grep&#39;s `-A 1` option will give you one line after; `-B 1` will give you one line before; and `-C 1` combines both to give you one line both before and after, `-1` does the same.

Use -B, -A or -C option

    grep --help
    ...
    -B, --before-context=NUM  print NUM lines of leading context
    -A, --after-context=NUM   print NUM lines of trailing context
    -C, --context=NUM         print NUM lines of output context
    -NUM                      same as --context=NUM
    ...



Use -A and -B switches (mean lines-after and lines-before):

    grep -A 1 -B 1 FAILED file.txt

How do I locate the current file in the project structure? (Similar to Visual Studio&#39;s &lt;kbd&gt;Ctrl&lt;/kbd&gt; + &lt;kbd&gt;Alt&lt;/kbd&gt; + &lt;kbd&gt;L&lt;/kbd&gt;). What is the name of the operation (so I can define it in the keymap)

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Is there a way to stop this behavior?

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I have to parse a very large file and I want to use the command grep (or any other tool).

I want to search each log line for the word `FAILED`, then print the line above and below each matching line, as well as the matching line.

For example:
---------

    id : 15
    Satus : SUCCESS
    Message : no problem

---------

    id : 15
    Satus : FAILED
    Message : connection error

---------


And I need to print:

    id : 15
    Satus : FAILED
    Message : connection error

How can I make grep print the lines below and above each matching line?

I have to parse a very large file and I want to use the command grep (or any other tool).
I want to search each log line for the word <code>FAILED</code>, then print the line above and below each matching line, as well as the matching line.
<h4 id="for-example"><a aria-hidden="true" tabindex="-1" href="#for-example"></a>For example:</h4>
<pre><code class="hljs language-yaml">id : 15
Satus : SUCCESS
Message : no problem
</code></pre>
<hr>
<pre><code class="hljs language-yaml">id : 15
Satus : FAILED
Message : connection error
</code></pre>
<hr>
And I need to print:
<pre><code class="hljs language-yaml">id : 15
Satus : FAILED
Message : connection error
</code></pre>

Is there a limit to the amount of data that can be stored in an environment variable on Linux, and if so: what is it?

For Windows, I&#39;ve found following [KB article][1] which summarizes to:
  Windows XP or later: 8191 characters
  Windows 2000/NT 4.0: 2047 characters


  [1]: http://support.microsoft.com/kb/830473


What is the maximum size of a Linux environment variable value?

I am creating a Python script within which I am executing UNIX system commands. I have a
war archive named Binaries.war which is within an ear archive named Portal.ear

The Portal ear file resides in, say /home/foo/bar/

    jar xf /home/foo/bar/Portal.ear Binaries.war

Will extract the Binaries.war file out of the /home/foo/bar/Portal.ear archive into the current directory I am running the script from.

How do you specify a target directory to be extracted to using just one command? 
I would like to do something like this to extract Binaries.war into the directory /home/foo/bar/baz 

    jar xf /home/foo/bar/Portal.ear Binaries.war [into target directory /home/foo/bar/baz]

I searched the the JAR man page for options and can&#39;t seem to find a simple way to do this. Of course I can extract the archive into my current directory and then move it using mv but I&#39;d like to do this in one shot and not shuffle directories and files around.

How do you extract a JAR in a UNIX filesystem with a single command and specify its target directory using the JAR command?

I have to variables and I want to find the value of one divided by the other. What commands should I use to do this?

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I need something simple like `date`, but in seconds since 1970 instead of the current date, hours, minutes, and seconds.

`date` doesn&#39;t seem to offer that option. Is there an easy way?

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A process is considered to have completed correctly in Linux if its exit status was 0.

I&#39;ve seen that segmentation faults often result in an exit status of 11, though I don&#39;t know if this is simply the convention where I work (the applications that failed like that have all been internal) or a standard.

Are there standard exit codes for processes in Linux?


Are there any standard exit status codes in Linux?

For instance, I have a large filesystem that is filling up faster than I expected. So I look for what&#39;s being added:

    find /rapidly_shrinking_drive/ -type f -mtime -1 -ls | less

And I find, well, lots of stuff. Thousands of files of six-seven types. I can single out a type and count them:

    find /rapidly_shrinking_drive/ -name &quot;*offender1*&quot; -mtime -1 -ls | wc -l

but what I&#39;d really like is to be able to get the total size on disk of these files:

    find /rapidly_shrinking_drive/ -name &quot;*offender1*&quot; -mtime -1 | howmuchspace

I&#39;m open to a Perl one-liner for this, if someone&#39;s got one, but I&#39;m not going to use any solution that involves a multi-line script, or File::Find.



total size of group of files selected with &#39;find&#39;

I need to use chmod to change all files recursivly to 664. I would like to skip the folders.
I was thinking of doing something like this

    ls -lR | grep ^-r | chmod 664

This doesn&#39;t work, I&#39;m assuming because I can&#39;t pipe into chmod
Anyone know of an easy way to do this?

Thanks

changing chmod for files but not directories

I am using `egrep -R` followed by a regular expression containing about 10 unions, so like:
`.jpg | .png | .gif` etc. This works well, now I would like to replace all strings found with `.bmp`

I was thinking of something like

    egrep -lR &quot;\.jpg|\.png|\.gif&quot; . | sed &quot;s/some_expression/.jpg/&quot; file_it_came_form

so the issue here is how do I do a similar union regular expression in `sed` and how do I tell it to save the changes to the file that it got the input from.


Using sed and grep/egrep to search and replace

I’m stuck in trying to grep anything just after `name=`, include only spaces and alphanumeric.

e.g.:

    name=some value here

I get

    some value here

I’m totally newb in this, the following grep match everything including the `name=`.

    grep &#39;name=.*&#39; filename

Any help is much appreciated.

How to use grep to get anything just after `name=`?

I see it is possible to view a list of properties set on every directory within an SVN repository using proplist and the -R flag (recursive) and -v flag (verbose):

    svn proplist -Rv

This shows me all properties, such as svn:mime-type or svn:executable. I&#39;m looking to filter this to just `svn:ignore` properties. I&#39;m sure there is some way to pipe the result from this command through a shell command that would only show me the lines I&#39;m interested in, but I can&#39;t figure out how to do it. As an example of the type of thing that would be most useful is some type of command like this (but this one doesn&#39;t work!).

    svn proplist -Rv | grep &quot;^  svn:ignore&quot; | awk &quot;{print \$1}&quot;

I just don&#39;t know enough about shell commands like [grep][1] and [awk][2] to make this work for me. This just shows &quot;svn:ignore&quot; over and over again, but it doesn&#39;t print out the directory path or contents of the `svn:ignore` property. Here is an example of the output from &quot;svn proplist -Rv&quot; that I&#39;d like to grab, where &#39;cache&#39; is the path and &#39;*&#39; is the value of the property.

    Properties on &#39;cache&#39;:
      svn:ignore
        *

How can the above command be made to work and/or is there a better way to view all `svn:ignore` properties in my repository?

  [1]: http://en.wikipedia.org/wiki/Grep
  [2]: http://en.wikipedia.org/wiki/AWK


Content Type	Original Author	Original Content on Stackoverflow
Question	poiuytrez	View Question on Stackoverflow
Solution 1 - Linux	pgs	View Answer on Stackoverflow
Solution 2 - Linux	tefozi	View Answer on Stackoverflow
Solution 3 - Linux	Milan Babuškov	View Answer on Stackoverflow

How can I make grep print the lines below and above each matching line?

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