How do I check if a date is within a certain range?

Java Problem Overview

I have a series of ranges with start dates and end dates. I want to check to see if a date is within that range.

Date.before() and Date.after() seem to be a little awkward to use. What I really need is something like this pseudocode:

boolean isWithinRange(Date testDate) {
    return testDate >= startDate && testDate <= endDate;
}

Not sure if it's relevant, but the dates I'm pulling from the database have timestamps.

Java Solutions

Solution 1 - Java

boolean isWithinRange(Date testDate) {
   return !(testDate.before(startDate) || testDate.after(endDate));
}

Doesn't seem that awkward to me. Note that I wrote it that way instead of

return testDate.after(startDate) && testDate.before(endDate);

so it would work even if testDate was exactly equal to one of the end cases.

Solution 2 - Java

tl;dr

ZoneId z = ZoneId.of( "America/Montreal" );  // A date only has meaning within a specific time zone. At any given moment, the date varies around the globe by zone.
LocalDate ld = 
    givenJavaUtilDate.toInstant()  // Convert from legacy class `Date` to modern class `Instant` using new methods added to old classes.
                     .atZone( z )  // Adjust into the time zone in order to determine date.
                     .toLocalDate();  // Extract date-only value.

LocalDate today = LocalDate.now( z );  // Get today’s date for specific time zone.
LocalDate kwanzaaStart = today.withMonth( Month.DECEMBER ).withDayOfMonth( 26 );  // Kwanzaa starts on Boxing Day, day after Christmas.
LocalDate kwanzaaStop = kwanzaaStart.plusWeeks( 1 );  // Kwanzaa lasts one week.
Boolean isDateInKwanzaaThisYear = (
    ( ! today.isBefore( kwanzaaStart ) ) // Short way to say "is equal to or is after".
    &&
    today.isBefore( kwanzaaStop )  // Half-Open span of time, beginning inclusive, ending is *exclusive*.
)

Half-Open

Date-time work commonly employs the "Half-Open" approach to defining a span of time. The beginning is inclusive while the ending is exclusive. So a week starting on a Monday runs up to, but does not include, the following Monday.

java.time

Java 8 and later comes with the java.time framework built-in. Supplants the old troublesome classes including java.util.Date/.Calendar and SimpleDateFormat. Inspired by the successful Joda-Time library. Defined by JSR 310. Extended by the ThreeTen-Extra project.

An Instant is a moment on the timeline in UTC with nanosecond resolution.

`Instant`

Convert your java.util.Date objects to Instant objects.

Instant start = myJUDateStart.toInstant();
Instant stop = …

If getting java.sql.Timestamp objects through JDBC from a database, convert to java.time.Instant in a similar way. A java.sql.Timestamp is already in UTC so no need to worry about time zones.

Instant start = mySqlTimestamp.toInstant() ;
Instant stop = …

Get the current moment for comparison.

Instant now = Instant.now();

Compare using the methods isBefore, isAfter, and equals.

Boolean containsNow = ( ! now.isBefore( start ) ) && ( now.isBefore( stop ) ) ;

`LocalDate`

Perhaps you want to work with only the date, not the time-of-day.

The LocalDate class represents a date-only value, without time-of-day and without time zone.

LocalDate start = LocalDate.of( 2016 , 1 , 1 ) ;
LocalDate stop = LocalDate.of( 2016 , 1 , 23 ) ;

To get the current date, specify a time zone. At any given moment, today’s date varies by time zone. For example, a new day dawns earlier in Paris than in Montréal.

LocalDate today = LocalDate.now( ZoneId.of( "America/Montreal" ) );

We can use the isEqual, isBefore, and isAfter methods to compare. In date-time work we commonly use the Half-Open approach where the beginning of a span of time is inclusive while the ending is exclusive.

Boolean containsToday = ( ! today.isBefore( start ) ) && ( today.isBefore( stop ) ) ;

`Interval`

If you chose to add the ThreeTen-Extra library to your project, you could use the Interval class to define a span of time. That class offers methods to test if the interval contains, abuts, encloses, or overlaps other date-times/intervals.

