How can I convert String to Int?
C#.NetStringIntType ConversionC# Problem Overview
I have a TextBoxD1.Text
and I want to convert it to an int
to store it in a database.
How can I do this?
C# Solutions
Solution 1 - C#
Try this:
int x = Int32.Parse(TextBoxD1.Text);
or better yet:
int x = 0;
Int32.TryParse(TextBoxD1.Text, out x);
Also, since Int32.TryParse
returns a bool
you can use its return value to make decisions about the results of the parsing attempt:
int x = 0;
if (Int32.TryParse(TextBoxD1.Text, out x))
{
// you know that the parsing attempt
// was successful
}
If you are curious, the difference between Parse
and TryParse
is best summed up like this:
> The TryParse method is like the Parse > method, except the TryParse method > does not throw an exception if the > conversion fails. It eliminates the > need to use exception handling to test > for a FormatException in the event > that s is invalid and cannot be > successfully parsed. - MSDN
Solution 2 - C#
Convert.ToInt32( TextBoxD1.Text );
Use this if you feel confident that the contents of the text box is a valid int
. A safer option is
int val = 0;
Int32.TryParse( TextBoxD1.Text, out val );
This will provide you with some default value you can use. Int32.TryParse
also returns a Boolean value indicating whether it was able to parse or not, so you can even use it as the condition of an if
statement.
if( Int32.TryParse( TextBoxD1.Text, out val ){
DoSomething(..);
} else {
HandleBadInput(..);
}
Solution 3 - C#
int.TryParse()
It won't throw if the text is not numeric.
Solution 4 - C#
int myInt = int.Parse(TextBoxD1.Text)
Another way would be:
bool isConvertible = false;
int myInt = 0;
isConvertible = int.TryParse(TextBoxD1.Text, out myInt);
The difference between the two is that the first one would throw an exception if the value in your textbox can't be converted, whereas the second one would just return false.
Solution 5 - C#
You need to parse the string, and you also need to ensure that it is truly in the format of an integer.
The easiest way is this:
int parsedInt = 0;
if (int.TryParse(TextBoxD1.Text, out parsedInt))
{
// Code for if the string was valid
}
else
{
// Code for if the string was invalid
}
Solution 6 - C#
Be careful when using Convert.ToInt32()
on a char!
It will return the UTF-16 code of the character!
If you access the string only in a certain position using the [i]
indexing operator, it will return a char
and not a string
!
String input = "123678";
^
|
int indexOfSeven = 4;
int x = Convert.ToInt32(input[indexOfSeven]); // Returns 55
int x = Convert.ToInt32(input[indexOfSeven].toString()); // Returns 7
Solution 7 - C#
int x = 0;
int.TryParse(TextBoxD1.Text, out x);
The TryParse statement returns a boolean representing whether the parse has succeeded or not. If it succeeded, the parsed value is stored into the second parameter.
See Int32.TryParse Method (String, Int32) for more detailed information.
Solution 8 - C#
Enjoy it...
int i = 0;
string s = "123";
i =int.Parse(s);
i = Convert.ToInt32(s);
Solution 9 - C#
While there are already many solutions here that describe int.Parse
, there's something important missing in all the answers. Typically, the string representations of numeric values differ by culture. Elements of numeric strings such as currency symbols, group (or thousands) separators, and decimal separators all vary by culture.
If you want to create a robust way to parse a string to an integer, it's therefore important to take the culture information into account. If you don't, the current culture settings will be used. That might give a user a pretty nasty surprise -- or even worse, if you're parsing file formats. If you just want English parsing, it's best to simply make it explicit, by specifying the culture settings to use:
var culture = CultureInfo.GetCulture("en-US");
int result = 0;
if (int.TryParse(myString, NumberStyles.Integer, culture, out result))
{
// use result...
}
For more information, read up on CultureInfo, specifically NumberFormatInfo on MSDN.
