (
	@value as nvarchar(max),
	@delimeter as nvarchar(max),
	@position as int
) returns NVARCHAR(MAX) 
AS BEGIN
	declare @startPos as int
	declare @endPos as int
	set @endPos = -1
	while (@position > 0 and @endPos != 0) begin
		set @startPos = @endPos + 1
		set @endPos = charindex(@delimeter, @value, @startPos)

		if(@position = 1) begin
			if(@endPos = 0)
				set @endPos = len(@value) + 1

			return substring(@value, @startPos, @endPos - @startPos)
		end

		set @position = @position - 1
	end

	return null
end

and the usage:

select dbo.GetStringPartByDelimeter ('a;b;c;d;e', ';', 3)

which returns:

c

If your database has compatibility level of 130 or higher then you can use the STRING_SPLIT function along with OFFSET FETCH clauses to get the specific item by index.

To get the item at index N (zero based), you can use the following code

SELECT value
FROM STRING_SPLIT('Hello John Smith',' ')
ORDER BY (SELECT NULL)
OFFSET N ROWS
FETCH NEXT 1 ROWS ONLY

To check the compatibility level of your database, execute this code:

SELECT compatibility_level  
FROM sys.databases WHERE name = 'YourDBName';

Try this:

CREATE function [SplitWordList]
(
 @list varchar(8000)
)
returns @t table 
(
 Word varchar(50) not null,
 Position int identity(1,1) not null
)
as begin
  declare 
    @pos int,
    @lpos int,
    @item varchar(100),
    @ignore varchar(100),
    @dl int,
    @a1 int,
    @a2 int,
    @z1 int,
    @z2 int,
    @n1 int,
    @n2 int,
    @c varchar(1),
    @a smallint
  select 
    @a1 = ascii('a'),
    @a2 = ascii('A'),
    @z1 = ascii('z'),
    @z2 = ascii('Z'),
    @n1 = ascii('0'),
    @n2 = ascii('9')
  set @ignore = '''"'
  set @pos = 1
  set @dl = datalength(@list)
  set @lpos = 1
  set @item = ''
  while (@pos <= @dl) begin
    set @c = substring(@list, @pos, 1)
    if (@ignore not like '%' + @c + '%') begin
      set @a = ascii(@c)
      if ((@a >= @a1) and (@a <= @z1))  
        or ((@a >= @a2) and (@a <= @z2))
        or ((@a >= @n1) and (@a <= @n2))
      begin
        set @item = @item + @c
      end else if (@item > '') begin
        insert into @t values (@item)
        set @item = ''
      end
    end 
    set @pos = @pos + 1
  end
  if (@item > '') begin
    insert into @t values (@item)
  end
  return
end

Test it like this:

select * from SplitWordList('Hello John Smith')

I was looking for the solution on net and the below works for me. Ref.

And you call the function like this :

SELECT * FROM dbo.split('ram shyam hari gopal',' ')

---

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

CREATE FUNCTION [dbo].[Split](@String VARCHAR(8000), @Delimiter CHAR(1))       
RETURNS @temptable TABLE (items VARCHAR(8000))       
AS       
BEGIN       
    DECLARE @idx INT       
    DECLARE @slice VARCHAR(8000)        
    SELECT @idx = 1       
    IF len(@String)<1 OR @String IS NULL  RETURN       
    WHILE @idx!= 0       
    BEGIN       
        SET @idx = charindex(@Delimiter,@String)       
        IF @idx!=0       
            SET @slice = LEFT(@String,@idx - 1)       
        ELSE       
            SET @slice = @String       
        IF(len(@slice)>0)  
            INSERT INTO @temptable(Items) VALUES(@slice)       
        SET @String = RIGHT(@String,len(@String) - @idx)       
        IF len(@String) = 0 break       
    END   
    RETURN       
END

The following example uses a recursive CTE

Update 18.09.2013

CREATE FUNCTION dbo.SplitStrings_CTE(@List nvarchar(max), @Delimiter nvarchar(1))
RETURNS @returns TABLE (val nvarchar(max), [level] int, PRIMARY KEY CLUSTERED([level]))
AS
BEGIN
;WITH cte AS
 (
  SELECT SUBSTRING(@List, 0, CHARINDEX(@Delimiter,  @List + @Delimiter)) AS val,
         CAST(STUFF(@List + @Delimiter, 1, CHARINDEX(@Delimiter, @List + @Delimiter), '') AS nvarchar(max)) AS stval, 
         1 AS [level]
  UNION ALL
  SELECT SUBSTRING(stval, 0, CHARINDEX(@Delimiter, stval)),
         CAST(STUFF(stval, 1, CHARINDEX(@Delimiter, stval), '') AS nvarchar(max)),
         [level] + 1
  FROM cte
  WHERE stval != ''
  )
  INSERT @returns
  SELECT REPLACE(val, ' ','' ) AS val, [level]
  FROM cte
  WHERE val > ''
  RETURN
END