The Interval class works on Instant objects. The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds (up to nine (9) digits of a decimal fraction).

We can adjust the LocalDate into a specific moment, the first moment of the day, by specifying a time zone to get a ZonedDateTime. From there we can get back to UTC by extracting a Instant.

ZoneId z = ZoneId.of( "America/Montreal" );
Interval interval = 
    Interval.of( 
        start.atStartOfDay( z ).toInstant() , 
        stop.atStartOfDay( z ).toInstant() );
Instant now = Instant.now();
Boolean containsNow = interval.contains( now );

About java.time

The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.

The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.

To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.

Where to obtain the java.time classes?

Java SE 8 and SE 9 and later
Built-in.
Part of the standard Java API with a bundled implementation.
Java 9 adds some minor features and fixes.
Java SE 6 and SE 7
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
The ThreeTenABP project adapts ThreeTen-Backport (mentioned above) for Android specifically.
See How to use….

The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.

Solution 3 - Java

That's the correct way. Calendars work the same way. The best I could offer you (based on your example) is this:

boolean isWithinRange(Date testDate) {
    return testDate.getTime() >= startDate.getTime() &&
             testDate.getTime() <= endDate.getTime();
}

Date.getTime() returns the number of milliseconds since 1/1/1970 00:00:00 GMT, and is a long so it's easily comparable.

Solution 4 - Java

Consider using Joda Time. I love this library and wish it would replace the current horrible mess that are the existing Java Date and Calendar classes. It's date handling done right.

EDIT: It's not 2009 any more, and Java 8's been out for ages. Use Java 8's built in java.time classes which are based on Joda Time, as Basil Bourque mentions above. In this case you'll want the Period class, and here's Oracle's tutorial on how to use it.

Solution 5 - Java

An easy way is to convert the dates into milliseconds after January 1, 1970 (use Date.getTime()) and then compare these values.

Solution 6 - Java

Since `Java 8`

NOTE: All, but one, Date's constructors are deprecated. Most of the Date's methods are deprecated. REF: Date: Deprecated Methods. All, but Date::from(Instant), static methods are deprecated.

So, since java 8 consider using Instant (immutable, thread-safe, leap-seconds aware) type rather than Date. REF: Instant

  static final LocalTime MARKETS_OPEN = LocalTime.of(07, 00);
  static final LocalTime MARKETS_CLOSE = LocalTime.of(20, 00);

    // Instant utcTime = testDate.toInstant();
    var bigAppleTime = ZonedDateTime.ofInstant(utcTime, ZoneId.of("America/New_York"));

within the range INCLUSIVE:

    return !bigAppleTime.toLocalTime().isBefore(MARKETS_OPEN)
        && !bigAppleTime.toLocalTime().isAfter(MARKETS_CLOSE);

within the range EXCLUSIVE:

    return bigAppleTime.toLocalTime().isAfter(MARKETS_OPEN)
        && bigAppleTime.toLocalTime().isBefore(MARKETS_CLOSE);

Solution 7 - Java

if you want inclusive comparison with LocalDate then use this code.

LocalDate from = LocalDate.of(2021,8,1);
LocalDate to = LocalDate.of(2021,8,1);
LocalDate current = LocalDate.of(2021,8,1);

boolean isDateInRage = ( ! (current.isBefore(from.minusDays(1)) && current.isBefore(to.plusDays(1))) );