Solution 10 - C#
You can write your own extension method
public static class IntegerExtensions
{
public static int ParseInt(this string value, int defaultValue = 0)
{
int parsedValue;
if (int.TryParse(value, out parsedValue))
{
return parsedValue;
}
return defaultValue;
}
public static int? ParseNullableInt(this string value)
{
if (string.IsNullOrEmpty(value))
{
return null;
}
return value.ParseInt();
}
}
And wherever in code just call
int myNumber = someString.ParseInt(); // Returns value or 0
int age = someString.ParseInt(18); // With default value 18
int? userId = someString.ParseNullableInt(); // Returns value or null
In this concrete case
int yourValue = TextBoxD1.Text.ParseInt();
Solution 11 - C#
int x = Int32.TryParse(TextBoxD1.Text, out x) ? x : 0;
Solution 12 - C#
As explained in the TryParse documentation, TryParse() returns a Boolean which indicates that a valid number was found:
bool success = Int32.TryParse(TextBoxD1.Text, out val);
if (success)
{
// Put val in database
}
else
{
// Handle the case that the string doesn't contain a valid number
}
Solution 13 - C#
Conversion of string
to int
can be done for: int
, Int32
, Int64
and other data types reflecting integer data types in .NET
Below example shows this conversion:
This shows (for info) data adapter element initialized to int value. The same can be done directly like,
int xxiiqVal = Int32.Parse(strNabcd);
Ex.
string strNii = "";
UsrDataAdapter.SelectCommand.Parameters["@Nii"].Value = Int32.Parse(strNii );
Solution 14 - C#
You can use either,
int i = Convert.ToInt32(TextBoxD1.Text);
or
int i = int.Parse(TextBoxD1.Text);
Solution 15 - C#
//May be quite some time ago but I just want throw in some line for any one who may still need it
int intValue;
string strValue = "2021";
try
{
intValue = Convert.ToInt32(strValue);
}
catch
{
//Default Value if conversion fails OR return specified error
// Example
intValue = 2000;
}
Solution 16 - C#
You can convert string to int many different type methods in C#
First one is mostly use :
string test = "123";
int x = Convert.ToInt16(test);
if int value is higher you should use int32 type.
Second one:
int x = int.Parse(text);
if you want to error check, you can use TryParse method. In below I add nullable type;
int i=0;
Int32.TryParse(text, out i) ? i : (int?)null);
Enjoy your codes....
Solution 17 - C#
int i = Convert.ToInt32(TextBoxD1.Text);
Solution 18 - C#
You also may use an extension method, so it will be more readable (although everybody is already used to the regular Parse functions).
public static class StringExtensions
{
/// <summary>
/// Converts a string to int.
/// </summary>
/// <param name="value">The string to convert.</param>
/// <returns>The converted integer.</returns>
public static int ParseToInt32(this string value)
{
return int.Parse(value);
}
/// <summary>
/// Checks whether the value is integer.
/// </summary>
/// <param name="value">The string to check.</param>
/// <param name="result">The out int parameter.</param>
/// <returns>true if the value is an integer; otherwise, false.</returns>
public static bool TryParseToInt32(this string value, out int result)
{
return int.TryParse(value, out result);
}
}
And then you can call it that way:
-
If you are sure that your string is an integer, like "50".
int num = TextBoxD1.Text.ParseToInt32();
-
If you are not sure and want to prevent crashes.
int num; if (TextBoxD1.Text.TryParseToInt32(out num)) { //The parse was successful, the num has the parsed value. }
To make it more dynamic, so you can parse it also to double, float, etc., you can make a generic extension.
Solution 19 - C#
This would do
string x = TextBoxD1.Text;
int xi = Convert.ToInt32(x);
Or you can use
int xi = Int32.Parse(x);
Solution 20 - C#
You can do like below without TryParse or inbuilt functions:
static int convertToInt(string a)
{
int x = 0;
for (int i = 0; i < a.Length; i++)
{
int temp = a[i] - '0';
if (temp != 0)
{
x += temp * (int)Math.Pow(10, (a.Length - (i+1)));
}
}
return x;
}
Solution 21 - C#
You can convert a string to int in C# using:
Functions of convert class i.e. Convert.ToInt16()
, Convert.ToInt32()
, Convert.ToInt64()
or by using Parse
and TryParse
Functions. Examples are given here.
Solution 22 - C#
You can convert string to an integer value with the help of parse method.
