How can I obtain pattern string from compiled regexp pattern in python?
PythonRegexPython Problem Overview
I have some code like this one:
>>> import re
>>> p = re.compile('my pattern')
>>> print p
_sre.SRE_Pattern object at 0x02274380
Is it possible to get string "my pattern" from p variable?
Python Solutions
Solution 1 - Python
p.pattern
Read more about re module here: http://docs.python.org/library/re.html
Solution 2 - Python
From the "Regular Expression Objects" section of the re module documentation:
> RegexObject.pattern
>
> The pattern string from which the RE object was compiled.
For example:
>>> import re
>>> p = re.compile('my pattern')
>>> p
<_sre.SRE_Pattern object at 0x1001ba818>
>>> p.pattern
'my pattern'
With the re module in Python 3.0 and above, you can find this by doing a simple dir(p):
>>> print(dir(p))
['__class__', '__copy__', '__deepcopy__', '__delattr__', '__doc__',
'__eq__', '__format__', '__ge__', '__getattribute__', '__gt__',
'__hash__', '__init__', '__le__', '__lt__', '__ne__', '__new__',
'__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__',
'__str__', '__subclasshook__', 'findall', 'finditer', 'flags',
'groupindex', 'groups', 'match', 'pattern', 'scanner', 'search',
'split', 'sub', 'subn']
This however does not work on Python 2.6 (or 2.5) - the dir command isn't perfect, so it's always worth checking the docs!
>>> print dir(p)
['__copy__', '__deepcopy__', 'findall', 'finditer', 'match', 'scanner',
'search', 'split', 'sub', 'subn']
Solution 3 - Python
Yes:
print p.pattern
hint, use the dir function in python to obtain a list of members:
dir(p)
this lists:
['__class__', '__copy__', '__deepcopy__', '__delattr__', '__doc__', '__eq__','__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__','__le__', '__lt__', '__ne__', '__new__', '__reduce__', '__reduce_ex__','__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__','findall', 'finditer', 'flags', 'groupindex', 'groups', 'match', 'pattern','scanner', 'search', 'split', 'sub', 'subn']