Solution 8 - Java

This was clearer to me,

// declare calendar outside the scope of isWithinRange() so that we initialize it only once
private Calendar calendar = Calendar.getInstance();

public boolean isWithinRange(Date date, Date startDate, Date endDate) {

    calendar.setTime(startDate);
    int startDayOfYear = calendar.get(Calendar.DAY_OF_YEAR); // first day is 1, last day is 365
    int startYear = calendar.get(Calendar.YEAR);

    calendar.setTime(endDate);
    int endDayOfYear = calendar.get(Calendar.DAY_OF_YEAR);
    int endYear = calendar.get(Calendar.YEAR);

    calendar.setTime(date);
    int dayOfYear = calendar.get(Calendar.DAY_OF_YEAR);
    int year = calendar.get(Calendar.YEAR);

    return (year > startYear && year < endYear) // year is within the range
            || (year == startYear && dayOfYear >= startDayOfYear) // year is same as start year, check day as well
            || (year == endYear && dayOfYear < endDayOfYear); // year is same as end year, check day as well

}

Solution 9 - Java

For covering my case -> I've got a range start & end date, and dates list that can be as partly in provided range, as fully (overlapping).

Solution covered with tests:

/**
 * Check has any of quote work days in provided range.
 *
 * @param startDate inclusively
 * @param endDate   inclusively
 *
 * @return true if any in provided range inclusively
 */
public boolean hasAnyWorkdaysInRange(LocalDate startDate, LocalDate endDate) {
    if (CollectionUtils.isEmpty(workdays)) {
        return false;
    }

    LocalDate firstWorkDay = getFirstWorkDay().getDate();
    LocalDate lastWorkDay = getLastWorkDay().getDate();

    return (firstWorkDay.isBefore(endDate) || firstWorkDay.equals(endDate))
            && (lastWorkDay.isAfter(startDate) || lastWorkDay.equals(startDate));
}

Solution 10 - Java

Doesnn't care which date boundry is which.

Math.abs(date1.getTime() - date2.getTime()) == 
    Math.abs(date1.getTime() - dateBetween.getTime()) + Math.abs(dateBetween.getTime() - date2.getTime());

Solution 11 - Java

you can use like this

Interval interval = new Interval(date1.getTime(),date2.getTime());
Interval interval2 = new Interval(date3.getTime(), date4.getTime());
Interval overlap = interval.overlap(interval2);
boolean isOverlap = overlap == null ? false : true

Solution 12 - Java

  public class TestDate {

    public static void main(String[] args) {
	// TODO Auto-generated method stub
	
	String fromDate = "18-FEB-2018";
	String toDate = "20-FEB-2018";
	
	String requestDate = "19/02/2018";	
	System.out.println(checkBetween(requestDate,fromDate, toDate));
}

public static boolean checkBetween(String dateToCheck, String startDate, String endDate) {
	boolean res = false;
	SimpleDateFormat fmt1 = new SimpleDateFormat("dd-MMM-yyyy"); //22-05-2013
	SimpleDateFormat fmt2 = new SimpleDateFormat("dd/MM/yyyy"); //22-05-2013
	try {
	 Date requestDate = fmt2.parse(dateToCheck);
	 Date fromDate = fmt1.parse(startDate);
	 Date toDate = fmt1.parse(endDate);
	 res = requestDate.compareTo(fromDate) >= 0 && requestDate.compareTo(toDate) <=0;
	}catch(ParseException pex){
		pex.printStackTrace();
	}
	return res;
   }
 }

Solution 13 - Java

Adding new solution if the date is equals to start date:

boolean isWithinRange(Date testDate) {
   return !(testDate.before(startDate) || testDate.after(endDate));
}

Solution

return testDate.equals(startDate) || (testDate.after(startDate) && 
testDate.before(endDate)) || testDate.equals(endDate);

Solution 14 - Java

    public boolean isBetween(LocalDate target, LocalDate min, LocalDate max) {
    if (target == null || min == null || max == null) {
        throw new IllegalArgumentException("paramettres can't be null");
    }

    return target.compareTo(min) >= 0 && target.compareTo(max) <= 0;
}

Solution 15 - Java

A solution will be to check date with after and before method. If is required to consider inclusive endDate, testDate.before(endDate) returns false when testDate and endDate are the same day, we can use "apache commons lang" package to verify this (org.apache.commons.lang.time.DateUtils)

import org.apache.commons.lang.time.DateUtils;

boolean isWithinRange(Date testDate) {
    return   testDate.after(startDate) && (testDate.before(endDate) || DateUtils.isSameDay(testDate, endDate));
}

Solution 16 - Java

your logic would work fine . As u mentioned the dates ur getting from the database are in timestamp , You just need to convert timestamp to date first and then use this logic.

