How can you use an object's property in a double-quoted string?

I have the following code:

$DatabaseSettings = @();
$NewDatabaseSetting = "" | select DatabaseName, DataFile, LogFile, LiveBackupPath;
$NewDatabaseSetting.DatabaseName = "LiveEmployees_PD";
$NewDatabaseSetting.DataFile = "LiveEmployees_PD_Data";
$NewDatabaseSetting.LogFile = "LiveEmployees_PD_Log";
$NewDatabaseSetting.LiveBackupPath = '\\LiveServer\LiveEmployeesBackups';
$DatabaseSettings += $NewDatabaseSetting;

When I try to use one of the properties in a string execute command:

& "$SQlBackupExePath\SQLBackupC.exe" -I $InstanceName -SQL `
  "RESTORE DATABASE $DatabaseSettings[0].DatabaseName FROM DISK = '$tempPath\$LatestFullBackupFile' WITH NORECOVERY, REPLACE, MOVE '$DataFileName' TO '$DataFilegroupFolder\$DataFileName.mdf', MOVE '$LogFileName' TO '$LogFilegroupFolder\$LogFileName.ldf'"

It tries to just use the value of $DatabaseSettings rather than the value of $DatabaseSettings[0].DatabaseName, which is not valid.
My workaround is to have it copied into a new variable.

How can I access the object's property directly in a double-quoted string?

When you enclose a variable name in a double-quoted string it will be replaced by that variable's value:

$foo = 2
"$foo"

becomes

"2"

If you don't want that you have to use single quotes:

$foo = 2
'$foo'

However, if you want to access properties, or use indexes on variables in a double-quoted string, you have to enclose that subexpression in $():

$foo = 1,2,3
"$foo[1]"     # yields "1 2 3[1]"
"$($foo[1])"  # yields "2"

$bar = "abc"
"$bar.Length"    # yields "abc.Length"
"$($bar.Length)" # yields "3"

PowerShell only expands variables in those cases, nothing more. To force evaluation of more complex expressions, including indexes, properties or even complete calculations, you have to enclose those in the subexpression operator $( ) which causes the expression inside to be evaluated and embedded in the string.

@Joey has the correct answer, but just to add a bit more as to why you need to force the evaluation with $():

Your example code contains an ambiguity that points to why the makers of PowerShell may have chosen to limit expansion to mere variable references and not support access to properties as well (as an aside: string expansion is done by calling the ToString() method on the object, which can explain some "odd" results).

Your example contained at the very end of the command line:

...\$LogFileName.ldf

If properties of objects were expanded by default, the above would resolve to

...\

since the object referenced by $LogFileName would not have a property called ldf, $null (or an empty string) would be substituted for the variable.

^{Documentation note: Get-Help about_Quoting_Rules covers string interpolation, but, as of PSv5, not in-depth.}

To complement Joey's helpful answer with a pragmatic summary of PowerShell's string expansion (string interpolation in double-quoted strings ("...", a.k.a. expandable strings), including in double-quoted here-strings):

• Only references such as $foo, $global:foo (or $script:foo, ...) and $env:PATH (environment variables) can directly be embedded in a "..." string - that is, only the variable reference itself, as a whole is expanded, irrespective of what follows.

  • E.g., "$HOME.foo" expands to something like C:\Users\jdoe.foo, because the .foo part was interpreted literally - not as a property access.

  • To disambiguate a variable name from subsequent characters in the string, enclose it in { and }; e.g., ${foo}.
    This is especially important if the variable name is followed by a :, as PowerShell would otherwise consider everything between the $ and the : a scope specifier, typically causing the interpolation to fail; e.g., "$HOME: where the heart is." breaks, but "${HOME}: where the heart is." works as intended.
    (Alternatively, `-escape the :: "$HOME`: where the heart is.", but that only works if the character following the variable name wouldn't then accidentally form an escape sequence with a preceding `, such as `b - see the conceptual about_Special_Characters help topic).

  • To treat a $ or a " as a literal, prefix it with escape char. ` (a backtick); e.g.:
    "`$HOME's value: $HOME"

• For anything else, including using array subscripts and accessing an object variable's properties, you must enclose the expression in $(...), the subexpression operator (e.g., "PS version: $($PSVersionTable.PSVersion)" or "1st el.: $($someArray[0])")

  • Using $(...) even allows you to embed the output from entire commands in double-quoted strings (e.g., "Today is $((Get-Date).ToString('d')).").

• Interpolation results don't necessarily look the same as the default output format (what you'd see if you printed the variable / subexpression directly to the console, for instance, which involves the default formatter; see Get-Help about_format.ps1xml):

  • Collections, including arrays, are converted to strings by placing a single space between the string representations of the elements (by default; a different separator can be specified by setting preference variable $OFS, though that is rarely seen in practice) E.g., "array: $(@(1, 2, 3))" yields array: 1 2 3

  • Instances of any other type (including elements of collections that aren't themselves collections) are stringified by either calling the IFormattable.ToString() method with the invariant culture, if the instance's type supports the IFormattable interface^[1], or by calling .psobject.ToString(), which in most cases simply invokes the underlying .NET type's .ToString() method^[2], which may or may not give a meaningful representation: unless a (non-primitive) type has specifically overridden the .ToString() method, all you'll get is the full type name (e.g., "hashtable: $(@{ key = 'value' })" yields hashtable: System.Collections.Hashtable).

  • To get the same output as in the console, use a subexpression in which you pipe to Out-String and apply .Trim() to remove any leading and trailing empty lines, if desired; e.g.,
    "hashtable:`n$((@{ key = 'value' } | Out-String).Trim())" yields:

       hashtable:                                                                                                                                                                          
       Name                           Value                                                                                                                                               
       ----                           -----                                                                                                                                               
       key                            value      
    

---

^{[1] This perhaps surprising behavior means that, for types that support culture-sensitive representations, $obj.ToString() yields a current-culture-appropriate representation, whereas "$obj" (string interpolation) always results in a culture-invariant representation - see this answer.}

^{[2] Notable overrides:
• The previously discussed stringification of collections (space-separated list of elements rather than something like System.Object[]).
• The hashtable-like representation of [pscustomobject] instances (explained here) rather than the empty string.}

@Joey has a good answer. There is another way with a more .NET look with a String.Format equivalent, I prefer it when accessing properties on objects:

Things about a car:

$properties = @{ 'color'='red'; 'type'='sedan'; 'package'='fully loaded'; }

Create an object:

$car = New-Object -typename psobject -Property $properties

Interpolate a string:

"The {0} car is a nice {1} that is {2}" -f $car.color, $car.type, $car.package

Outputs:

# The red car is a nice sedan that is fully loaded

If you want to use properties within quotes follow as below. You have to use $ outside of the bracket to print property.

$($variable.property)

Example:

$uninstall= Get-WmiObject -ClassName Win32_Product |
    Where-Object {$_.Name -like "Google Chrome"

Output:

IdentifyingNumber : {57CF5E58-9311-303D-9241-8CB73E340963}
Name              : Google Chrome
Vendor            : Google LLC
Version           : 95.0.4638.54
Caption           : Google Chrome

If you want only name property then do as below:

"$($uninstall.name) Found and triggered uninstall"

Output:

Google Chrome Found and triggered uninstall