Demo on SQLFiddle

Alter Function dbo.fn_Split
(
@Expression nvarchar(max),
@Delimiter  nvarchar(20) = ',',
@Qualifier  char(1) = Null
)
RETURNS @Results TABLE (id int IDENTITY(1,1), value nvarchar(max))
AS
BEGIN
   /* USAGE
        Select * From dbo.fn_Split('apple pear grape banana orange honeydew cantalope 3 2 1 4', ' ', Null)
        Select * From dbo.fn_Split('1,abc,"Doe, John",4', ',', '"')
        Select * From dbo.fn_Split('Hello <=1, Y>0,"&""&&&&', ',', '"')
   */

   -- Declare Variables
   DECLARE
      @X     xml,
      @Temp  nvarchar(max),
      @Temp2 nvarchar(max),
      @Start int,
      @End   int

   -- HTML Encode @Expression
   Select @Expression = (Select @Expression For XML Path(''))

   -- Find all occurences of @Delimiter within @Qualifier and replace with |||***|||
   While PATINDEX('%' + @Qualifier + '%', @Expression) > 0 AND Len(IsNull(@Qualifier, '')) > 0
   BEGIN
      Select
         -- Starting character position of @Qualifier
         @Start = PATINDEX('%' + @Qualifier + '%', @Expression),
         -- @Expression starting at the @Start position
         @Temp = SubString(@Expression, @Start + 1, LEN(@Expression)-@Start+1),
         -- Next position of @Qualifier within @Expression
         @End = PATINDEX('%' + @Qualifier + '%', @Temp) - 1,
         -- The part of Expression found between the @Qualifiers
         @Temp2 = Case When @End &LT 0 Then @Temp Else Left(@Temp, @End) End,
         -- New @Expression
         @Expression = REPLACE(@Expression,
                               @Qualifier + @Temp2 + Case When @End &LT 0 Then '' Else @Qualifier End,
                               Replace(@Temp2, @Delimiter, '|||***|||')
                       )
   END

   -- Replace all occurences of @Delimiter within @Expression with '&lt/fn_Split&gt&ltfn_Split&gt'
   -- And convert it to XML so we can select from it
   SET
      @X = Cast('&ltfn_Split&gt' +
                Replace(@Expression, @Delimiter, '&lt/fn_Split&gt&ltfn_Split&gt') +
                '&lt/fn_Split&gt' as xml)

   -- Insert into our returnable table replacing '|||***|||' back to @Delimiter
   INSERT @Results
   SELECT
      "Value" = LTRIM(RTrim(Replace(C.value('.', 'nvarchar(max)'), '|||***|||', @Delimiter)))
   FROM
      @X.nodes('fn_Split') as X(C)

   -- Return our temp table
   RETURN
END

You can split a string in SQL without needing a function:

DECLARE @bla varchar(MAX)
SET @bla = 'BED40DFC-F468-46DD-8017-00EF2FA3E4A4,64B59FC5-3F4D-4B0E-9A48-01F3D4F220B0,A611A108-97CA-42F3-A2E1-057165339719,E72D95EA-578F-45FC-88E5-075F66FD726C'

-- http://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes
SELECT 
    x.XmlCol.value('.', 'varchar(36)') AS val 
FROM 
(
    SELECT 
    CAST('<e>' + REPLACE(@bla, ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b 
CROSS APPLY b.RawXml.nodes('e') x(XmlCol);

If you need to support arbitrary strings (with xml special characters)

DECLARE @bla NVARCHAR(MAX)
SET @bla = '<html>unsafe & safe Utf8CharsDon''tGetEncoded ÄöÜ - "Conex"<html>,Barnes & Noble,abc,def,ghi'

-- http://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes
SELECT 
    x.XmlCol.value('.', 'nvarchar(MAX)') AS val 
FROM 
(
    SELECT 
    CAST('<e>' + REPLACE((SELECT @bla FOR XML PATH('')), ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b 
CROSS APPLY b.RawXml.nodes('e') x(XmlCol); 