Eg:
int val = Int32.parse(stringToBeParsed);
int x = Int32.parse(1234);
Solution 23 - C#
The way I always do this is like this:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace example_string_to_int
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
string a = textBox1.Text;
// This turns the text in text box 1 into a string
int b;
if (!int.TryParse(a, out b))
{
MessageBox.Show("This is not a number");
}
else
{
textBox2.Text = a+" is a number" ;
}
// Then this 'if' statement says if the string is not a number, display an error, else now you will have an integer.
}
}
}
This is how I would do it.
Solution 24 - C#
In C# v.7 you could use an inline out parameter, without an additional variable declaration:
int.TryParse(TextBoxD1.Text, out int x);
Solution 25 - C#
If you're looking for the long way, just create your one method:
static int convertToInt(string a)
{
int x = 0;
Char[] charArray = a.ToCharArray();
int j = charArray.Length;
for (int i = 0; i < charArray.Length; i++)
{
j--;
int s = (int)Math.Pow(10, j);
x += ((int)Char.GetNumericValue(charArray[i]) * s);
}
return x;
}
Solution 26 - C#
All the above answers are good but for information, we can use int.TryParse
which is safe to convert string to int, for example
// TryParse returns true if the conversion succeeded
// and stores the result in j.
int j;
if (Int32.TryParse("-105", out j))
Console.WriteLine(j);
else
Console.WriteLine("String could not be parsed.");
// Output: -105
TryParse never throws an exception—even on invalid input and null. It is overall preferable to int.Parse
in most program contexts.
Source: How to convert string to int in C#? (With Difference between Int.Parse and Int.TryParse)
Solution 27 - C#
In case you know the string is an integer do:
int value = int.Parse(TextBoxD1.Text);
In case you don't know the string is an integer do it safely with TryParse
.
In C# 7.0
you can use inline variable declaration.
- If parse successes - value = its parsed value.
- If parse fails - value = 0.
Code:
if (int.TryParse(TextBoxD1.Text, out int value))
{
// Parse succeed
}
Drawback:
You cannot differentiate between a 0 value and a non parsed value.
Solution 28 - C#
Here is the version of doing it via an Extension Method that has an option to set the default value as well, if the converting fails. In fact, this is what I used to convert a string input to any convertible type:
using System;
using System.ComponentModel;
public static class StringExtensions
{
public static TOutput AsOrDefault<TOutput>(this string input, TOutput defaultValue = default)
where TOutput : IConvertible
{
TOutput output = defaultValue;
try
{
var converter = TypeDescriptor.GetConverter(typeof(TOutput));
if (converter != null)
{
output = (TOutput)converter.ConvertFromString(input);
}
}
catch { }
return output;
}
}
For my usage, I limited the output to be one of the convertible types: https://docs.microsoft.com/en-us/dotnet/api/system.iconvertible?view=net-5.0. I don't need crazy logics to convert a string to a class, for example.
To use it to convert a string to int:
using FluentAssertions;
using Xunit;
[Theory]
[InlineData("0", 0)]
[InlineData("1", 1)]
[InlineData("123", 123)]
[InlineData("-123", -123)]
public void ValidStringWithNoDefaultValue_ReturnsExpectedResult(string input, int expectedResult)
{
var result = input.AsOrDefault<int>();
result.Should().Be(expectedResult);
}
[Theory]
[InlineData("0", 999, 0)]
[InlineData("1", 999, 1)]
[InlineData("123", 999, 123)]
[InlineData("-123", -999, -123)]
public void ValidStringWithDefaultValue_ReturnsExpectedResult(string input, int defaultValue, int expectedResult)
{
var result = input.AsOrDefault(defaultValue);
result.Should().Be(expectedResult);
}
[Theory]
[InlineData("")]
[InlineData(" ")]
[InlineData("abc")]
public void InvalidStringWithNoDefaultValue_ReturnsIntegerDefault(string input)
{
var result = input.AsOrDefault<int>();
result.Should().Be(default(int));
}
[Theory]
[InlineData("", 0)]
[InlineData(" ", 1)]
[InlineData("abc", 234)]
public void InvalidStringWithDefaultValue_ReturnsDefaultValue(string input, int defaultValue)
{
var result = input.AsOrDefault(defaultValue);
result.Should().Be(defaultValue);
}
Solution 29 - C#
You can try the following. It will work:
int x = Convert.ToInt32(TextBoxD1.Text);
The string value in the variable TextBoxD1.Text will be converted into Int32 and will be stored in x.
