How can I get the href of elements found by partial link text?
PythonSeleniumSelenium ChromedriverPython Problem Overview
Using Selenium and the Chrome Driver I do:
links = browser.find_elements_by_partial_link_text('##') matches about 160 links.
If I try,
for link in links:
print link.text
with it I get the text of all the links:
##1
##2
...
##160
The links are like this:
<a href="1.html">##1</a>
<a href="2.html">##2</a>
...
<a href="160.html">##160</a>
How can I get the href attribute of all the links found?
Python Solutions
Solution 1 - Python
Call get_attribute on each of the links you have found:
links = browser.find_elements_by_partial_link_text('##')
for link in links:
print(link.get_attribute("href"))
Solution 2 - Python
An existing answer to a similar question seems like it might apply:
Assume
>your HTML consists solely of that one tag, then this should do it:
String href = selenium.getAttribute("css=a@href");
>You use the DefaultSelenium#getAttribute() method and pass in a CSS locator, an @ symbol, and the name of the attribute you want to fetch. In this case, you select the a and get its @href.
So if the link contains "..blablabla..." text then you can find it in that way:
selenium.getAttribute("css=a:contains('..blablabla...')@href");