I know it's an old Question, but i think some one can benefit from my solution.

select 
SUBSTRING(column_name,1,CHARINDEX(' ',column_name,1)-1)
,SUBSTRING(SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name))
	,1
	,CHARINDEX(' ',SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name)),1)-1)
,SUBSTRING(SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name))
	,CHARINDEX(' ',SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name)),1)+1
	,LEN(column_name))
from table_name

SQL FIDDLE

Advantages:

• It separates all the 3 sub-strings deliminator by ' '.
• One must not use while loop, as it decreases the performance.
• No need to Pivot as all the resultant sub-string will be displayed in one Row

Limitations:

• One must know the total no. of spaces (sub-string).

Note: the solution can give sub-string up to to N.

To overcame the limitation we can use the following ref.

But again the above solution can't be use in a table (Actaully i wasn't able to use it).

Again i hope this solution can help some-one.

Update: In case of Records > 50000 it is not advisable to use LOOPS as it will degrade the Performance

Almost all the other answers are replacing the string being split which wastes CPU cycles and performs unnecessary memory allocations.

I cover a much better way to do a string split here: http://www.digitalruby.com/split-string-sql-server/

Here is the code:

SET NOCOUNT ON

-- You will want to change nvarchar(MAX) to nvarchar(50), varchar(50) or whatever matches exactly with the string column you will be searching against
DECLARE @SplitStringTable TABLE (Value nvarchar(MAX) NOT NULL)
DECLARE @StringToSplit nvarchar(MAX) = 'your|string|to|split|here'
DECLARE @SplitEndPos int
DECLARE @SplitValue nvarchar(MAX)
DECLARE @SplitDelim nvarchar(1) = '|'
DECLARE @SplitStartPos int = 1

SET @SplitEndPos = CHARINDEX(@SplitDelim, @StringToSplit, @SplitStartPos)

WHILE @SplitEndPos > 0
BEGIN
	SET @SplitValue = SUBSTRING(@StringToSplit, @SplitStartPos, (@SplitEndPos - @SplitStartPos))
	INSERT @SplitStringTable (Value) VALUES (@SplitValue)
	SET @SplitStartPos = @SplitEndPos + 1
	SET @SplitEndPos = CHARINDEX(@SplitDelim, @StringToSplit, @SplitStartPos)
END

SET @SplitValue = SUBSTRING(@StringToSplit, @SplitStartPos, 2147483647)
INSERT @SplitStringTable (Value) VALUES(@SplitValue)

SET NOCOUNT OFF

-- You can select or join with the values in @SplitStringTable at this point.

Pure set-based solution using TVF with recursive CTE. You can JOIN and APPLY this function to any dataset.

create function [dbo].[SplitStringToResultSet] (@value varchar(max), @separator char(1))
returns table
as return
with r as (
    select value, cast(null as varchar(max)) [x], -1 [no] from (select rtrim(cast(@value as varchar(max))) [value]) as j
    union all
    select right(value, len(value)-case charindex(@separator, value) when 0 then len(value) else charindex(@separator, value) end) [value]
    , left(r.[value], case charindex(@separator, r.value) when 0 then len(r.value) else abs(charindex(@separator, r.[value])-1) end ) [x]
    , [no] + 1 [no]
    from r where value > '')

select ltrim(x) [value], [no] [index] from r where x is not null;
go

Usage:

select *
from [dbo].[SplitStringToResultSet]('Hello John Smith', ' ')
where [index] = 1;

Result:

value	index
-------------
John	1

In Azure SQL Database (based on Microsoft SQL Server but not exactly the same thing) the signature of STRING_SPLIT function looks like:

STRING_SPLIT ( string , separator [ , enable_ordinal ] )

When enable_ordinal flag is set to 1 the result will include a column named ordinal that consists of the 1‑based position of the substring within the input string:

SELECT *
FROM STRING_SPLIT('hello john smith', ' ', 1)

| value | ordinal |
|-------|---------|
| hello | 1       |
| john  | 2       |
| smith | 3       |

This allows us to do this:

SELECT value
FROM STRING_SPLIT('hello john smith', ' ', 1)
WHERE ordinal = 2

| value |
|-------|
| john  |

---

If enable_ordinal is not available then there is a trick which assumes that the substrings with the input string are unique. In this scenario, CHAR_INDEX could be used to find the position of the substring within the input string:

SELECT value, ROW_NUMBER() OVER (ORDER BY CHARINDEX(value, input_str)) AS ord_pos
FROM (VALUES
    ('hello john smith')
) AS x(input_str)
CROSS APPLY STRING_SPLIT(input_str, ' ')

| value | ord_pos |
|-------+---------|
| hello | 1       |
| john  | 2       |
| smith | 3       |

Recursive CTE solution with server pain, test it

MS SQL Server 2008 Schema Setup:

create table Course( Courses varchar(100) );
insert into Course values ('Hello John Smith');

Query 1:

with cte as
   ( select 
        left( Courses, charindex( ' ' , Courses) ) as a_l,
        cast( substring( Courses, 
                         charindex( ' ' , Courses) + 1 , 
                         len(Courses ) ) + ' ' 
              as varchar(100) )  as a_r,
        Courses as a,
        0 as n
     from Course t
    union all
      select 
        left(a_r, charindex( ' ' , a_r) ) as a_l,
        substring( a_r, charindex( ' ' , a_r) + 1 , len(a_R ) ) as a_r,
        cte.a,
        cte.n + 1 as n
    from Course t inner join cte 
         on t.Courses = cte.a and len( a_r ) > 0
        
   )
select a_l, n from cte
--where N = 1

Results:

|    A_L | N |
|--------|---|
| Hello  | 0 |
|  John  | 1 |
| Smith  | 2 |

while similar to the xml based answer by josejuan, i found that processing the xml path only once, then pivoting was moderately more efficient:

select ID,
    [3] as PathProvidingID,
    [4] as PathProvider,
    [5] as ComponentProvidingID,
    [6] as ComponentProviding,
    [7] as InputRecievingID,
    [8] as InputRecieving,
    [9] as RowsPassed,
    [10] as InputRecieving2
    from
    (
    select id,message,d.* from sysssislog cross apply       ( 
    	  SELECT Item = y.i.value('(./text())[1]', 'varchar(200)'),
	          row_number() over(order by y.i) as rn
		  FROM 
		  ( 
		     SELECT x = CONVERT(XML, '<i>' + REPLACE(Message, ':', '</i><i>') + '</i>').query('.')
		  ) AS a CROSS APPLY x.nodes('i') AS y(i)
	   ) d
	   WHERE event
	   = 
	   'OnPipelineRowsSent'
    ) as tokens 
    pivot 
    ( max(item) for [rn] in ([3],[4],[5],[6],[7],[8],[9],[10]) 
    ) as data

ran in 8:30

select id,
tokens.value('(/n[3])', 'varchar(100)')as PathProvidingID,
tokens.value('(/n[4])', 'varchar(100)') as PathProvider,
tokens.value('(/n[5])', 'varchar(100)') as ComponentProvidingID,
tokens.value('(/n[6])', 'varchar(100)') as ComponentProviding,
tokens.value('(/n[7])', 'varchar(100)') as InputRecievingID,
tokens.value('(/n[8])', 'varchar(100)') as InputRecieving,
tokens.value('(/n[9])', 'varchar(100)') as RowsPassed
 from
(
    select id, Convert(xml,'<n>'+Replace(message,'.','</n><n>')+'</n>') tokens
         from sysssislog 
	   WHERE event
	   = 
	   'OnPipelineRowsSent'
    ) as data

ran in 9:20

CREATE FUNCTION [dbo].[fnSplitString] 
( 
    @string NVARCHAR(MAX), 
    @delimiter CHAR(1) 
) 
RETURNS @output TABLE(splitdata NVARCHAR(MAX) 
) 
BEGIN 
    DECLARE @start INT, @end INT 
    SELECT @start = 1, @end = CHARINDEX(@delimiter, @string) 
    WHILE @start < LEN(@string) + 1 BEGIN 
        IF @end = 0  
            SET @end = LEN(@string) + 1
       
        INSERT INTO @output (splitdata)  
        VALUES(SUBSTRING(@string, @start, @end - @start)) 
        SET @start = @end + 1 
        SET @end = CHARINDEX(@delimiter, @string, @start)
        
    END 
    RETURN 
END

AND USE IT

select *from dbo.fnSplitString('Querying SQL Server','')

if anyone wants to get only one part of the seperatured text can use this

select * from fromSplitStringSep('Word1 wordr2 word3',' ')