Solution 30 - C#
METHOD 1
int TheAnswer1 = 0;
bool Success = Int32.TryParse("42", out TheAnswer1);
if (!Success) {
Console.WriteLine("String not Convertable to an Integer");
}
METHOD 2
int TheAnswer2 = 0;
try {
TheAnswer2 = Int32.Parse("42");
}
catch {
Console.WriteLine("String not Convertable to an Integer");
}
METHOD 3
int TheAnswer3 = 0;
try {
TheAnswer3 = Int32.Parse("42");
}
catch (FormatException) {
Console.WriteLine("String not in the correct format for an Integer");
}
catch (ArgumentNullException) {
Console.WriteLine("String is null");
}
catch (OverflowException) {
Console.WriteLine("String represents a number less than"
+ "MinValue or greater than MaxValue");
}
Solution 31 - C#
This code works for me in Visual Studio 2010:
int someValue = Convert.ToInt32(TextBoxD1.Text);
Solution 32 - C#
While I agree on using the TryParse
method, a lot of people dislike the use of out
parameter (myself included). With tuple support having been added to C#, an alternative is to create an extension method that will limit the number of times you use out
to a single instance:
public static class StringExtensions
{
public static (int result, bool canParse) TryParse(this string s)
{
int res;
var valid = int.TryParse(s, out res);
return (result: res, canParse: valid);
}
}
(Source: C# how to convert a string to int)
Solution 33 - C#
using System;
class HelloWorld {
static void Main()
{
int experience = 0;
Console.WriteLine("How many years of experience do you have?");
var years = Console.ReadLine();
Int32.TryParse(years, out experience);
if (experience == 0)
Console.WriteLine("Inexperienced");
else if (experience == 1)
Console.WriteLine("Junior");
else if (experience == 2)
Console.WriteLine("Intermediate");
else if (experience == 3)
Console.WriteLine("Advanced");
else
Console.WriteLine("Senior");
}
}
Solution 34 - C#
This may help you ;D
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
float Stukprijs;
float Aantal;
private void label2_Click(object sender, EventArgs e)
{
}
private void button2_Click(object sender, EventArgs e)
{
MessageBox.Show("In de eersre textbox staat een geldbedrag." + Environment.NewLine + "In de tweede textbox staat een aantal." + Environment.NewLine + "Bereken wat er moetworden betaald." + Environment.NewLine + "Je krijgt 15% korting over het bedrag BOVEN de 100." + Environment.NewLine + "Als de korting meer dan 10 euri is," + Environment.NewLine + "wordt de korting textbox lichtgroen");
}
private void button1_Click(object sender, EventArgs e)
{
errorProvider1.Clear();
errorProvider2.Clear();
if (float.TryParse(textBox1.Text, out Stukprijs))
{
if (float.TryParse(textBox2.Text, out Aantal))
{
float Totaal = Stukprijs * Aantal;
string Output = Totaal.ToString();
textBox3.Text = Output;
if (Totaal >= 100)
{
float korting = Totaal - 100;
float korting2 = korting / 100 * 15;
string Output2 = korting2.ToString();
textBox4.Text = Output2;
if (korting2 >= 10)
{
textBox4.BackColor = Color.LightGreen;
}
else
{
textBox4.BackColor = SystemColors.Control;
}
}
else
{
textBox4.Text = "0";
textBox4.BackColor = SystemColors.Control;
}
}
else
{
errorProvider2.SetError(textBox2, "Aantal plz!");
}
}
else
{
errorProvider1.SetError(textBox1, "Bedrag plz!");
if (float.TryParse(textBox2.Text, out Aantal))
{
}
else
{
errorProvider2.SetError(textBox2, "Aantal plz!");
}
}
}
private void BTNwissel_Click(object sender, EventArgs e)
{
//LL, LU, LR, LD.
Color c = LL.BackColor;
LL.BackColor = LU.BackColor;
LU.BackColor = LR.BackColor;
LR.BackColor = LD.BackColor;
LD.BackColor = c;
}
private void button3_Click(object sender, EventArgs e)
{
MessageBox.Show("zorg dat de kleuren linksom wisselen als je op de knop drukt.");
}
}
}