How can I process each letter of text using Javascript?

I would like to alert each letter of a string, but I am unsure how to do this.

So, if I have:

var str = 'This is my string';

I would like to be able to separately alert T, h, i, s, etc. This is just the beginning of an idea that I am working on, but I need to know how to process each letter separately.

I was thinking I might need to use the split function after testing what the length of the string is.

How can I do this?

If the order of alerts matters, use this:

for (var i = 0; i < str.length; i++) {
  alert(str.charAt(i));
}

Or this: (see also this answer)

 for (var i = 0; i < str.length; i++) {
   alert(str[i]);
 }

If the order of alerts doesn't matter, use this:

var i = str.length;
while (i--) {
  alert(str.charAt(i));
}

Or this: (see also this answer)

 var i = str.length;
while (i--) {
  alert(str[i]);
}

var str = 'This is my string';

function matters() {
  for (var i = 0; i < str.length; i++) {
    alert(str.charAt(i));
  }
}

function dontmatter() {
  var i = str.length;
  while (i--) {
    alert(str.charAt(i));
  }
}

<p>If the order of alerts matters, use <a href="#" onclick="matters()">this</a>.</p>

<p>If the order of alerts doesn't matter, use <a href="#" onclick="dontmatter()">this</a>.</p>

It's probably more than solved. Just want to contribute with another simple solution:

var text = 'uololooo';

// With ES6
[...text].forEach(c => console.log(c))

// With the `of` operator
for (const c of text) {
    console.log(c)
}

// With ES5
for (var x = 0, c=''; c = text.charAt(x); x++) { 
    console.log(c); 
}

// ES5 without the for loop:
text.split('').forEach(function(c) {
    console.log(c);
});

How to process each letter of text (with benchmarks)

https://jsperf.com/str-for-in-of-foreach-map-2</s>

for (var i = 0; i < str.length; i++) {
  console.info(str[i]);
}

let result = '';
for (let letter of str) {
  result += letter;
}

// ES6 version.
let result = '';
str.split('').forEach(letter => {
  result += letter;
});

var result = '';
str.split('').forEach(function(letter) {
  result += letter;
});

var result = '';
for (var letterIndex in str) {
  result += str[letterIndex];
}

// ES6 version.
var result = '';
str.split('').map(letter => {
  result += letter;
});

let result = '';
str.split('').map(function(letter) {
  result += letter;
});

One possible solution in pure javascript:

for (var x = 0; x < str.length; x++)
{
    var c = str.charAt(x);
    alert(c);
}

Most if not all of the answers here are wrong because they will break whenever there is a character in the string outside the Unicode BMP (Basic Multilingual Plane). That means all Emoji will be broken.

JavaScript uses UTF-16 Unicode for all strings. In UTF-16, characters beyond the BMP are made out of two parts, called a "Surrogate Pair" and most of the answers here will process each part of such pairs individually instead of as a single character.

One way in modern JavaScript since at least 2016 is to use the new String iterator. Here's the example (almost) straight out of MDN:

var string = 'A\uD835\uDC68B\uD835\uDC69C\uD835\uDC6A';

for (var v of string) {
  alert(v);
}
// "A"
// "\uD835\uDC68"
// "B"
// "\uD835\uDC69"
// "C"
// "\uD835\uDC6A"

You can try this

var arrValues = 'This is my string'.split('');
// Loop over each value in the array.
$.each(arrValues, function (intIndex, objValue) {
    alert(objValue);
})

New JS allows this:

const str = 'This is my string';
Array.from(str).forEach(alert);

One more solution...

var strg= 'This is my string';
for(indx in strg){
  alert(strg[indx]);
}

It is better to use the for...of statement, if the string contains unicode characters, because of the different byte size.

for(var c of "tree 木") { console.log(c); }
//"𝐀A".length === 3

If you want to do a transformation on the text on a character level, and get the transformed text back at the end, you would do something like this:

var value = "alma";
var new_value = [...value].map((x) => x+"E").join("")

So the steps:

• Split the string into an array (list) of characters
• Map each character via a functor
• Join the resulting array of chars together into the resulting string

NOTE: If you need performance, there are probably better, more optimized solutions for this. I posted this one as a clean codestyle approach.

short answer: Array.from(string) will give you what you probably want and then you can iterate on it or whatever since it's just an array.

ok let's try it with this string: abc|⚫️\n⚪️|👨‍👩‍👧‍👧.

codepoints are:

97
98
99
124
9899, 65039
10
9898, 65039
124
128104, 8205, 128105, 8205, 128103, 8205, 128103

so some characters have one codepoint (byte) and some have two or more, and a newline added for extra testing.

so after testing there are two ways:

• byte per byte (codepoint per codepoint)
• character groups (but not the whole family emoji)

string = "abc|⚫️\n⚪️|👨‍👩‍👧‍👧"

console.log({ 'string': string }) // abc|⚫️\n⚪️|👨‍👩‍👧‍👧
console.log({ 'string.length': string.length }) // 21

for (let i = 0; i < string.length; i += 1) {
  console.log({ 'string[i]': string[i] }) // byte per byte
  console.log({ 'string.charAt(i)': string.charAt(i) }) // byte per byte
}

for (let char of string) {
  console.log({ 'for char of string': char }) // character groups
}

for (let char in string) {
  console.log({ 'for char in string': char }) // index of byte per byte
}

string.replace(/./g, (char) => {
  console.log({ 'string.replace(/./g, ...)': char }) // byte per byte
});

string.replace(/[\S\s]/g, (char) => {
  console.log({ 'string.replace(/[\S\s]/g, ...)': char }) // byte per byte
});

