How do I get difference between two dates in android?, tried every thing and post

JavaAndroidDateTime

Java Problem Overview


I saw all the post in here and still I can't figure how do get difference between two android dates.

This is what I do:

long diff = date1.getTime() - date2.getTime();
Date diffDate = new Date(diff);

and I get: the date is Jan. 1, 1970 and the time is always bigger in two hours...I'm from Israel so the two hours is timeOffset.

How can I get normal difference???

Java Solutions


Solution 1 - Java

You're close to the right answer, you are getting the difference in milliseconds between those two dates, but when you attempt to construct a date out of that difference, it is assuming you want to create a new Date object with that difference value as its epoch time. If you're looking for a time in hours, then you would simply need to do some basic arithmetic on that diff to get the different time parts.

Java:

long diff = date1.getTime() - date2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;

Kotlin:

val diff: Long = date1.getTime() - date2.getTime()
val seconds = diff / 1000
val minutes = seconds / 60
val hours = minutes / 60
val days = hours / 24

All of this math will simply do integer arithmetic, so it will truncate any decimal points

Solution 2 - Java

    long diffInMillisec = date1.getTime() - date2.getTime();

    long diffInDays = TimeUnit.MILLISECONDS.toDays(diffInMillisec);
    long diffInHours = TimeUnit.MILLISECONDS.toHours(diffInMillisec);
    long diffInMin = TimeUnit.MILLISECONDS.toMinutes(diffInMillisec);
    long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMillisec);

Solution 3 - Java

Some addition: Here I convert string to date then I compare the current time.

String toyBornTime = "2014-06-18 12:56:50";
	SimpleDateFormat dateFormat = new SimpleDateFormat(
			"yyyy-MM-dd HH:mm:ss");

	try {

		Date oldDate = dateFormat.parse(toyBornTime);
		System.out.println(oldDate);

		Date currentDate = new Date();

		long diff = currentDate.getTime() - oldDate.getTime();
		long seconds = diff / 1000;
		long minutes = seconds / 60;
		long hours = minutes / 60;
		long days = hours / 24;

		if (oldDate.before(currentDate)) {

			Log.e("oldDate", "is previous date");
			Log.e("Difference: ", " seconds: " + seconds + " minutes: " + minutes
					+ " hours: " + hours + " days: " + days);

		}

		// Log.e("toyBornTime", "" + toyBornTime);

	} catch (ParseException e) {

		e.printStackTrace();
	}

Solution 4 - Java

java.time.Duration

Use java.time.Duration:

	Duration diff = Duration.between(instant2, instant1);
	System.out.println(diff);

This will print something like

PT109H27M21S

This means a period of time of 109 hours 27 minutes 21 seconds. If you want someting more human-readable — I’ll give the Java 9 version first, it’s simplest:

	String formattedDiff = String.format(Locale.ENGLISH,
			"%d days %d hours %d minutes %d seconds",
			diff.toDays(), diff.toHoursPart(), diff.toMinutesPart(), diff.toSecondsPart());
	System.out.println(formattedDiff);

Now we get

4 days 13 hours 27 minutes 21 seconds

The Duration class is part of java.time the modern Java date and time API. This is bundled on newer Android devices. On older devices, get ThreeTenABP and add it to your project, and make sure to import org.threeten.bp.Duration and other date-time classes you may need from the same package.

Assuming you still haven’t got the Java 9 version, you may subtract the larger units in turn to get the smaller ones:

	long days = diff.toDays();
	diff = diff.minusDays(days);
	long hours = diff.toHours();
	diff = diff.minusHours(hours);
	long minutes = diff.toMinutes();
	diff = diff.minusMinutes(minutes);
	long seconds = diff.toSeconds();

Then you can format the four variables as above.

What did you do wrong?

A Date represents a point in time. It was never meant for representing an amount of time, a duration, and it isn’t suited for it. Trying to make that work would at best lead to confusing and hard-to-maintain code. You don’t want that, so please don’t.

Question: Doesn’t java.time require Android API level 26?

java.time works nicely on both older and newer Android devices. It just requires at least Java 6.

  • In Java 8 and later and on newer Android devices (from API level 26) the modern API comes built-in.
  • In non-Android Java 6 and 7 get the ThreeTen Backport, the backport of the modern classes (ThreeTen for JSR 310; see the links at the bottom).
  • On (older) Android use the Android edition of ThreeTen Backport. It’s called ThreeTenABP. And make sure you import the date and time classes from org.threeten.bp with subpackages.