CREATE function [dbo].[SplitStringSep] 
(
    @str nvarchar(4000), 
    @separator char(1)
)
returns table
AS
return (
    with tokens(p, a, b) AS (
        select 
        1, 
        1, 
        charindex(@separator, @str)
        union all
        select
            p + 1, 
            b + 1, 
            charindex(@separator, @str, b + 1)
        from tokens
        where b > 0
        )
        select
            p-1 zeroBasedOccurance,
            substring(
                @str, 
                a, 
                case when b > 0 then b-a ELSE 4000 end) 
            AS s
        from tokens
  )

I devoloped this,

declare @x nvarchar(Max) = 'ali.veli.deli.';
declare @item nvarchar(Max);
declare @splitter char='.';

while CHARINDEX(@splitter,@x) != 0
begin
	set @item = LEFT(@x,CHARINDEX(@splitter,@x))
	set @x    = RIGHT(@x,len(@x)-len(@item) )
	 select @item as item, @x as x;
end

the only attention you should is dot '.' that end of the @x is always should be there.

declare @strng varchar(max)='hello john smith'
select (
    substring(
        @strng,
        charindex(' ', @strng) + 1,
        (
          (charindex(' ', @strng, charindex(' ', @strng) + 1))
          - charindex(' ',@strng)
        )
    ))

building on @NothingsImpossible solution, or, rather, comment on the most voted answer (just below the accepted one), i found the following quick-and-dirty solution fulfill my own needs - it has a benefit of being solely within SQL domain.

given a string "first;second;third;fourth;fifth", say, I want to get the third token. this works only if we know how many tokens the string is going to have - in this case it's 5. so my way of action is to chop the last two tokens away (inner query), and then to chop the first two tokens away (outer query)

i know that this is ugly and covers the specific conditions i was in, but am posting it just in case somebody finds it useful. cheers

select 
	REVERSE(
		SUBSTRING(
			reverse_substring, 
			0, 
			CHARINDEX(';', reverse_substring)
	    )
	) 
from 
(
	select 
		msg,
		SUBSTRING(
			REVERSE(msg), 
			CHARINDEX(
				';', 
				REVERSE(msg), 
				CHARINDEX(
					';',
					REVERSE(msg)
				)+1
			)+1,
			1000
		) reverse_substring
	from 
	(
		select 'first;second;third;fourth;fifth' msg
	) a
) b

Starting with SQL Server 2016 we string_split

DECLARE @string varchar(100) = 'Richard, Mike, Mark'

SELECT value FROM string_split(@string, ',')

A modern approach using [STRING_SPLIT][1], requires SQL Server 2016 and above.

DECLARE @string varchar(100) = 'Hello John Smith'

SELECT
	ROW_NUMBER() OVER (ORDER BY value) AS RowNr,
	value
FROM string_split(@string, ' ')

Result:

RowNr	value
1	    Hello
2	    John
3	    Smith

Now it is possible to get th nth element from the row number. [1]: https://docs.microsoft.com/en-us/sql/t-sql/functions/string-split-transact-sql

Aaron Bertrand's answer is great, but flawed. It doesn't accurately handle a space as a delimiter (as was the example in the original question) since the length function strips trailing spaces.

The following is his code, with a small adjustment to allow for a space delimiter:

CREATE FUNCTION [dbo].[SplitString]
(
    @List NVARCHAR(MAX),
    @Delim VARCHAR(255)
)
RETURNS TABLE
AS
    RETURN ( SELECT [Value] FROM 
      ( 
        SELECT 
          [Value] = LTRIM(RTRIM(SUBSTRING(@List, [Number],
          CHARINDEX(@Delim, @List + @Delim, [Number]) - [Number])))
        FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
          FROM sys.all_objects) AS x
          WHERE Number <= LEN(@List)
          AND SUBSTRING(@Delim + @List, [Number], LEN(@Delim+'x')-1) = @Delim
      ) AS y
    );

Here is a function that will accomplish the question's goal of splitting a string and accessing item X:

CREATE FUNCTION [dbo].[SplitString]
(
   @List       VARCHAR(MAX),
   @Delimiter  VARCHAR(255),
   @ElementNumber INT
)
RETURNS VARCHAR(MAX)
AS
BEGIN

	   DECLARE @inp VARCHAR(MAX)
	   SET @inp = (SELECT REPLACE(@List,@Delimiter,'_DELMTR_') FOR XML PATH(''))

