How can I scroll a web page using selenium webdriver in python?

Python Selenium Selenium Webdriver Automated Tests

Python Problem Overview

I am currently using selenium webdriver to parse through facebook user friends page and extract all ids from the AJAX script. But I need to scroll down to get all the friends. How can I scroll down in Selenium. I am using python.

Python Solutions

Solution 1 - Python

You can use

driver.execute_script("window.scrollTo(0, Y)")

where Y is the height (on a fullhd monitor it's 1080). (Thanks to @lukeis)

You can also use

driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")

to scroll to the bottom of the page.

If you want to scroll to a page with infinite loading, like social network ones, facebook etc. (thanks to @Cuong Tran)

SCROLL_PAUSE_TIME = 0.5

# Get scroll height
last_height = driver.execute_script("return document.body.scrollHeight")

while True:
    # Scroll down to bottom
    driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")

    # Wait to load page
    time.sleep(SCROLL_PAUSE_TIME)

    # Calculate new scroll height and compare with last scroll height
    new_height = driver.execute_script("return document.body.scrollHeight")
    if new_height == last_height:
        break
    last_height = new_height

another method (thanks to Juanse) is, select an object and

label.sendKeys(Keys.PAGE_DOWN);

Solution 2 - Python

If you want to scroll down to bottom of infinite page (like linkedin.com), you can use this code:

SCROLL_PAUSE_TIME = 0.5

# Get scroll height
last_height = driver.execute_script("return document.body.scrollHeight")

while True:
    # Scroll down to bottom
    driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")

    # Wait to load page
    time.sleep(SCROLL_PAUSE_TIME)

    # Calculate new scroll height and compare with last scroll height
    new_height = driver.execute_script("return document.body.scrollHeight")
    if new_height == last_height:
        break
    last_height = new_height

Reference: https://stackoverflow.com/a/28928684/1316860

Solution 3 - Python

You can use send_keys to simulate an END (or PAGE_DOWN) key press (which normally scroll the page):

from selenium.webdriver.common.keys import Keys
html = driver.find_element_by_tag_name('html')
html.send_keys(Keys.END)

Solution 4 - Python

same method as shown here:

in python you can just use

driver.execute_script("window.scrollTo(0, Y)")

(Y is the vertical position you want to scroll to)

Solution 5 - Python

element=find_element_by_xpath("xpath of the li you are trying to access")

element.location_once_scrolled_into_view

this helped when I was trying to access a 'li' that was not visible.

Solution 6 - Python

For my purpose, I wanted to scroll down more, keeping the windows position in mind. My solution was similar and used window.scrollY

driver.execute_script("window.scrollTo(0, window.scrollY + 200)")

which will go to the current y scroll position + 200

Solution 7 - Python

This is how you scroll down the webpage:

driver.execute_script("window.scrollTo(0, 1000);")

Solution 8 - Python

None of these answers worked for me, at least not for scrolling down a facebook search result page, but I found after a lot of testing this solution:

while driver.find_element_by_tag_name('div'):
    driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
    Divs=driver.find_element_by_tag_name('div').text
    if 'End of Results' in Divs:
        print 'end'
        break
    else:
        continue

Solution 9 - Python

The easiest way i found to solve that problem was to select a label and then send:

label.sendKeys(Keys.PAGE_DOWN);

Hope it works!

Solution 10 - Python

scroll loading pages. Example: medium, quora,etc

last_height = driver.execute_script("return document.body.scrollHeight")
    while True:
        driver.execute_script("window.scrollTo(0, document.body.scrollHeight-1000);")
        # Wait to load the page.
        driver.implicitly_wait(30) # seconds
        new_height = driver.execute_script("return document.body.scrollHeight")
    
        if new_height == last_height:
            break
        last_height = new_height
        # sleep for 30s
        driver.implicitly_wait(30) # seconds
    driver.quit()

Solution 11 - Python

When working with youtube the floating elements give the value "0" as the scroll height so rather than using "return document.body.scrollHeight" try using this one "return document.documentElement.scrollHeight" adjust the scroll pause time as per your internet speed else it will run for only one time and then breaks after that.

SCROLL_PAUSE_TIME = 1

# Get scroll height
"""last_height = driver.execute_script("return document.body.scrollHeight")

this dowsnt work due to floating web elements on youtube
"""

last_height = driver.execute_script("return document.documentElement.scrollHeight")
while True:
    # Scroll down to bottom
    driver.execute_script("window.scrollTo(0,document.documentElement.scrollHeight);")

    # Wait to load page
    time.sleep(SCROLL_PAUSE_TIME)

    # Calculate new scroll height and compare with last scroll height
    new_height = driver.execute_script("return document.documentElement.scrollHeight")
    if new_height == last_height:
       print("break")
       break
    last_height = new_height

Solution 12 - Python

This code scrolls to the bottom but doesn't require that you wait each time. It'll continually scroll, and then stop at the bottom (or timeout)

from selenium import webdriver
import time

driver = webdriver.Chrome(executable_path='chromedriver.exe')
driver.get('https://example.com')

pre_scroll_height = driver.execute_script('return document.body.scrollHeight;')
run_time, max_run_time = 0, 1
while True:
    iteration_start = time.time()
    # Scroll webpage, the 100 allows for a more 'aggressive' scroll
    driver.execute_script('window.scrollTo(0, 100*document.body.scrollHeight);')

    post_scroll_height = driver.execute_script('return document.body.scrollHeight;')

    scrolled = post_scroll_height != pre_scroll_height
    timed_out = run_time >= max_run_time

    if scrolled:
        run_time = 0
        pre_scroll_height = post_scroll_height
    elif not scrolled and not timed_out:
        run_time += time.time() - iteration_start
    elif not scrolled and timed_out:
        break

# closing the driver is optional 
driver.close()

This is much faster than waiting 0.5-3 seconds each time for a response, when that response could take 0.1 seconds

Solution 13 - Python

You can use send_keys to simulate a PAGE_DOWN key press (which normally scroll the page):

from selenium.webdriver.common.keys import Keys
html = driver.find_element_by_tag_name('html')
html.send_keys(Keys.PAGE_DOWN)

Solution 14 - Python

I was looking for a way of scrolling through a dynamic webpage, and automatically stopping once the end of the page is reached, and found this thread.

