How can I create a Java method that accepts a variable number of arguments?

JavaFunctionMethodsOverloading

Java Problem Overview


For example, Java's own String.format() supports a variable number of arguments.

String.format("Hello %s! ABC %d!", "World", 123);
//=> Hello World! ABC 123!

How can I make my own function that accepts a variable number of arguments?


Follow-up question:

I'm really trying to make a convenience shortcut for this:

System.out.println( String.format("...", a, b, c) );

So that I can call it as something less verbose like this:

print("...", a, b, c);

How can I achieve this?

Java Solutions


Solution 1 - Java

You could write a convenience method:

public PrintStream print(String format, Object... arguments) {
    return System.out.format(format, arguments);
}

But as you can see, you've simply just renamed format (or printf).

Here's how you could use it:

private void printScores(Player... players) {
    for (int i = 0; i < players.length; ++i) {
        Player player = players[i];
        String name   = player.getName();
        int    score  = player.getScore();
        // Print name and score followed by a newline
        System.out.format("%s: %d%n", name, score);
    }
}

// Print a single player, 3 players, and all players
printScores(player1);
System.out.println();
printScores(player2, player3, player4);
System.out.println();
printScores(playersArray);

// Output
Abe: 11

Bob: 22
Cal: 33
Dan: 44

Abe: 11
Bob: 22
Cal: 33
Dan: 44

Note there's also the similar System.out.printf method that behaves the same way, but if you peek at the implementation, printf just calls format, so you might as well use format directly.

Solution 2 - Java

This is known as varargs see the link here for more details

In past java releases, a method that took an arbitrary number of values required you to create an array and put the values into the array prior to invoking the method. For example, here is how one used the MessageFormat class to format a message:

Object[] arguments = {
    new Integer(7),
    new Date(),
    "a disturbance in the Force"
};
    String result = MessageFormat.format(
        "At {1,time} on {1,date}, there was {2} on planet "
         + "{0,number,integer}.", arguments);

It is still true that multiple arguments must be passed in an array, but the varargs feature automates and hides the process. Furthermore, it is upward compatible with preexisting APIs. So, for example, the MessageFormat.format method now has this declaration:

public static String format(String pattern,
                            Object... arguments);

Solution 3 - Java

Take a look at the Java guide on varargs.

You can create a method as shown below. Simply call System.out.printf instead of System.out.println(String.format(....

public static void print(String format, Object... args) {
    System.out.printf(format, args);
}

Alternatively, you can just use a static import if you want to type as little as possible. Then you don't have to create your own method:

import static java.lang.System.out;

out.printf("Numer of apples: %d", 10);

Solution 4 - Java

This is just an extension to above provided answers.

  1. There can be only one variable argument in the method.
  2. Variable argument (varargs) must be the last argument.

Clearly explained here and rules to follow to use Variable Argument.

Solution 5 - Java

The following will create a variable length set of arguments of the type of string:

print(String arg1, String... arg2)

You can then refer to arg2 as an array of Strings. This is a new feature in Java 5.

Solution 6 - Java

The variable arguments must be the last of the parameters specified in your function declaration. If you try to specify another parameter after the variable arguments, the compiler will complain since there is no way to determine how many of the parameters actually belong to the variable argument.

void print(final String format, final String... arguments) {
    System.out.format( format, arguments );
}

Solution 7 - Java

You can pass all similar type values in the function while calling it. In the function definition put a array so that all the passed values can be collected in that array. e.g. .

static void demo (String ... stringArray) {
  your code goes here where read the array stringArray
}
 

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionmačekView Question on Stackoverflow
Solution 1 - JavaNate W.View Answer on Stackoverflow
Solution 2 - JavaPaul WhelanView Answer on Stackoverflow
Solution 3 - JavadogbaneView Answer on Stackoverflow
Solution 4 - JavaPrashanth DebbadwarView Answer on Stackoverflow
Solution 5 - JavaBradley StaceyView Answer on Stackoverflow
Solution 6 - JavaIzzaView Answer on Stackoverflow
Solution 7 - JavaSumerView Answer on Stackoverflow