How can I load an object into a variable name that I specify from an R data file?

RVariable NamesRdata

R Problem Overview


When you save a variable in an R data file using save, it is saved under whatever name it had in the session that saved it. When I later go to load it from another session, it is loaded with the same name, which the loading script cannot possibly know. This name could overwrite an existing variable of the same name in the loading session. Is there a way to safely load an object from a data file into a specified variable name without risk of clobbering existing variables?

##Example:

###Saving session:

x = 5
save(x, file="x.Rda")

###Loading session:

x = 7
load("x.Rda")
print(x) # This will print 5. Oops.

###How I want it to work:

x = 7
y = load_object_from_file("x.Rda")
print(x) # should print 7
print(y) # should print 5

R Solutions


Solution 1 - R

If you're just saving a single object, don't use an .Rdata file, use an .RDS file:

x <- 5
saveRDS(x, "x.rds")
y <- readRDS("x.rds")
all.equal(x, y)

Solution 2 - R

I use the following:

loadRData <- function(fileName){
#loads an RData file, and returns it
    load(fileName)
    get(ls()[ls() != "fileName"])
}
d <- loadRData("~/blah/ricardo.RData")

Solution 3 - R

You can create a new environment, load the .rda file into that environment, and retrieve the object from there. However, this does impose some restrictions: either you know what the original name for your object is, or there is only one object saved in the file.

This function returns an object loaded from a supplied .rda file. If there is more than one object in the file, an arbitrary one is returned.

load_obj <- function(f)
{
    env <- new.env()
    nm <- load(f, env)[1]
    env[[nm]]
}

Solution 4 - R

You could also try something like:

# Load the data, and store the name of the loaded object in x
x = load('data.Rsave')
# Get the object by its name
y = get(x)
# Remove the old object since you've stored it in y 
rm(x)

Solution 5 - R

Rdata file with one object

assign('newname', get(load('~/oldname.Rdata')))

Solution 6 - R

Similar to the other solutions above, I load variables into an environment variable. This way if I load multiple variables from the .Rda, those will not clutter my environment.

load("x.Rda", dt <- new.env())

Demo:

x <- 2
y <- 1
save(x, y, file = "mydata.Rda")
rm(x, y)

x <- 123
# Load 'x' and 'y' into a new environment called 'dt'
load("mydata.Rda", dt <- new.env())
dt$x
#> [1] 2
x
#> [1] 123

Solution 7 - R

In case anyone is looking to do this with a plain source file, rather than a saved Rdata/RDS/Rda file, the solution is very similar to the one provided by @Hong Ooi

load_obj <- function(fileName) {
  
  local_env = new.env()
  source(file = fileName, local = local_env)
  
  return(local_env[[names(local_env)[1]]])
  
}

my_loaded_obj = load_obj(fileName = "TestSourceFile.R")

my_loaded_obj(7)

Prints: > [1] "Value of arg is 7"

And in the separate source file TestSourceFile.R

myTestFunction = function(arg) {
  print(paste0("Value of arg is ", arg))
}

Again, this solution only works if there is exactly one file, if there are more, then it will just return one of them (probably the first, but that is not guaranteed).

Solution 8 - R

I'm extending the answer from @ricardo to allow selection of specific variable if the .Rdata file contains multiple variables (as my credits are low to edit an answer). It adds some lines to read user input after listing the variables contained in the .Rdata file.

loadRData <- function(fileName) {
  #loads an RData file, and returns it
  load(fileName)
  print(ls())
  n <- readline(prompt="Which variable to load? \n")
  get(ls()[as.integer(n)])
}

select_var <- loadRData('Multiple_variables.Rdata')

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRyan C. ThompsonView Question on Stackoverflow
Solution 1 - RhadleyView Answer on Stackoverflow
Solution 2 - RricardoView Answer on Stackoverflow
Solution 3 - RHong OoiView Answer on Stackoverflow
Solution 4 - ROmar WagihView Answer on Stackoverflow
Solution 5 - RJavier AcostaView Answer on Stackoverflow
Solution 6 - RHBatView Answer on Stackoverflow
Solution 7 - Ruser2711915View Answer on Stackoverflow
Solution 8 - RSeanMView Answer on Stackoverflow