	   DECLARE @xml XML
	   SET @xml = '<split><el>' + REPLACE(@inp,'_DELMTR_','</el><el>') + '</el></split>'

	   DECLARE @ret VARCHAR(MAX)
	   SET @ret = (SELECT
			  el = split.el.value('.','varchar(max)')
	   FROM  @xml.nodes('/split/el[string-length(.)>0][position() = sql:variable("@elementnumber")]') split(el))

	   RETURN @ret

END

Usage:

SELECT dbo.SplitString('Hello John Smith', ' ', 2)

Result:

John

SIMPLE SOLUTION FOR PARSING FIRST AND LAST NAME

DECLARE @Name varchar(10) = 'John Smith'

-- Get First Name
SELECT SUBSTRING(@Name, 0, (SELECT CHARINDEX(' ', @Name)))
    
-- Get Last Name
SELECT SUBSTRING(@Name, (SELECT CHARINDEX(' ', @Name)) + 1, LEN(@Name))

In my case (and in many others it seems...), I have a list of first and last names separated by a single space. This can be used directly inside a select statement to parse first and last name.

-- i.e. Get First and Last Name from a table of Full Names
SELECT SUBSTRING(FullName, 0, (SELECT CHARINDEX(' ', FullName))) as FirstName,
SUBSTRING(FullName, (SELECT CHARINDEX(' ', FullName)) + 1, LEN(FullName)) as LastName,
From FullNameTable

I know its late, but I recently had this requirement and came up with the below code. I don't have a choice to use User defined function. Hope this helps.

SELECT 
	SUBSTRING(
				SUBSTRING('Hello John Smith' ,0,CHARINDEX(' ','Hello John Smith',CHARINDEX(' ','Hello John Smith')+1)
						),CHARINDEX(' ','Hello John Smith'),LEN('Hello John Smith')
			)

CREATE TABLE test(
	id int,
	adress varchar(100)
);
INSERT INTO test VALUES(1, 'Ludovic Aubert, 42 rue de la Victoire, 75009, Paris, France'),(2, 'Jose Garcia, 1 Calle de la Victoria, 56500 Barcelona, Espana');

SELECT id, value, COUNT(*) OVER (PARTITION BY id) AS n, ROW_NUMBER() OVER (PARTITION BY id ORDER BY (SELECT NULL)) AS rn, adress
FROM test
CROSS APPLY STRING_SPLIT(adress, ',')

Modified function of @Aaron Bertrand

    CREATE FUNCTION [dbo].[SplitString]
(
	@List NVARCHAR(MAX),
	@Delim VARCHAR(255),
	@Idx int
)
RETURNS NVARCHAR(1000)
AS
BEGIN
	DECLARE @ValueTable TABLE(String NVARCHAR(50), Ind int)
	DECLARE @Value NVARCHAR(50)
	BEGIN
	INSERT INTO @ValueTable
	SELECT Value, idx FROM
		(SELECT [Value], idx = RANK() OVER (ORDER BY n) FROM 
			  ( 
				SELECT n = Number, 
				[Value] = LTRIM(RTRIM(SUBSTRING(@List, [Number],
				CHARINDEX(@Delim, @List + @Delim, [Number]) - [Number])))
				FROM	
						(SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
						 FROM sys.all_objects) AS x
				WHERE Number <= LEN(@List)
				AND SUBSTRING(@Delim + @List, [Number], LEN(@Delim)) = @Delim
			  ) AS y
		  ) AS R WHERE idx = @Idx
	SET @Value = (SELECT String FROM @ValueTable)
	END
	RETURN @Value
END
GO

Well, mine isn't all that simpler, but here is the code I use to split a comma-delimited input variable into individual values, and put it into a table variable. I'm sure you could modify this slightly to split based on a space and then to do a basic SELECT query against that table variable to get your results.

