How can I set the current working directory to the directory of the script in Bash?
BashPathScriptingBash Problem Overview
I'm writing a Bash script. I need the current working directory to always be the directory that the script is located in.
The default behavior is that the current working directory in the script is that of the shell from which I run it, but I do not want this behavior.
Bash Solutions
Solution 1 - Bash
#!/bin/bash
cd "$(dirname "$0")"
Solution 2 - Bash
The following also works:
cd "${0%/*}"
The syntax is thoroughly described in this StackOverflow answer.
Solution 3 - Bash
Try the following simple one-liners:
For all UNIX/OSX/Linux
dir=$(cd -P -- "$(dirname -- "$0")" && pwd -P)
Bash
dir=$(cd -P -- "$(dirname -- "${BASH_SOURCE[0]}")" && pwd -P)
Note: A double dash (--) is used in commands to signify the end of command options, so files containing dashes or other special characters won't break the command.
Note: In Bash, use ${BASH_SOURCE[0]}
in favor of $0
, otherwise the path can break when sourcing it (source
/.
).
*For Linux, Mac and other BSD:
cd "$(dirname "$(realpath "$0")")";
Note: realpath
should be installed in the most popular Linux distribution by default (like Ubuntu), but in some it can be missing, so you have to install it.
Note: If you're using Bash, use ${BASH_SOURCE[0]}
in favor of $0
, otherwise the path can break when sourcing it (source
/.
).
Otherwise you could try something like that (it will use the first existing tool):
cd "$(dirname "$(readlink -f "$0" || realpath "$0")")"
For Linux specific:
cd "$(dirname "$(readlink -f "$0")")"
*Using GNU readlink on BSD/Mac:
cd "$(dirname "$(greadlink -f "$0")")"
Note: You need to have coreutils
installed
(e.g. 1. Install Homebrew, 2. brew install coreutils
).
In bash
In bash you can use Parameter Expansions to achieve that, like:
cd "${0%/*}"
but it doesn't work if the script is run from the same directory.
Alternatively you can define the following function in bash:
realpath () {
[[ $1 = /* ]] && echo "$1" || echo "$PWD/${1#./}"
}
This function takes 1 argument. If argument has already absolute path, print it as it is, otherwise print $PWD
variable + filename argument (without ./
prefix).
or here is the version taken from Debian .bashrc
file:
function realpath()
{
f=$@
if [ -d "$f" ]; then
base=""
dir="$f"
else
base="/$(basename "$f")"
dir=$(dirname "$f")
fi
dir=$(cd "$dir" && /bin/pwd)
echo "$dir$base"
}
Related:
-
https://stackoverflow.com/questions/59895/can-a-bash-script-tell-what-directory-its-stored-in
-
https://stackoverflow.com/questions/3572030/bash-script-absolute-path-with-osx
See also:
https://stackoverflow.com/questions/1055671/how-can-i-get-the-behavior-of-gnus-readlink-f-on-a-mac
Solution 4 - Bash
cd "$(dirname "${BASH_SOURCE[0]}")"
It's easy. It works.
Solution 5 - Bash
The accepted answer works well for scripts that have not been symlinked elsewhere, such as into $PATH
.
#!/bin/bash
cd "$(dirname "$0")"
However if the script is run via a symlink,
ln -sv ~/project/script.sh ~/bin/;
~/bin/script.sh
This will cd into the ~/bin/
directory and not the ~/project/
directory, which will probably break your script if the purpose of the cd
is to include dependencies relative to ~/project/
The symlink safe answer is below:
#!/bin/bash
cd "$(dirname "$(readlink -f "${BASH_SOURCE[0]}")")" # cd current directory
readlink -f
is required to resolve the absolute path of the potentially symlinked file.
The quotes are required to support filepaths that could potentially contain whitespace (bad practice, but its not safe to assume this won't be the case)
Solution 6 - Bash
This script seems to work for me:
#!/bin/bash
mypath=`realpath $0`
cd `dirname $mypath`
pwd
The pwd command line echoes the location of the script as the current working directory no matter where I run it from.
Solution 7 - Bash
I take this and it works.
#!/bin/bash
cd "$(dirname "$0")"
CUR_DIR=$(pwd)
Solution 8 - Bash
Get the real path to your script
if [ -L $0 ] ; then
ME=$(readlink $0)
else
ME=$0
fi
DIR=$(dirname $ME)
(This is answer to the same my question here: https://stackoverflow.com/questions/3373132/get-name-of-directory-wher-script-is-executed)
Solution 9 - Bash
There are a lot of correct answers in here, but one that tends to be more useful for me (making sure a script's relative paths remain predictable/work) is to use pushd/popd:
pushd "$(dirname ${BASH_SOURCE:0})"
trap popd EXIT
# ./xyz, etc...
This will push the source file's directory on to a navigation stack, thereby changing the working directory, but then, when the script exits (for whatever reason, including failure), the trap
will run popd
, restoring the current working directory before it was executed. If the script were to cd
and then fail, your terminal could be left in an unpredictable state after the execution ends - the trap prevents this.
Solution 10 - Bash
cd "`dirname $(readlink -f ${0})`"
Solution 11 - Bash
Most answers either don't handle files which are symlinked via a relative path, aren't one-liners or don't handle BSD (Mac). A solution which does all three is:
HERE=$(cd "$(dirname "$BASH_SOURCE")"; cd -P "$(dirname "$(readlink "$BASH_SOURCE" || echo .)")"; pwd)
First, cd to bash's conception of the script's directory. Then readlink the file to see if it is a symlink (relative or otherwise), and if so, cd to that directory. If not, cd to the current directory (necessary to keep things a one-liner). Then echo the current directory via pwd
.
You could add --
to the arguments of cd and readlink to avoid issues of directories named like options, but I don't bother for most purposes.
You can see the full explanation with illustrations here:
https://www.binaryphile.com/bash/2020/01/12/determining-the-location-of-your-script-in-bash.html
Solution 12 - Bash
echo $PWD
PWD is an environment variable.
Solution 13 - Bash
If you just need to print present working directory then you can follow this.
$ vim test
#!/bin/bash
pwd
:wq to save the test file.
Give execute permission:
chmod u+x test
Then execute the script by ./test
then you can see the present working directory.