The post by @Cuong Tran, with one main modification, was the answer that I was looking for. I thought that others might find the modification helpful (it has a pronounced effect on how the code works), hence this post.

The modification is to move the statement that captures the last page height inside the loop (so that each check is comparing to the previous page height).

So, the code below: > Continuously scrolls down a dynamic webpage (.scrollTo()), only stopping when, for one iteration, the page height stays the same.

(There is another modification, where the break statement is inside another condition (in case the page 'sticks') which can be removed).

    SCROLL_PAUSE_TIME = 0.5


    while True:

        # Get scroll height
        ### This is the difference. Moving this *inside* the loop
        ### means that it checks if scrollTo is still scrolling 
        last_height = driver.execute_script("return document.body.scrollHeight")

        # Scroll down to bottom
        driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")

        # Wait to load page
        time.sleep(SCROLL_PAUSE_TIME)

        # Calculate new scroll height and compare with last scroll height
        new_height = driver.execute_script("return document.body.scrollHeight")
        if new_height == last_height:

            # try again (can be removed)
            driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")

            # Wait to load page
            time.sleep(SCROLL_PAUSE_TIME)

            # Calculate new scroll height and compare with last scroll height
            new_height = driver.execute_script("return document.body.scrollHeight")

            # check if the page height has remained the same
            if new_height == last_height:
                # if so, you are done
                break
            # if not, move on to the next loop
            else:
                last_height = new_height
                continue

Solution 15 - Python

Here's an example selenium code snippet that you could use for this type of purpose. It goes to the url for youtube search results on 'Enumerate python tutorial' and scrolls down until it finds the video with the title: 'Enumerate python tutorial(2020).'

driver.get('https://www.youtube.com/results?search_query=enumerate+python')
target = driver.find_element_by_link_text('Enumerate python tutorial(2020).')
target.location_once_scrolled_into_view

Solution 16 - Python

The ScrollTo() function doesn't work anymore. This is what I used and it worked fine.

driver.execute_script("document.getElementById('mydiv').scrollIntoView();")

Solution 17 - Python

if you want to scroll within a particular view/frame (WebElement), what you only need to do is to replace "body" with a particular element that you intend to scroll within. i get that element via "getElementById" in the example below:

self.driver.execute_script('window.scrollTo(0, document.getElementById("page-manager").scrollHeight);')

this is the case on YouTube, for example...

Solution 18 - Python

insert this line driver.execute_script("window.scrollBy(0,925)", "")

Solution 19 - Python

driver.execute_script("document.getElementById('your ID Element').scrollIntoView();")

it's working for my case.

Solution 20 - Python

The loop using the "send keys" method of scrolling the page:

pre_scroll_height = driver.execute_script('return document.body.scrollHeight;')
while True:
    driver.find_element_by_tag_name('body').send_keys(Keys.END)
    time.sleep(5)
    post_scroll_height = driver.execute_script('return document.body.scrollHeight;')

    print(pre_scroll_height, post_scroll_height)
    if pre_scroll_height == post_scroll_height:
        break
    pre_scroll_height=post_scroll_height

Solution 21 - Python

According to the docs, the class ActionChains does the job:

from selenium import webdriver
from selenium.webdriver import ActionChains

driver = webdriver.Firefox()
action_chains = ActionChains(driver)
action_chains.scroll(x: int, y: int, delta_x: int, delta_y: int, duration: int = 0, origin: str = 'viewport')

Content Type	Original Author	Original Content on Stackoverflow
Question	user2523364	View Question on Stackoverflow
Solution 1 - Python	OWADVL	View Answer on Stackoverflow
Solution 2 - Python	Cuong Tran	View Answer on Stackoverflow
Solution 3 - Python	LIU YUE	View Answer on Stackoverflow
Solution 4 - Python	lukeis	View Answer on Stackoverflow
Solution 5 - Python	premonition	View Answer on Stackoverflow
Solution 6 - Python	Nick Brady	View Answer on Stackoverflow
Solution 7 - Python	sahaja nadendla	View Answer on Stackoverflow
Solution 8 - Python	Bass Dee	View Answer on Stackoverflow
Solution 9 - Python	Juanse	View Answer on Stackoverflow
Solution 10 - Python	ashishmishra	View Answer on Stackoverflow
Solution 11 - Python	Vinay Verma	View Answer on Stackoverflow
Solution 12 - Python	Osuynonma	View Answer on Stackoverflow
Solution 13 - Python	NourEldin Osama	View Answer on Stackoverflow
Solution 14 - Python	myles	View Answer on Stackoverflow
Solution 15 - Python	coder420	View Answer on Stackoverflow
Solution 16 - Python	MoKG	View Answer on Stackoverflow
Solution 17 - Python	user9597905	View Answer on Stackoverflow
Solution 18 - Python	bonifacio_kid	View Answer on Stackoverflow
Solution 19 - Python	Long Lê Hoàng	View Answer on Stackoverflow
Solution 20 - Python	grantr	View Answer on Stackoverflow
Solution 21 - Python	S.Khajeh	View Answer on Stackoverflow