-- Create temporary table to parse the list of accounting cycles.
DECLARE @tblAccountingCycles table
(
    AccountingCycle varchar(10)
)

DECLARE @vchAccountingCycle varchar(10)
DECLARE @intPosition int

SET @vchAccountingCycleIDs = LTRIM(RTRIM(@vchAccountingCycleIDs)) + ','
SET @intPosition = CHARINDEX(',', @vchAccountingCycleIDs, 1)

IF REPLACE(@vchAccountingCycleIDs, ',', '') <> ''
BEGIN
    WHILE @intPosition > 0
    BEGIN
        SET @vchAccountingCycle = LTRIM(RTRIM(LEFT(@vchAccountingCycleIDs, @intPosition - 1)))
        IF @vchAccountingCycle <> ''
        BEGIN
            INSERT INTO @tblAccountingCycles (AccountingCycle) VALUES (@vchAccountingCycle)
        END
        SET @vchAccountingCycleIDs = RIGHT(@vchAccountingCycleIDs, LEN(@vchAccountingCycleIDs) - @intPosition)
        SET @intPosition = CHARINDEX(',', @vchAccountingCycleIDs, 1)
    END
END

The concept is pretty much the same. One other alternative is to leverage the .NET compatibility within SQL Server 2005 itself. You can essentially write yourself a simple method in .NET that would split the string and then expose that as a stored procedure/function.

I realize this is a really old question, but starting with SQL Server 2016 there are functions for parsing JSON data that can be used to specifically address the OP's question--and without splitting strings or resorting to a user-defined function. To access an item at a particular index of a delimited string, use the JSON_VALUE function. Properly formatted JSON data is required, however: strings must be enclosed in double quotes " and the delimiter must be a comma ,, with the entire string enclosed in square brackets [].

DECLARE @SampleString NVARCHAR(MAX) = '"Hello John Smith"';
--Format as JSON data.
SET @SampleString = '[' + REPLACE(@SampleString, ' ', '","') + ']';
SELECT 
	JSON_VALUE(@SampleString, '$[0]') AS Element1Value,
	JSON_VALUE(@SampleString, '$[1]') AS Element2Value,
	JSON_VALUE(@SampleString, '$[2]') AS Element3Value;

Output

Element1Value         Element2Value       Element3Value
--------------------- ------------------- ------------------------------
Hello                 John                Smith

(1 row affected)

Using SQL Server 2016 and above. Use this code to TRIM strings, ignore NULL values and apply a row index in the correct order. It also works with a space delimiter:

DECLARE @STRING_VALUE NVARCHAR(MAX) = 'one, two,,three, four,     five'

SELECT ROW_NUMBER() OVER (ORDER BY R.[index]) [index], R.[value] FROM
(
	SELECT
		1 [index], NULLIF(TRIM([value]), '') [value] FROM STRING_SPLIT(@STRING_VALUE, ',') T
	WHERE
		NULLIF(TRIM([value]), '') IS NOT NULL
) R

If you check the following SQL tutorial on splitting string using SQL, you will find a number of functions that can be used to split a given string on SQL Server

For example, SplitAndReturnNth UDF function can be used to split a text using a separator and return the Nth piece as the output of the function

select dbo.SplitAndReturnNth('Hello John Smith',' ',2)

Here's my solution that may help someone. Modification of Jonesinator's answer above.

If I have a string of delimited INT values and want a table of INTs returned (Which I can then join on). e.g. '1,20,3,343,44,6,8765'

Create a UDF:

IF OBJECT_ID(N'dbo.ufn_GetIntTableFromDelimitedList', N'TF') IS NOT NULL
    DROP FUNCTION dbo.[ufn_GetIntTableFromDelimitedList];
GO

CREATE FUNCTION dbo.[ufn_GetIntTableFromDelimitedList](@String NVARCHAR(MAX),                 @Delimiter CHAR(1))

RETURNS @table TABLE 
(
    Value INT NOT NULL
)
AS 
BEGIN
DECLARE @Pattern NVARCHAR(3)
SET @Pattern = '%' + @Delimiter + '%'
DECLARE @Value NVARCHAR(MAX)

WHILE LEN(@String) > 0
	BEGIN
		IF PATINDEX(@Pattern, @String) > 0
		BEGIN
			SET @Value = SUBSTRING(@String, 0, PATINDEX(@Pattern, @String))
			INSERT INTO @table (Value) VALUES (@Value)

			SET @String = SUBSTRING(@String, LEN(@Value + @Delimiter) + 1, LEN(@String))
		END
		ELSE
		BEGIN
			-- Just the one value.
			INSERT INTO @table (Value) VALUES (@String)
			RETURN
		END
	END

RETURN
END
GO

Then get the table results:

SELECT * FROM dbo.[ufn_GetIntTableFromDelimitedList]('1,20,3,343,44,6,8765', ',')

1
20
3
343
44
6
8765

And in a join statement:

SELECT [ID], [FirstName]
FROM [User] u
JOIN dbo.[ufn_GetIntTableFromDelimitedList]('1,20,3,343,44,6,8765', ',') t ON u.[ID] = t.[Value]