Also dont forget to check for null dates.

here m sharing a bit to convert from Timestamp to date.

public static Date convertTimeStamptoDate(String val) throws Exception {

	DateFormat df = null;
	Date date = null;

	try {
		df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
		date = df.parse(val);
		// System.out.println("Date Converted..");
		return date;
	} catch (Exception ex) {
		System.out.println(ex);
		return convertDate2(val);
	} finally {
		df = null;
		date = null;
	}
}

Solution 17 - Java

google guava

Range.closed(start, end)
            .isConnected(Range.closed(now, now));

Content Type	Original Author	Original Content on Stackoverflow
Question	Mike Sickler	View Question on Stackoverflow
Solution 1 - Java	Paul Tomblin	View Answer on Stackoverflow
Solution 2 - Java	Basil Bourque	View Answer on Stackoverflow
Solution 3 - Java	MBCook	View Answer on Stackoverflow
Solution 4 - Java	Ben Hardy	View Answer on Stackoverflow
Solution 5 - Java	Rahul	View Answer on Stackoverflow
Solution 6 - Java	epox	View Answer on Stackoverflow
Solution 7 - Java	keval dholakiya	View Answer on Stackoverflow
Solution 8 - Java	Dhunju_likes_to_Learn	View Answer on Stackoverflow
Solution 9 - Java	Oleksandr Yefymov	View Answer on Stackoverflow
Solution 10 - Java	Radu	View Answer on Stackoverflow
Solution 11 - Java	Koray Peker	View Answer on Stackoverflow
Solution 12 - Java	rashedmedisys	View Answer on Stackoverflow
Solution 13 - Java	Ricardo De Leon	View Answer on Stackoverflow
Solution 14 - Java	Mohammed El Amine Mahmoudi	View Answer on Stackoverflow
Solution 15 - Java	Maxim Z	View Answer on Stackoverflow
Solution 16 - Java	Naveen Yadav	View Answer on Stackoverflow
Solution 17 - Java	取一个好的名字	View Answer on Stackoverflow

How do I check if a date is within a certain range?

Java Problem Overview

Java Solutions

Solution 1 - Java

Solution 2 - Java

tl;dr

Half-Open

java.time

`Instant`

`LocalDate`

`Interval`

About java.time

Solution 3 - Java

Solution 4 - Java

Solution 5 - Java

Solution 6 - Java

Since `Java 8`

within the range INCLUSIVE:

within the range EXCLUSIVE:

Solution 7 - Java

Solution 8 - Java

Solution 9 - Java

Solution 10 - Java

Solution 11 - Java

Solution 12 - Java

Solution 13 - Java

Solution 14 - Java

Solution 15 - Java

Solution 16 - Java

Solution 17 - Java

How do I list all loaded assemblies?

Semantic Diff Utilities

Attributions

Java Problem Overview

Java Solutions

Solution 1 - Java

Solution 2 - Java

tl;dr

Half-Open

java.time

Instant

LocalDate

Interval

About java.time

Solution 3 - Java

Solution 4 - Java

Solution 5 - Java

Solution 6 - Java

Since Java 8

within the range INCLUSIVE:

within the range EXCLUSIVE:

Solution 7 - Java

Solution 8 - Java

Solution 9 - Java

Solution 10 - Java

Solution 11 - Java

Solution 12 - Java

Solution 13 - Java

Solution 14 - Java

Solution 15 - Java

Solution 16 - Java

Solution 17 - Java

How do I list all loaded assemblies?

Semantic Diff Utilities

Attributions

`Instant`

`LocalDate`

`Interval`

Since `Java 8`