[...string].forEach((char) => {
  console.log({ "[...string].forEach": char }) // character groups
})

string.split('').forEach((char) => {
  console.log({ "string.split('').forEach": char }) // byte per byte
})

Array.from(string).forEach((char) => {
  console.log({ "Array.from(string).forEach": char }) // character groups
})

Array.prototype.map.call(string, (char) => {
  console.log({ "Array.prototype.map.call(string, ...)": char }) // byte per byte
})

var regexp = /(?:[\0-\uD7FF\uE000-\uFFFF]|[\uD800-\uDBFF][\uDC00-\uDFFF]|[\uD800-\uDBFF](?![\uDC00-\uDFFF])|(?:[^\uD800-\uDBFF]|^)[\uDC00-\uDFFF])/g

string.replace(regexp, (char) => {
  console.log({ 'str.replace(regexp, ...)': char }) // character groups
});

When I need to write short code or a one-liner, I use this "hack":

'Hello World'.replace(/./g, function (char) {
    alert(char);
    return char; // this is optional 
});

This won't count newlines so that can be a good thing or a bad thing. If you which to include newlines, replace: /./ with /[\S\s]/. The other one-liners you may see probably use .split() which has many problems

You can now use in keyword.

    var s = 'Alien';
    for (var c in s) alert(s[c]);

You can now iterate over individual Unicode code points contained in a String by using String.prototype[@@iterator], which returns a value of well known Symbol type Symbol.iterator - the default iterator for array-like Objects (String in this case).

Example code:

const str = 'The quick red 🦊 jumped over the lazy 🐶! 太棒了！';

let iterator = str[Symbol.iterator]();
let theChar = iterator.next();

while(!theChar.done) {
  console.log(theChar.value);
  theChar = iterator.next();
}

// logs every unicode character as expected into the console.

This works with Unicode characters such as emoji or non-roman characters that would trip up legacy constructs.

Reference: [MDN Link to String.prototype@@iterator]1.

You can simply iterate it as in an array:

for(var i in txt){
    console.log(txt[i]);
}

In ES6 / ES2015, you can iterate over an string with iterators,as you can see in

Symbol.iterator MDN

var str = 'Hello';
var it = str[Symbol.iterator]();

for (let v of it) {
  console.log(v)
 }
 
//  "H"
//  "e"
//  "l"
//  "l"
//  "o"

It is a declarative style. What is the advantage? You do not have to concern about how to access each element of the string.

You can get an array of the individual characters like so

var test = "test string",
    characters = test.split('');

and then loop using regular Javascript, or else you can iterate over the string's characters using jQuery by

var test = "test string";

$(test.split('')).each(function (index,character) {
    alert(character);
});

you can convert this string into an array of chars using split(), then iterate through it.

const str = "javascript";
const strArray = str.split('');

strArray.map(s => console.log(s));

// There are multiple ways but I find this easiest.

let str = 'This is my string';
for(let character of str) 
  console.log(character)

In today's JavaScript you can

Obviously, c+c represents whatever you want to do with c.

This returns

  "mm", "yy", "  ", "ss", "tt", "rr", "ii", "nn", "gg"]```

This should work in older browsers and with UTF-16 characters like .

This should be the most compatible solution. However, it is less performant than a for loop would be.

I generated the regular expression using regexpu

var str = 'My String 💩 ';
var regEx = /(?:[\0-\uD7FF\uE000-\uFFFF]|[\uD800-\uDBFF][\uDC00-\uDFFF]|[\uD800-\uDBFF](?![\uDC00-\uDFFF])|(?:[^\uD800-\uDBFF]|^)[\uDC00-\uDFFF])/g


str.replace(regEx, function (char) {
    console.log(char)
});

Hope this helps!

You can access single characters with str.charAt(index) or str[index]. But the latter way is not part of ECMAScript so you better go with the former one.

If you want to animate each character you might need to wrap it in span element;

var $demoText = $("#demo-text");
$demoText.html( $demoText.html().replace(/./g, "<span>$&amp;</span>").replace(/\s/g, " "));

I think this is the best way to do it, then process the spans. ( for example with TweenMax)

TweenMax.staggerFromTo( $demoText.find("span"), 0.2, {autoAlpha:0}, {autoAlpha:1}, 0.1 );

Try this code

    function myFunction() {
    var text =(document.getElementById("htext").value); 
	var meow = " <p> <,> </p>";
    var i;
	
	
    for (i = 0; i < 9000; i++) {
        
		text+=text[i] ;
		
		
	 	
    }
	
    document.getElementById("demo2").innerHTML = text;
	
}
</script>
<p>Enter your text: <input type="text" id="htext"/>

    <button onclick="myFunction();">click on me</button>
</p>