Solution 5 - Java

What about using Instant:

val instant1 = now()
val instant2 = now()
val diff: Duration = Duration.between(instant1, instant2)
val minutes = diff.toMinutes()

You can even save your Instant using instant1.toString() and parse that string with parse(string).

If you need to support Android API level < 26 just add Java 8+ API desugaring support to your project.

Solution 6 - Java

If you use Kotlin language for Android development you can get difference in days like this:

fun daysDiff(c1: Calendar, c2: Calendar): Long {
    val diffInMillis = c1.timeInMillis - c2.timeInMillis
    return diffInMillis.milliseconds.inWholeDays
}

or if you want to get results in different type you can replace inWholeDays with toInt(...), toDouble(...), toString(...).

If the only date difference you're interested in is days (let's say as a Double type result) you can create operator extension method like this:

operator fun Calendar.minus(c: Calendar): Double {
    val diffInMillis = timeInMillis - c.timeInMillis
    return diffInMillis.milliseconds.toDouble(DurationUnit.DAYS)
}

And then any operation like calendar2 - calendar1 will return difference in days as Double.

Solution 7 - Java

Here is my answer based on @Ole V. V. answer.

This also works with Singular.

private String getDuration(Date d1, Date d2) {
    Duration diff = Duration.between(d1.toInstant(), d2.toInstant());


    long days = diff.toDays();
    diff = diff.minusDays(days);
    long hours = diff.toHours();
    diff = diff.minusHours(hours);
    long minutes = diff.toMinutes();
    diff = diff.minusMinutes(minutes);
    long seconds = diff.toMillis();

    StringBuilder formattedDiff = new StringBuilder();
    if(days!=0){
        if(days==1){
            formattedDiff.append(days + " Day ");

        }else {
            formattedDiff.append(days + " Days ");
        }
    }if(hours!=0){
        if(hours==1){
            formattedDiff.append(hours + " hour ");
        }else{
            formattedDiff.append(hours + " hours ");
        }
    }if(minutes!=0){
        if(minutes==1){
            formattedDiff.append(minutes + " minute ");
        }else{
            formattedDiff.append(minutes + " minutes ");
        }
    }if(seconds!=0){
        if(seconds==1){
            formattedDiff.append(seconds + " second ");
        }else{
            formattedDiff.append(seconds + " seconds ");
        }
    }


    return formattedDiff.toString();
}

It works with a StringBuilder to append everything together.

Solution 8 - Java

I tried this method..but don't know why I am not getting proper result

long diff = date1.getTime() - date2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;

But this works

long miliSeconds = date1.getTime() -date2.getTime();
long seconds = TimeUnit.MILLISECONDS.toSeconds(miliSeconds);
long minute = seconds/60;
long hour = minute/60;
long days = hour/24;

Solution 9 - Java

Using georgian calander

 public void dateDifferenceExample() {

        // Set the date for both of the calendar instance
        GregorianCalendar calDate = new GregorianCalendar(2012, 10, 02,5,23,43);
        GregorianCalendar cal2 = new GregorianCalendar(2015, 04, 02);

        // Get the represented date in milliseconds
        long millis1 = calDate.getTimeInMillis();
        long millis2 = cal2.getTimeInMillis();

        // Calculate difference in milliseconds
        long diff = millis2 - millis1;

        // Calculate difference in seconds
        long diffSeconds = diff / 1000;

        // Calculate difference in minutes
        long diffMinutes = diff / (60 * 1000);

        // Calculate difference in hours
        long diffHours = diff / (60 * 60 * 1000);

        // Calculate difference in days
        long diffDays = diff / (24 * 60 * 60 * 1000);
    Toast.makeText(getContext(), ""+diffSeconds, Toast.LENGTH_SHORT).show();


}

Solution 10 - Java

Use these functions

    public static int getDateDifference(
        int previousYear, int previousMonthOfYear, int previousDayOfMonth,
        int nextYear, int nextMonthOfYear, int nextDayOfMonth,
        int differenceToCount){
    // int differenceToCount = can be any of the following
    //  Calendar.MILLISECOND;
    //  Calendar.SECOND;
    //  Calendar.MINUTE;
    //  Calendar.HOUR;
    //  Calendar.DAY_OF_MONTH;
    //  Calendar.MONTH;
    //  Calendar.YEAR;
    //  Calendar.----

