How do I check to see if a value is an integer in MySQL?

Mysql

Mysql Problem Overview


I see that within MySQL there are Cast() and Convert() functions to create integers from values, but is there any way to check to see if a value is an integer? Something like is_int() in PHP is what I am looking for.

Mysql Solutions


Solution 1 - Mysql

I'll assume you want to check a string value. One nice way is the REGEXP operator, matching the string to a regular expression. Simply do

select field from table where field REGEXP '^-?[0-9]+$';

this is reasonably fast. If your field is numeric, just test for

ceil(field) = field

instead.

Solution 2 - Mysql

Match it against a regular expression.

c.f. http://forums.mysql.com/read.php?60,1907,38488#msg-38488 as quoted below:

>Re: IsNumeric() clause in MySQL?? >
Posted by: kevinclark () >
Date: August 08, 2005 01:01PM > >
I agree. Here is a function I created for MySQL 5:

CREATE FUNCTION IsNumeric (sIn varchar(1024)) RETURNS tinyint
RETURN sIn REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$';

>
This allows for an optional plus/minus sign at the beginning, one optional decimal point, and the rest numeric digits.

Solution 3 - Mysql

Suppose we have column with alphanumeric field having entries like

a41q
1458
xwe8
1475
asde
9582
.
.
.
.
.
qe84

and you want highest numeric value from this db column (in this case it is 9582) then this query will help you

SELECT Max(column_name) from table_name where column_name REGEXP '^[0-9]+$'

Solution 4 - Mysql

Here is the simple solution for it assuming the data type is varchar

select * from calender where year > 0

It will return true if the year is numeric else false

Solution 5 - Mysql

This also works:

CAST( coulmn_value AS UNSIGNED ) // will return 0 if not numeric string.

for example

SELECT CAST('a123' AS UNSIGNED) // returns 0
SELECT CAST('123' AS UNSIGNED) // returns 123 i.e. > 0

Solution 6 - Mysql

To check if a value is Int in Mysql, we can use the following query. This query will give the rows with Int values

SELECT col1 FROM table WHERE concat('',col * 1) = col;

Solution 7 - Mysql

The best i could think of a variable is a int Is a combination with MySQL's functions CAST() and LENGTH().
This method will work on strings, integers, doubles/floats datatypes.

SELECT (LENGTH(CAST(<data> AS UNSIGNED))) = (LENGTH(<data>)) AS is_int

see demo http://sqlfiddle.com/#!9/ff40cd/44

> it will fail if the column has a single character value. if column has > a value 'A' then Cast('A' as UNSIGNED) will evaluate to 0 and > LENGTH(0) will be 1. so LENGTH(Cast('A' as UNSIGNED))=LENGTH(0) will > evaluate to 1=1 => 1

True Waqas Malik totally fogotten to test that case. the patch is.

SELECT <data>, (LENGTH(CAST(<data> AS UNSIGNED))) = CASE WHEN CAST(<data> AS UNSIGNED) = 0 THEN CAST(<data> AS UNSIGNED) ELSE (LENGTH(<data>)) END AS is_int;

Results

**Query #1**

    SELECT 1, (LENGTH(CAST(1 AS UNSIGNED))) = CASE WHEN CAST(1 AS UNSIGNED) = 0 THEN CAST(1 AS UNSIGNED) ELSE (LENGTH(1)) END AS is_int;

| 1   | is_int |
| --- | ------ |
| 1   | 1      |

---
**Query #2**

    SELECT 1.1, (LENGTH(CAST(1 AS UNSIGNED))) = CASE WHEN CAST(1.1 AS UNSIGNED) = 0 THEN CAST(1.1 AS UNSIGNED) ELSE (LENGTH(1.1)) END AS is_int;

| 1.1 | is_int |
| --- | ------ |
| 1.1 | 0      |

---
**Query #3**

    SELECT "1", (LENGTH(CAST("1" AS UNSIGNED))) = CASE WHEN CAST("1" AS UNSIGNED) = 0 THEN CAST("1" AS UNSIGNED) ELSE (LENGTH("1")) END AS is_int;

| 1   | is_int |
| --- | ------ |
| 1   | 1      |

---
**Query #4**

    SELECT "1.1", (LENGTH(CAST("1.1" AS UNSIGNED))) = CASE WHEN CAST("1.1" AS UNSIGNED) = 0 THEN CAST("1.1" AS UNSIGNED) ELSE (LENGTH("1.1")) END AS is_int;