1    Elvis
20   Karen
3    David
343  Simon
44   Raj
6    Mike
8765 Richard

If you want to return a list of NVARCHARs instead of INTs then just change the table definition:

RETURNS @table TABLE 
(
    Value NVARCHAR(MAX) NOT NULL
)

Here is a SQL UDF that can split a string and grab just a certain piece.

create FUNCTION [dbo].[udf_SplitParseOut]
(
	@List nvarchar(MAX),
	@SplitOn nvarchar(5),
	@GetIndex smallint
)  
returns varchar(1000)
AS  

BEGIN

DECLARE @RtnValue table 
(
		
	Id int identity(0,1),
	Value nvarchar(MAX)
) 


	DECLARE @result varchar(1000)

	While (Charindex(@SplitOn,@List)>0)
	Begin
		Insert Into @RtnValue (value)
		Select Value = ltrim(rtrim(Substring(@List,1,Charindex(@SplitOn,@List)-1)))
		Set @List = Substring(@List,Charindex(@SplitOn,@List)+len(@SplitOn),len(@List))
	End
	
    Insert Into @RtnValue (Value)
    Select Value = ltrim(rtrim(@List))

	select @result = value from @RtnValue where ID = @GetIndex

    Return @result
END

A simple optimized algorithm :

ALTER FUNCTION [dbo].[Split]( @Text NVARCHAR(200),@Splitor CHAR(1) )
RETURNS @Result TABLE ( value NVARCHAR(50)) 
AS
BEGIN
	DECLARE @PathInd INT
	Set @Text+=@Splitor
	WHILE LEN(@Text) > 0
	BEGIN
		SET @PathInd=PATINDEX('%'+@Splitor+'%',@Text)
		INSERT INTO  @Result VALUES(SUBSTRING(@Text, 0, @PathInd))
		SET @Text= SUBSTRING(@Text, @PathInd+1, LEN(@Text))
	END
		RETURN 
END

I've been using vzczc's answer using recursive cte's for some time, but have wanted to update it to handle a variable length separator and also to handle strings with leading and lagging "separators" such as when you have a csv file with records such as:

"Bob","Smith","Sunnyvale","CA"

or when you are dealing with six part fqn's as shown below. I use these extensively for logging of the subject_fqn for auditing, error handling, etc. and parsename only handles four parts:

[netbios_name].[machine_name].[instance].[database].[schema].[table].[column]

Here is my updated version, and thanks to vzczc's for his original post!

select * from [utility].[split_string](N'"this"."string"."gets"."split"."and"."removes"."leading"."and"."trailing"."quotes"', N'"."', N'"', N'"');

select * from [utility].[split_string](N'"this"."string"."gets"."split"."but"."leaves"."leading"."and"."trailing"."quotes"', N'"."', null, null);

select * from [utility].[split_string](N'[netbios_name].[machine_name].[instance].[database].[schema].[table].[column]', N'].[', N'[', N']');

create function [utility].[split_string] ( 
  @input       [nvarchar](max) 
  , @separator [sysname] 
  , @lead      [sysname] 
  , @lag       [sysname]) 
returns @node_list table ( 
  [index]  [int] 
  , [node] [nvarchar](max)) 
  begin 
      declare @separator_length [int]= len(@separator) 
              , @lead_length    [int] = isnull(len(@lead), 0) 
              , @lag_length     [int] = isnull(len(@lag), 0); 
      -- 
      set @input = right(@input, len(@input) - @lead_length); 
      set @input = left(@input, len(@input) - @lag_length); 
      -- 
      with [splitter]([index], [starting_position], [start_location]) 
           as (select cast(@separator_length as [bigint]) 
                      , cast(1 as [bigint]) 
                      , charindex(@separator, @input) 
               union all 
               select [index] + 1 
                      , [start_location] + @separator_length 
                      , charindex(@separator, @input, [start_location] + @separator_length) 
               from   [splitter] 
               where  [start_location] > 0) 
      -- 
      insert into @node_list 
                  ([index],[node]) 
        select [index] - @separator_length                   as [index] 
               , substring(@input, [starting_position], case 
                                                            when [start_location] > 0 
                                                                then 
                                                              [start_location] - [starting_position] 
                                                            else 
                                                              len(@input) 
                                                        end) as [node] 
        from   [splitter]; 
      -- 
      return; 
  end; 
go