    Calendar previousDate = Calendar.getInstance();
    previousDate.set(Calendar.DAY_OF_MONTH, previousDayOfMonth);
    // month is zero indexed so month should be minus 1
    previousDate.set(Calendar.MONTH, previousMonthOfYear);
    previousDate.set(Calendar.YEAR, previousYear);

    Calendar nextDate = Calendar.getInstance();
    nextDate.set(Calendar.DAY_OF_MONTH, previousDayOfMonth);
    // month is zero indexed so month should be minus 1
    nextDate.set(Calendar.MONTH, previousMonthOfYear);
    nextDate.set(Calendar.YEAR, previousYear);

    return getDateDifference(previousDate,nextDate,differenceToCount);
}
public static int getDateDifference(Calendar previousDate,Calendar nextDate,int differenceToCount){
    // int differenceToCount = can be any of the following
    //  Calendar.MILLISECOND;
    //  Calendar.SECOND;
    //  Calendar.MINUTE;
    //  Calendar.HOUR;
    //  Calendar.DAY_OF_MONTH;
    //  Calendar.MONTH;
    //  Calendar.YEAR;
    //  Calendar.----

    //raise an exception if previous is greater than nextdate.
    if(previousDate.compareTo(nextDate)>0){
        throw new RuntimeException("Previous Date is later than Nextdate");
    }

    int difference=0;
    while(previousDate.compareTo(nextDate)<=0){
        difference++;
        previousDate.add(differenceToCount,1);
    }
    return difference;
}

Solution 11 - Java

written in Kotlin: if you need difference between 2 dates and don't care about the dates itself ( good if you need to do something in the app,based on time from other operation time that was saved in shared preferences for example). save first time :

val firstTime:Long= System.currentTimeMillis()
                    

save second time:

val now:Long= System.currentTimeMillis()

calculate the miliseconds between 2 times:

val milisecondsSinceLastTime: Long =(now-lastScrollTime)

Solution 12 - Java

Get time difference between AM and PM

private int  getTimeDiff() {
    SimpleDateFormat sdf = new SimpleDateFormat("hh:mm:ss aa");
    Date systemDate = Calendar.getInstance().getTime();
    String myDate = sdf.format(systemDate);
    Date current = null;
    Date Date2 = null;
    try {
        current = sdf.parse(myDate);
        // current = sdf.parse("05:00:00 pm");
        Date2 = sdf.parse("12:00:00 am");
    } catch (ParseException e) {
        e.printStackTrace();
    }
    long millse = Date2.getTime() - current.getTime();
    long mills = Math.abs(millse);
    int Hours = (int) (mills / (1000 * 60 * 60));
    int Mins = (int) (mills / (1000 * 60)) % 60;
    long Secs = (int) (mills / 1000) % 60;
    String diff = Hours + ":" + Mins + ":" + Secs;
    int min = 60-Mins;
    if (Hours >= 12) {
        String requiredTime = 24 - Hours + ":" + Mins + ":" + Secs;
        int minutes= ((24-Hours)*60)-Mins;
        return minutes;

    } else {
        int time = 12 - Hours;
        int hours=time+12;
        int res = (hours*60);
        int minutes = res-Mins;
        return minutes;
    }
}

Solution 13 - Java

when you attempt to construct a date out of that difference, it is assuming you want to create a new Date object with that difference value as its epoch time.

//get time in milliseconds
long diff = date1.getTime() - date2.getTime();
//get time in seconds
long seconds = diff / 1000;
//and so on
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;

for more information you could use these links:

Oracle tutorial: Date Time, explaining how to use java.time.

ThreeTen Backport project, the backport of java.time to Java 6 and 7.

ThreeTenABP, Android edition of ThreeTen Backport.

Question: How to use ThreeTenABP in Android Project, with a very thorough explanation.

Solution 14 - Java

shortest answer that works for me. send start and end date in millisecond.

public int GetDifference(long start,long end){
    Calendar cal = Calendar.getInstance();
    cal.setTimeInMillis(start);
    int hour = cal.get(Calendar.HOUR_OF_DAY);
    int min = cal.get(Calendar.MINUTE);
    long t=(23-hour)*3600000+(59-min)*60000;

    t=start+t;

    int diff=0;
    if(end>t){
        diff=(int)((end-t)/ TimeUnit.DAYS.toMillis(1))+1;
    }

    return  diff;
}

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QuestionAlex KapustianView Question on Stackoverflow
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Solution 3 - JavaShihab UddinView Answer on Stackoverflow
Solution 4 - JavaOle V.V.View Answer on Stackoverflow
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