| 1.1 | is_int |
| --- | ------ |
| 1.1 | 0      |

---
**Query #5**

    SELECT "1a", (LENGTH(CAST("1.1" AS UNSIGNED))) = CASE WHEN CAST("1a" AS UNSIGNED) = 0 THEN CAST("1a" AS UNSIGNED) ELSE (LENGTH("1a")) END AS is_int;

| 1a  | is_int |
| --- | ------ |
| 1a  | 0      |

---
**Query #6**

    SELECT "1.1a", (LENGTH(CAST("1.1a" AS UNSIGNED))) = CASE WHEN CAST("1.1a" AS UNSIGNED) = 0 THEN CAST("1.1a" AS UNSIGNED) ELSE (LENGTH("1.1a")) END AS is_int;

| 1.1a | is_int |
| ---- | ------ |
| 1.1a | 0      |

---
**Query #7**

    SELECT "a1", (LENGTH(CAST("1.1a" AS UNSIGNED))) = CASE WHEN CAST("a1" AS UNSIGNED) = 0 THEN CAST("a1" AS UNSIGNED) ELSE (LENGTH("a1")) END AS is_int;

| a1  | is_int |
| --- | ------ |
| a1  | 0      |

---
**Query #8**

    SELECT "a1.1", (LENGTH(CAST("a1.1" AS UNSIGNED))) = CASE WHEN CAST("a1.1" AS UNSIGNED) = 0 THEN CAST("a1.1" AS UNSIGNED) ELSE (LENGTH("a1.1")) END AS is_int;

| a1.1 | is_int |
| ---- | ------ |
| a1.1 | 0      |

---
**Query #9**

    SELECT "a", (LENGTH(CAST("a" AS UNSIGNED))) = CASE WHEN CAST("a" AS UNSIGNED) = 0 THEN CAST("a" AS UNSIGNED) ELSE (LENGTH("a")) END AS is_int;

| a   | is_int |
| --- | ------ |
| a   | 0      |

see demo

Solution 8 - Mysql

What about:

WHERE table.field = "0" or CAST(table.field as SIGNED) != 0

to test for numeric and the corrolary:

WHERE table.field != "0" and CAST(table.field as SIGNED) = 0

Solution 9 - Mysql

I have tried using the regular expressions listed above, but they do not work for the following:

SELECT '12 INCHES' REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$' FROM ...

The above will return 1 (TRUE), meaning the test of the string '12 INCHES' against the regular expression above, returns TRUE. It looks like a number based on the regular expression used above. In this case, because the 12 is at the beginning of the string, the regular expression interprets it as a number.

The following will return the right value (i.e. 0) because the string starts with characters instead of digits

SELECT 'TOP 10' REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$' FROM ...

The above will return 0 (FALSE) because the beginning of the string is text and not numeric.

However, if you are dealing with strings that have a mix of numbers and letters that begin with a number, you will not get the results you want. REGEXP will interpret the string as a valid number when in fact it is not.

Solution 10 - Mysql

This works well for VARCHAR where it begins with a number or not..

WHERE concat('',fieldname * 1) != fieldname 

may have restrictions when you get to the larger NNNNE+- numbers

Solution 11 - Mysql

for me the only thing that works is:

CREATE FUNCTION IsNumeric (SIN VARCHAR(1024)) RETURNS TINYINT
RETURN SIN REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$';

from kevinclark all other return useless stuff for me in case of 234jk456 or 12 inches

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionCraig NakamotoView Question on Stackoverflow
Solution 1 - MysqlJumpyView Answer on Stackoverflow
Solution 2 - MysqlJBBView Answer on Stackoverflow
Solution 3 - MysqlTarun SoodView Answer on Stackoverflow
Solution 4 - MysqlJayjitrajView Answer on Stackoverflow
Solution 5 - MysqlRiadView Answer on Stackoverflow
Solution 6 - Mysqlminhas23View Answer on Stackoverflow
Solution 7 - MysqlRaymond NijlandView Answer on Stackoverflow
Solution 8 - MysqlTom AugerView Answer on Stackoverflow
Solution 9 - MysqlBill KellyView Answer on Stackoverflow
Solution 10 - MysqlPodTech.ioView Answer on Stackoverflow
Solution 11 - MysqlTimView Answer on Stackoverflow