How do I add two count(*) results together on two different tables?

MysqlCountSum

Mysql Problem Overview


I have two tables: Toys and Games.

+--------------------+------------------+
| Field              | Type             |
+--------------------+------------------+
| toy_id             | int(10) unsigned |
| little_kid_id      | int(10) unsigned |
+--------------------+------------------+

+--------------------+------------------+
| Field              | Type             |
+--------------------+------------------+
| game_id            | int(10) unsigned |
| little_kid1        | int(10) unsigned |
| little_kid2        | int(10) unsigned |
| little_kid3        | int(10) unsigned |
+--------------------+------------------+

A little kid can have multiple toys. A little kid can be participating in multiple games at once.

I want a query that will give me the total number of toys + games that a little_kid is involved with.

Basically, I want the sum of these two queries:

SELECT COUNT() FROM Toys WHERE little_kid_id = 900;
SELECT COUNT() from Games WHERE little_kid1 = 900
OR little_kid2 = 900
OR little_kid3 = 900;

Is it possible to get this in a single SQL query? Obviously, I can sum them programmatically, but that's less desirable.

(I realize that the contrived example makes the schema look ineffecient. Let's assume that we can't change the schema.)

Mysql Solutions


Solution 1 - Mysql

Wrap them up and use subqueries:

SELECT
(SELECT COUNT(*) FROM Toys WHERE little_kid_id = 900)+
(SELECT COUNT(*) from Games WHERE little_kid1 = 900 
                              OR little_kid2 = 900 
                              OR little_kid3 = 900)
AS SumCount

Voila!

Solution 2 - Mysql

SELECT
((SELECT COUNT(*) FROM Toys WHERE little_kid_id = 900)+
(SELECT COUNT(*) from Games WHERE little_kid1 = 900 
                              OR little_kid2 = 900 
                              OR little_kid3 = 900))
AS Sum FROM DUAL;

Selecting from the DUAL Table

Solution 3 - Mysql

SELECT COUNT(1) FROM
(
    SELECT 1 FROM Toys WHERE little_kid_id = 900
    UNION
    SELECT 1 FROM Games WHERE little_kid1 = 900
                        OR little_kid2 = 900
                        OR little_kid3 = 900
)

Solution 4 - Mysql

Depending on how much this query is likely to be run and how often the data changes you could periodically put data into an aggregated table like this:

CREATE TABLE aggregated (
    little_kid_id INT UNSIGNED,
    games_count INT UNSIGNED,
    toys_count INT UNSIGNED,
    PRIMARY KEY (little_kid_id)
);

Performance wise that would be s**t hot fast and avoids any nasty sub-queries.

Solution 5 - Mysql

Try this one...

db: mysql

SELECT  SUM(dum.tab) AS total FROM (
SELECT COUNT(b.category_id) AS tab FROM tblcategory AS b WHERE b.category_id=1
UNION  ALL
SELECT COUNT(a.category_id) AS tab FROM tblcategory AS a WHERE a.category_id=2
) AS dum

Solution 6 - Mysql

  SELECT  M.*,M.TOYSCOUNT+M.GAMECOUNT  
FROM (
    (SELECT COUNT(*) FROM Toys WHERE little_kid_id) AS TOYSCOUNT,
    (SELECT COUNT(*) from Games WHERE little_kid1 = 900 OR little_kid2 = 900 OR little_kid3 = 900) AS GAMECOUNT
    ) M

Solution 7 - Mysql

SELECT COUNT(1) FROM
(
    (SELECT 1 FROM Toys WHERE little_kid_id = 900
    UNION
    SELECT 1 FROM Games WHERE little_kid1 = 900
                        OR little_kid2 = 900
                        OR little_kid3 = 900) as temptable
)

Solution 8 - Mysql

select t1.tx,t2.px,t3.mx,t2.px + t3.mx  
        as total from(
SELECT COUNT (DISTINCT id) as tx
FROM Customer) as t1
cross join(
select COUNT (DISTINCT name) as px
FROM details 
) as t2
cross join(
select count (distinct device_id) as mx
from detailconfig 
) as t3

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRuncibleView Question on Stackoverflow
Solution 1 - MysqlEricView Answer on Stackoverflow
Solution 2 - MysqlanishView Answer on Stackoverflow
Solution 3 - MysqlAdam RobinsonView Answer on Stackoverflow
Solution 4 - MysqlJames CView Answer on Stackoverflow
Solution 5 - MysqlScott RameyView Answer on Stackoverflow
Solution 6 - MysqlHitesh MakwanaView Answer on Stackoverflow
Solution 7 - MysqlPhantomReferenceView Answer on Stackoverflow
Solution 8 - MysqlArulView Answer on Stackoverflow